Integrand size = 14, antiderivative size = 109 \[ \int x \cosh (a+b x) \text {Shi}(a+b x) \, dx=\frac {x}{2 b}+\frac {a \text {Chi}(2 a+2 b x)}{2 b^2}-\frac {a \log (a+b x)}{2 b^2}-\frac {\cosh (a+b x) \sinh (a+b x)}{2 b^2}-\frac {\cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {x \sinh (a+b x) \text {Shi}(a+b x)}{b}+\frac {\text {Shi}(2 a+2 b x)}{2 b^2} \]
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Time = 0.16 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.714, Rules used = {6683, 6874, 2715, 8, 3393, 3382, 6675, 5556, 12, 3379} \[ \int x \cosh (a+b x) \text {Shi}(a+b x) \, dx=\frac {a \text {Chi}(2 a+2 b x)}{2 b^2}+\frac {\text {Shi}(2 a+2 b x)}{2 b^2}-\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b^2}-\frac {a \log (a+b x)}{2 b^2}-\frac {\sinh (a+b x) \cosh (a+b x)}{2 b^2}+\frac {x \text {Shi}(a+b x) \sinh (a+b x)}{b}+\frac {x}{2 b} \]
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Rule 8
Rule 12
Rule 2715
Rule 3379
Rule 3382
Rule 3393
Rule 5556
Rule 6675
Rule 6683
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \frac {x \sinh (a+b x) \text {Shi}(a+b x)}{b}-\frac {\int \sinh (a+b x) \text {Shi}(a+b x) \, dx}{b}-\int \frac {x \sinh ^2(a+b x)}{a+b x} \, dx \\ & = -\frac {\cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {x \sinh (a+b x) \text {Shi}(a+b x)}{b}+\frac {\int \frac {\cosh (a+b x) \sinh (a+b x)}{a+b x} \, dx}{b}-\int \left (\frac {\sinh ^2(a+b x)}{b}-\frac {a \sinh ^2(a+b x)}{b (a+b x)}\right ) \, dx \\ & = -\frac {\cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {x \sinh (a+b x) \text {Shi}(a+b x)}{b}-\frac {\int \sinh ^2(a+b x) \, dx}{b}+\frac {\int \frac {\sinh (2 a+2 b x)}{2 (a+b x)} \, dx}{b}+\frac {a \int \frac {\sinh ^2(a+b x)}{a+b x} \, dx}{b} \\ & = -\frac {\cosh (a+b x) \sinh (a+b x)}{2 b^2}-\frac {\cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {x \sinh (a+b x) \text {Shi}(a+b x)}{b}+\frac {\int 1 \, dx}{2 b}+\frac {\int \frac {\sinh (2 a+2 b x)}{a+b x} \, dx}{2 b}-\frac {a \int \left (\frac {1}{2 (a+b x)}-\frac {\cosh (2 a+2 b x)}{2 (a+b x)}\right ) \, dx}{b} \\ & = \frac {x}{2 b}-\frac {a \log (a+b x)}{2 b^2}-\frac {\cosh (a+b x) \sinh (a+b x)}{2 b^2}-\frac {\cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {x \sinh (a+b x) \text {Shi}(a+b x)}{b}+\frac {\text {Shi}(2 a+2 b x)}{2 b^2}+\frac {a \int \frac {\cosh (2 a+2 b x)}{a+b x} \, dx}{2 b} \\ & = \frac {x}{2 b}+\frac {a \text {Chi}(2 a+2 b x)}{2 b^2}-\frac {a \log (a+b x)}{2 b^2}-\frac {\cosh (a+b x) \sinh (a+b x)}{2 b^2}-\frac {\cosh (a+b x) \text {Shi}(a+b x)}{b^2}+\frac {x \sinh (a+b x) \text {Shi}(a+b x)}{b}+\frac {\text {Shi}(2 a+2 b x)}{2 b^2} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.72 \[ \int x \cosh (a+b x) \text {Shi}(a+b x) \, dx=\frac {2 b x+2 a \text {Chi}(2 (a+b x))-2 a \log (a+b x)-\sinh (2 (a+b x))+4 (-\cosh (a+b x)+b x \sinh (a+b x)) \text {Shi}(a+b x)+2 \text {Shi}(2 (a+b x))}{4 b^2} \]
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Time = 1.54 (sec) , antiderivative size = 97, normalized size of antiderivative = 0.89
method | result | size |
derivativedivides | \(\frac {\operatorname {Shi}\left (b x +a \right ) \left (-a \sinh \left (b x +a \right )+\left (b x +a \right ) \sinh \left (b x +a \right )-\cosh \left (b x +a \right )\right )+a \left (-\frac {\ln \left (b x +a \right )}{2}+\frac {\operatorname {Chi}\left (2 b x +2 a \right )}{2}\right )-\frac {\cosh \left (b x +a \right ) \sinh \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}+\frac {\operatorname {Shi}\left (2 b x +2 a \right )}{2}}{b^{2}}\) | \(97\) |
default | \(\frac {\operatorname {Shi}\left (b x +a \right ) \left (-a \sinh \left (b x +a \right )+\left (b x +a \right ) \sinh \left (b x +a \right )-\cosh \left (b x +a \right )\right )+a \left (-\frac {\ln \left (b x +a \right )}{2}+\frac {\operatorname {Chi}\left (2 b x +2 a \right )}{2}\right )-\frac {\cosh \left (b x +a \right ) \sinh \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}+\frac {\operatorname {Shi}\left (2 b x +2 a \right )}{2}}{b^{2}}\) | \(97\) |
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\[ \int x \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int { x {\rm Shi}\left (b x + a\right ) \cosh \left (b x + a\right ) \,d x } \]
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\[ \int x \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int x \cosh {\left (a + b x \right )} \operatorname {Shi}{\left (a + b x \right )}\, dx \]
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\[ \int x \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int { x {\rm Shi}\left (b x + a\right ) \cosh \left (b x + a\right ) \,d x } \]
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\[ \int x \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int { x {\rm Shi}\left (b x + a\right ) \cosh \left (b x + a\right ) \,d x } \]
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Timed out. \[ \int x \cosh (a+b x) \text {Shi}(a+b x) \, dx=\int x\,\mathrm {sinhint}\left (a+b\,x\right )\,\mathrm {cosh}\left (a+b\,x\right ) \,d x \]
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