Optimal. Leaf size=49 \[ a \log (x)-\frac {1}{2} a \log \left (1-a x^2\right )+\frac {\log \left (1-a x^2\right )}{2 x^2}-\frac {\text {PolyLog}\left (2,a x^2\right )}{2 x^2} \]
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Rubi [A]
time = 0.03, antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.546, Rules used = {6726, 2504,
2442, 36, 29, 31} \begin {gather*} -\frac {\text {Li}_2\left (a x^2\right )}{2 x^2}-\frac {1}{2} a \log \left (1-a x^2\right )+\frac {\log \left (1-a x^2\right )}{2 x^2}+a \log (x) \end {gather*}
Antiderivative was successfully verified.
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Rule 29
Rule 31
Rule 36
Rule 2442
Rule 2504
Rule 6726
Rubi steps
\begin {align*} \int \frac {\text {Li}_2\left (a x^2\right )}{x^3} \, dx &=-\frac {\text {Li}_2\left (a x^2\right )}{2 x^2}-\int \frac {\log \left (1-a x^2\right )}{x^3} \, dx\\ &=-\frac {\text {Li}_2\left (a x^2\right )}{2 x^2}-\frac {1}{2} \text {Subst}\left (\int \frac {\log (1-a x)}{x^2} \, dx,x,x^2\right )\\ &=\frac {\log \left (1-a x^2\right )}{2 x^2}-\frac {\text {Li}_2\left (a x^2\right )}{2 x^2}+\frac {1}{2} a \text {Subst}\left (\int \frac {1}{x (1-a x)} \, dx,x,x^2\right )\\ &=\frac {\log \left (1-a x^2\right )}{2 x^2}-\frac {\text {Li}_2\left (a x^2\right )}{2 x^2}+\frac {1}{2} a \text {Subst}\left (\int \frac {1}{x} \, dx,x,x^2\right )+\frac {1}{2} a^2 \text {Subst}\left (\int \frac {1}{1-a x} \, dx,x,x^2\right )\\ &=a \log (x)-\frac {1}{2} a \log \left (1-a x^2\right )+\frac {\log \left (1-a x^2\right )}{2 x^2}-\frac {\text {Li}_2\left (a x^2\right )}{2 x^2}\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 49, normalized size = 1.00 \begin {gather*} a \log (x)-\frac {1}{2} a \log \left (1-a x^2\right )+\frac {\log \left (1-a x^2\right )}{2 x^2}-\frac {\text {PolyLog}\left (2,a x^2\right )}{2 x^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 43, normalized size = 0.88
method | result | size |
default | \(-\frac {\polylog \left (2, a \,x^{2}\right )}{2 x^{2}}+\frac {\ln \left (-a \,x^{2}+1\right )}{2 x^{2}}+a \left (-\frac {\ln \left (a \,x^{2}-1\right )}{2}+\ln \left (x \right )\right )\) | \(43\) |
meijerg | \(\frac {a \left (\frac {\left (-4 a \,x^{2}+4\right ) \ln \left (-a \,x^{2}+1\right )}{4 a \,x^{2}}-\frac {\polylog \left (2, a \,x^{2}\right )}{a \,x^{2}}+2 \ln \left (x \right )+\ln \left (-a \right )\right )}{2}\) | \(53\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.26, size = 34, normalized size = 0.69 \begin {gather*} a \log \left (x\right ) - \frac {{\left (a x^{2} - 1\right )} \log \left (-a x^{2} + 1\right ) + {\rm Li}_2\left (a x^{2}\right )}{2 \, x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 44, normalized size = 0.90 \begin {gather*} -\frac {a x^{2} \log \left (a x^{2} - 1\right ) - 2 \, a x^{2} \log \left (x\right ) + {\rm Li}_2\left (a x^{2}\right ) - \log \left (-a x^{2} + 1\right )}{2 \, x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.81, size = 37, normalized size = 0.76 \begin {gather*} a \log {\left (x \right )} + \frac {a \operatorname {Li}_{1}\left (a x^{2}\right )}{2} - \frac {\operatorname {Li}_{1}\left (a x^{2}\right )}{2 x^{2}} - \frac {\operatorname {Li}_{2}\left (a x^{2}\right )}{2 x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.21, size = 44, normalized size = 0.90 \begin {gather*} \frac {3\,a\,\ln \left (x\right )}{2}+\frac {\frac {\ln \left (1-a\,x^2\right )}{2}-\frac {\mathrm {polylog}\left (2,a\,x^2\right )}{2}}{x^2}-\frac {a\,\ln \left (a\,x^3-x\right )}{2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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