Integrand size = 16, antiderivative size = 219 \[ \int x^2 \cosh (a+b x) \text {Shi}(a+b x) \, dx=-\frac {a x}{2 b^2}+\frac {x^2}{4 b}+\frac {\cosh (2 a+2 b x)}{2 b^3}-\frac {\text {Chi}(2 a+2 b x)}{b^3}-\frac {a^2 \text {Chi}(2 a+2 b x)}{2 b^3}+\frac {\log (a+b x)}{b^3}+\frac {a^2 \log (a+b x)}{2 b^3}+\frac {a \cosh (a+b x) \sinh (a+b x)}{2 b^3}-\frac {x \cosh (a+b x) \sinh (a+b x)}{2 b^2}+\frac {\sinh ^2(a+b x)}{4 b^3}-\frac {2 x \cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {2 \sinh (a+b x) \text {Shi}(a+b x)}{b^3}+\frac {x^2 \sinh (a+b x) \text {Shi}(a+b x)}{b}-\frac {a \text {Shi}(2 a+2 b x)}{b^3} \]
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Time = 0.54 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.00, number of steps used = 21, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.875, Rules used = {6683, 6874, 2715, 8, 3391, 30, 3393, 3382, 6677, 5736, 6873, 2718, 3379, 6681} \[ \int x^2 \cosh (a+b x) \text {Shi}(a+b x) \, dx=-\frac {a^2 \text {Chi}(2 a+2 b x)}{2 b^3}+\frac {a^2 \log (a+b x)}{2 b^3}-\frac {\text {Chi}(2 a+2 b x)}{b^3}-\frac {a \text {Shi}(2 a+2 b x)}{b^3}+\frac {2 \text {Shi}(a+b x) \sinh (a+b x)}{b^3}+\frac {\log (a+b x)}{b^3}+\frac {\sinh ^2(a+b x)}{4 b^3}+\frac {\cosh (2 a+2 b x)}{2 b^3}+\frac {a \sinh (a+b x) \cosh (a+b x)}{2 b^3}-\frac {2 x \text {Shi}(a+b x) \cosh (a+b x)}{b^2}-\frac {a x}{2 b^2}-\frac {x \sinh (a+b x) \cosh (a+b x)}{2 b^2}+\frac {x^2 \text {Shi}(a+b x) \sinh (a+b x)}{b}+\frac {x^2}{4 b} \]
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Rule 8
Rule 30
Rule 2715
Rule 2718
Rule 3379
Rule 3382
Rule 3391
Rule 3393
Rule 5736
Rule 6677
Rule 6681
Rule 6683
Rule 6873
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \frac {x^2 \sinh (a+b x) \text {Shi}(a+b x)}{b}-\frac {2 \int x \sinh (a+b x) \text {Shi}(a+b x) \, dx}{b}-\int \frac {x^2 \sinh ^2(a+b x)}{a+b x} \, dx \\ & = -\frac {2 x \cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {x^2 \sinh (a+b x) \text {Shi}(a+b x)}{b}+\frac {2 \int \cosh (a+b x) \text {Shi}(a+b x) \, dx}{b^2}+\frac {2 \int \frac {x \cosh (a+b x) \sinh (a+b x)}{a+b x} \, dx}{b}-\int \left (-\frac {a \sinh ^2(a+b x)}{b^2}+\frac {x \sinh ^2(a+b x)}{b}+\frac {a^2 \sinh ^2(a+b x)}{b^2 (a+b x)}\right ) \, dx \\ & = -\frac {2 x \cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {2 \sinh (a+b x) \text {Shi}(a+b x)}{b^3}+\frac {x^2 \sinh (a+b x) \text {Shi}(a+b x)}{b}-\frac {2 \int \frac {\sinh ^2(a+b x)}{a+b x} \, dx}{b^2}+\frac {a \int \sinh ^2(a+b x) \, dx}{b^2}-\frac {a^2 \int \frac {\sinh ^2(a+b x)}{a+b x} \, dx}{b^2}-\frac {\int x \sinh ^2(a+b x) \, dx}{b}+\frac {\int \frac {x \sinh (2 (a+b x))}{a+b x} \, dx}{b} \\ & = \frac {a \cosh (a+b x) \sinh (a+b x)}{2 b^3}-\frac {x \cosh (a+b x) \sinh (a+b x)}{2 b^2}+\frac {\sinh ^2(a+b x)}{4 b^3}-\frac {2 x \cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {2 \sinh (a+b x) \text {Shi}(a+b x)}{b^3}+\frac {x^2 \sinh (a+b x) \text {Shi}(a+b x)}{b}+\frac {2 \int \left (\frac {1}{2 (a+b x)}-\frac {\cosh (2 a+2 b x)}{2 (a+b x)}\right ) \, dx}{b^2}-\frac {a \int 1 \, dx}{2 b^2}+\frac {a^2 \int \left (\frac {1}{2 (a+b x)}-\frac {\cosh (2 a+2 b x)}{2 (a+b x)}\right ) \, dx}{b^2}+\frac {\int x \, dx}{2 b}+\frac {\int \frac {x \sinh (2 a+2 b x)}{a+b x} \, dx}{b} \\ & = -\frac {a x}{2 b^2}+\frac {x^2}{4 b}+\frac {\log (a+b x)}{b^3}+\frac {a^2 \log (a+b x)}{2 b^3}+\frac {a \cosh (a+b x) \sinh (a+b x)}{2 b^3}-\frac {x \cosh (a+b x) \sinh (a+b x)}{2 b^2}+\frac {\sinh ^2(a+b x)}{4 b^3}-\frac {2 x \cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {2 \sinh (a+b x) \text {Shi}(a+b x)}{b^3}+\frac {x^2 \sinh (a+b x) \text {Shi}(a+b x)}{b}-\frac {\int \frac {\cosh (2 a+2 b x)}{a+b x} \, dx}{b^2}-\frac {a^2 \int \frac {\cosh (2 a+2 b x)}{a+b x} \, dx}{2 b^2}+\frac {\int \left (\frac {\sinh (2 a+2 b x)}{b}+\frac {a \sinh (2 a+2 b x)}{b (-a-b x)}\right ) \, dx}{b} \\ & = -\frac {a x}{2 b^2}+\frac {x^2}{4 b}-\frac {\text {Chi}(2 a+2 b x)}{b^3}-\frac {a^2 \text {Chi}(2 a+2 b x)}{2 b^3}+\frac {\log (a+b x)}{b^3}+\frac {a^2 \log (a+b x)}{2 b^3}+\frac {a \cosh (a+b x) \sinh (a+b x)}{2 b^3}-\frac {x \cosh (a+b x) \sinh (a+b x)}{2 b^2}+\frac {\sinh ^2(a+b x)}{4 b^3}-\frac {2 x \cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {2 \sinh (a+b x) \text {Shi}(a+b x)}{b^3}+\frac {x^2 \sinh (a+b x) \text {Shi}(a+b x)}{b}+\frac {\int \sinh (2 a+2 b x) \, dx}{b^2}+\frac {a \int \frac {\sinh (2 a+2 b x)}{-a-b x} \, dx}{b^2} \\ & = -\frac {a x}{2 b^2}+\frac {x^2}{4 b}+\frac {\cosh (2 a+2 b x)}{2 b^3}-\frac {\text {Chi}(2 a+2 b x)}{b^3}-\frac {a^2 \text {Chi}(2 a+2 b x)}{2 b^3}+\frac {\log (a+b x)}{b^3}+\frac {a^2 \log (a+b x)}{2 b^3}+\frac {a \cosh (a+b x) \sinh (a+b x)}{2 b^3}-\frac {x \cosh (a+b x) \sinh (a+b x)}{2 b^2}+\frac {\sinh ^2(a+b x)}{4 b^3}-\frac {2 x \cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {2 \sinh (a+b x) \text {Shi}(a+b x)}{b^3}+\frac {x^2 \sinh (a+b x) \text {Shi}(a+b x)}{b}-\frac {a \text {Shi}(2 a+2 b x)}{b^3} \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 134, normalized size of antiderivative = 0.61 \[ \int x^2 \cosh (a+b x) \text {Shi}(a+b x) \, dx=\frac {-4 a b x+2 b^2 x^2+5 \cosh (2 (a+b x))-4 \left (2+a^2\right ) \text {Chi}(2 (a+b x))+8 \log (a+b x)+4 a^2 \log (a+b x)+2 a \sinh (2 (a+b x))-2 b x \sinh (2 (a+b x))+8 \left (-2 b x \cosh (a+b x)+\left (2+b^2 x^2\right ) \sinh (a+b x)\right ) \text {Shi}(a+b x)-8 a \text {Shi}(2 (a+b x))}{8 b^3} \]
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Time = 2.45 (sec) , antiderivative size = 197, normalized size of antiderivative = 0.90
method | result | size |
