Integrand size = 53, antiderivative size = 697 \[ \int \frac {1}{\sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}} \, dx=\frac {\left (1944 b c^4+3640 a b x\right ) \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}+\left (-2106 b c^3+6561 a c^7 x\right ) \sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}+\left (2340 b c^2-4374 a c^6 x\right ) \sqrt {a x+\sqrt {-b+a^2 x^2}} \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}+\left (-2730 b c+3645 a c^5 x\right ) \left (a x+\sqrt {-b+a^2 x^2}\right )^{3/4} \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}+\sqrt {-b+a^2 x^2} \left (3640 b \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}+6561 c^7 \sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}-4374 c^6 \sqrt {a x+\sqrt {-b+a^2 x^2}} \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}+3645 c^5 \left (a x+\sqrt {-b+a^2 x^2}\right )^{3/4} \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}\right )}{4860 a c^5 \left (a x+\sqrt {-b+a^2 x^2}\right )^{5/4}}+\frac {182 b \arctan \left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}}{\sqrt {3} \sqrt [3]{c}}\right )}{243 \sqrt {3} a c^{16/3}}+\frac {182 b \log \left (-\sqrt [3]{c}+\sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}\right )}{729 a c^{16/3}}-\frac {91 b \log \left (c^{2/3}+\sqrt [3]{c} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}+\left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}\right )}{729 a c^{16/3}} \]
1/4860*((1944*b*c^4+3640*a*b*x)*(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(2/3)+(6 561*a*c^7*x-2106*b*c^3)*(a*x+(a^2*x^2-b)^(1/2))^(1/4)*(c+(a*x+(a^2*x^2-b)^ (1/2))^(1/4))^(2/3)+(-4374*a*c^6*x+2340*b*c^2)*(a*x+(a^2*x^2-b)^(1/2))^(1/ 2)*(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(2/3)+(3645*a*c^5*x-2730*b*c)*(a*x+(a ^2*x^2-b)^(1/2))^(3/4)*(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(2/3)+(a^2*x^2-b) ^(1/2)*(3640*b*(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(2/3)+6561*c^7*(a*x+(a^2* x^2-b)^(1/2))^(1/4)*(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(2/3)-4374*c^6*(a*x+ (a^2*x^2-b)^(1/2))^(1/2)*(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(2/3)+3645*c^5* (a*x+(a^2*x^2-b)^(1/2))^(3/4)*(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(2/3)))/a/ c^5/(a*x+(a^2*x^2-b)^(1/2))^(5/4)+182/729*b*arctan(1/3*3^(1/2)+2/3*(c+(a*x +(a^2*x^2-b)^(1/2))^(1/4))^(1/3)*3^(1/2)/c^(1/3))*3^(1/2)/a/c^(16/3)+182/7 29*b*ln(-c^(1/3)+(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(1/3))/a/c^(16/3)-91/72 9*b*ln(c^(2/3)+c^(1/3)*(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4))^(1/3)+(c+(a*x+(a^ 2*x^2-b)^(1/2))^(1/4))^(2/3))/a/c^(16/3)
