Integrand size = 19, antiderivative size = 97 \[ \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx=-\frac {e^{c+2 b^2 x^2} x}{4 b^3 \sqrt {\pi }}-\frac {e^{c+b^2 x^2} \text {erfi}(b x)}{2 b^4}+\frac {e^{c+b^2 x^2} x^2 \text {erfi}(b x)}{2 b^2}+\frac {5 e^c \text {erfi}\left (\sqrt {2} b x\right )}{8 \sqrt {2} b^4} \]
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Time = 0.09 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {6522, 6519, 2235, 2243} \[ \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx=\frac {5 e^c \text {erfi}\left (\sqrt {2} b x\right )}{8 \sqrt {2} b^4}+\frac {x^2 e^{b^2 x^2+c} \text {erfi}(b x)}{2 b^2}-\frac {e^{b^2 x^2+c} \text {erfi}(b x)}{2 b^4}-\frac {x e^{2 b^2 x^2+c}}{4 \sqrt {\pi } b^3} \]
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Rule 2235
Rule 2243
Rule 6519
Rule 6522
Rubi steps \begin{align*} \text {integral}& = \frac {e^{c+b^2 x^2} x^2 \text {erfi}(b x)}{2 b^2}-\frac {\int e^{c+b^2 x^2} x \text {erfi}(b x) \, dx}{b^2}-\frac {\int e^{c+2 b^2 x^2} x^2 \, dx}{b \sqrt {\pi }} \\ & = -\frac {e^{c+2 b^2 x^2} x}{4 b^3 \sqrt {\pi }}-\frac {e^{c+b^2 x^2} \text {erfi}(b x)}{2 b^4}+\frac {e^{c+b^2 x^2} x^2 \text {erfi}(b x)}{2 b^2}+\frac {\int e^{c+2 b^2 x^2} \, dx}{4 b^3 \sqrt {\pi }}+\frac {\int e^{c+2 b^2 x^2} \, dx}{b^3 \sqrt {\pi }} \\ & = -\frac {e^{c+2 b^2 x^2} x}{4 b^3 \sqrt {\pi }}-\frac {e^{c+b^2 x^2} \text {erfi}(b x)}{2 b^4}+\frac {e^{c+b^2 x^2} x^2 \text {erfi}(b x)}{2 b^2}+\frac {5 e^c \text {erfi}\left (\sqrt {2} b x\right )}{8 \sqrt {2} b^4} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.79 \[ \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx=\frac {e^c \left (-4 b e^{2 b^2 x^2} x+8 e^{b^2 x^2} \sqrt {\pi } \left (-1+b^2 x^2\right ) \text {erfi}(b x)+5 \sqrt {2 \pi } \text {erfi}\left (\sqrt {2} b x\right )\right )}{16 b^4 \sqrt {\pi }} \]
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\[\int {\mathrm e}^{b^{2} x^{2}+c} x^{3} \operatorname {erfi}\left (b x \right )d x\]
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none
Time = 0.25 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.89 \[ \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx=-\frac {4 \, \sqrt {\pi } b^{2} x e^{\left (2 \, b^{2} x^{2} + c\right )} + 5 \, \sqrt {2} \pi \sqrt {-b^{2}} \operatorname {erf}\left (\sqrt {2} \sqrt {-b^{2}} x\right ) e^{c} - 8 \, {\left (\pi b^{3} x^{2} - \pi b\right )} \operatorname {erfi}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )}}{16 \, \pi b^{5}} \]
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\[ \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx=e^{c} \int x^{3} e^{b^{2} x^{2}} \operatorname {erfi}{\left (b x \right )}\, dx \]
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\[ \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx=\int { x^{3} \operatorname {erfi}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )} \,d x } \]
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\[ \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx=\int { x^{3} \operatorname {erfi}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )} \,d x } \]
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Time = 0.44 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.21 \[ \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx=\frac {\sqrt {2}\,{\mathrm {e}}^c\,\mathrm {erfi}\left (\sqrt {2}\,x\,\sqrt {b^2}\right )}{16\,b\,{\left (b^2\right )}^{3/2}}-\frac {x\,{\mathrm {e}}^{2\,b^2\,x^2+c}}{4\,b^3\,\sqrt {\pi }}-\mathrm {erfi}\left (b\,x\right )\,\left (\frac {{\mathrm {e}}^{b^2\,x^2+c}}{2\,b^4}-\frac {x^2\,{\mathrm {e}}^{b^2\,x^2+c}}{2\,b^2}\right )-\frac {\sqrt {2}\,\mathrm {erf}\left (\sqrt {2}\,x\,\sqrt {-b^2}\right )\,{\mathrm {e}}^c}{4\,b\,{\left (-b^2\right )}^{3/2}} \]
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