derivativedivides | \(\frac {\operatorname {Shi}\left (b x +a \right ) \left (a^{2} \sinh \left (b x +a \right )-2 a \left (\left (b x +a \right ) \sinh \left (b x +a \right )-\cosh \left (b x +a \right )\right )+\left (b x +a \right )^{2} \sinh \left (b x +a \right )-2 \left (b x +a \right ) \cosh \left (b x +a \right )+2 \sinh \left (b x +a \right )\right )+\frac {a^{2} \ln \left (b x +a \right )}{2}-\frac {a^{2} \operatorname {Chi}\left (2 b x +2 a \right )}{2}+\cosh \left (b x +a \right ) \sinh \left (b x +a \right ) a -\left (b x +a \right ) a -a \,\operatorname {Shi}\left (2 b x +2 a \right )-\frac {\left (b x +a \right ) \cosh \left (b x +a \right ) \sinh \left (b x +a \right )}{2}+\frac {\left (b x +a \right )^{2}}{4}+\frac {5 \cosh \left (b x +a \right )^{2}}{4}+\ln \left (b x +a \right )-\operatorname {Chi}\left (2 b x +2 a \right )}{b^{3}}\) | \(197\) |
default | \(\frac {\operatorname {Shi}\left (b x +a \right ) \left (a^{2} \sinh \left (b x +a \right )-2 a \left (\left (b x +a \right ) \sinh \left (b x +a \right )-\cosh \left (b x +a \right )\right )+\left (b x +a \right )^{2} \sinh \left (b x +a \right )-2 \left (b x +a \right ) \cosh \left (b x +a \right )+2 \sinh \left (b x +a \right )\right )+\frac {a^{2} \ln \left (b x +a \right )}{2}-\frac {a^{2} \operatorname {Chi}\left (2 b x +2 a \right )}{2}+\cosh \left (b x +a \right ) \sinh \left (b x +a \right ) a -\left (b x +a \right ) a -a \,\operatorname {Shi}\left (2 b x +2 a \right )-\frac {\left (b x +a \right ) \cosh \left (b x +a \right ) \sinh \left (b x +a \right )}{2}+\frac {\left (b x +a \right )^{2}}{4}+\frac {5 \cosh \left (b x +a \right )^{2}}{4}+\ln \left (b x +a \right )-\operatorname {Chi}\left (2 b x +2 a \right )}{b^{3}}\) | \(197\) |
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\[ \int x^2 \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int { x^{2} {\rm Shi}\left (b x + a\right ) \cosh \left (b x + a\right ) \,d x } \]
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\[ \int x^2 \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int x^{2} \cosh {\left (a + b x \right )} \operatorname {Shi}{\left (a + b x \right )}\, dx \]
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\[ \int x^2 \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int { x^{2} {\rm Shi}\left (b x + a\right ) \cosh \left (b x + a\right ) \,d x } \]
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\[ \int x^2 \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int { x^{2} {\rm Shi}\left (b x + a\right ) \cosh \left (b x + a\right ) \,d x } \]
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Timed out. \[ \int x^2 \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int x^2\,\mathrm {sinhint}\left (a+b\,x\right )\,\mathrm {cosh}\left (a+b\,x\right ) \,d x \]
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