Time = 2.34 (sec) , antiderivative size = 438, normalized size of antiderivative = 0.63 \[ \int \frac {1}{\sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}} \, dx=\frac {\frac {3 \sqrt [3]{c} \left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3} \left (729 c^5 \left (a x+\sqrt {-b+a^2 x^2}\right )^{5/4} \left (9 c^2-6 c \sqrt [4]{a x+\sqrt {-b+a^2 x^2}}+5 \sqrt {a x+\sqrt {-b+a^2 x^2}}\right )+2 b \left (972 c^4-1053 c^3 \sqrt [4]{a x+\sqrt {-b+a^2 x^2}}+1170 c^2 \sqrt {a x+\sqrt {-b+a^2 x^2}}-1365 c \left (a x+\sqrt {-b+a^2 x^2}\right )^{3/4}+1820 \left (a x+\sqrt {-b+a^2 x^2}\right )\right )\right )}{\left (a x+\sqrt {-b+a^2 x^2}\right )^{5/4}}+3640 \sqrt {3} b \arctan \left (\frac {1+\frac {2 \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}}{\sqrt [3]{c}}}{\sqrt {3}}\right )+3640 b \log \left (-\sqrt [3]{c}+\sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}\right )-1820 b \log \left (c^{2/3}+\sqrt [3]{c} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}+\left (c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}\right )^{2/3}\right )}{14580 a c^{16/3}} \]
Integrate[1/((a*x + Sqrt[-b + a^2*x^2])^(1/4)*(c + (a*x + Sqrt[-b + a^2*x^ 2])^(1/4))^(1/3)),x]
((3*c^(1/3)*(c + (a*x + Sqrt[-b + a^2*x^2])^(1/4))^(2/3)*(729*c^5*(a*x + S qrt[-b + a^2*x^2])^(5/4)*(9*c^2 - 6*c*(a*x + Sqrt[-b + a^2*x^2])^(1/4) + 5 *Sqrt[a*x + Sqrt[-b + a^2*x^2]]) + 2*b*(972*c^4 - 1053*c^3*(a*x + Sqrt[-b + a^2*x^2])^(1/4) + 1170*c^2*Sqrt[a*x + Sqrt[-b + a^2*x^2]] - 1365*c*(a*x + Sqrt[-b + a^2*x^2])^(3/4) + 1820*(a*x + Sqrt[-b + a^2*x^2]))))/(a*x + Sq rt[-b + a^2*x^2])^(5/4) + 3640*Sqrt[3]*b*ArcTan[(1 + (2*(c + (a*x + Sqrt[- b + a^2*x^2])^(1/4))^(1/3))/c^(1/3))/Sqrt[3]] + 3640*b*Log[-c^(1/3) + (c + (a*x + Sqrt[-b + a^2*x^2])^(1/4))^(1/3)] - 1820*b*Log[c^(2/3) + c^(1/3)*( c + (a*x + Sqrt[-b + a^2*x^2])^(1/4))^(1/3) + (c + (a*x + Sqrt[-b + a^2*x^ 2])^(1/4))^(2/3)])/(14580*a*c^(16/3))
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{\sqrt [4]{\sqrt {a^2 x^2-b}+a x} \sqrt [3]{\sqrt [4]{\sqrt {a^2 x^2-b}+a x}+c}} \, dx\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \int \frac {1}{\sqrt [4]{\sqrt {a^2 x^2-b}+a x} \sqrt [3]{\sqrt [4]{\sqrt {a^2 x^2-b}+a x}+c}}dx\) |
3.32.20.3.1 Defintions of rubi rules used
\[\int \frac {1}{\left (a x +\sqrt {a^{2} x^{2}-b}\right )^{\frac {1}{4}} {\left (c +\left (a x +\sqrt {a^{2} x^{2}-b}\right )^{\frac {1}{4}}\right )}^{\frac {1}{3}}}d x\]
Time = 0.41 (sec) , antiderivative size = 1036, normalized size of antiderivative = 1.49 \[ \int \frac {1}{\sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}} \, dx=\text {Too large to display} \]
integrate(1/(a*x+(a^2*x^2-b)^(1/2))^(1/4)/(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4) )^(1/3),x, algorithm="fricas")
[1/14580*(5460*sqrt(1/3)*b^2*c*sqrt(-1/c^(2/3))*log(6*sqrt(1/3)*(a*c^(2/3) *x - sqrt(a^2*x^2 - b)*c^(2/3))*(a*x + sqrt(a^2*x^2 - b))^(3/4)*(c + (a*x + sqrt(a^2*x^2 - b))^(1/4))^(2/3)*sqrt(-1/c^(2/3)) - 3*(a*c^(2/3)*x + sqrt (1/3)*(a*c*x - sqrt(a^2*x^2 - b)*c)*sqrt(-1/c^(2/3)) - sqrt(a^2*x^2 - b)*c ^(2/3))*(a*x + sqrt(a^2*x^2 - b))^(3/4)*(c + (a*x + sqrt(a^2*x^2 - b))^(1/ 4))^(1/3) + 3*(a*c*x - sqrt(1/3)*(a*c^(4/3)*x - sqrt(a^2*x^2 - b)*c^(4/3)) *sqrt(-1/c^(2/3)) - sqrt(a^2*x^2 - b)*c)*(a*x + sqrt(a^2*x^2 - b))^(3/4) + 2*b) - 1820*b^2*c^(2/3)*log((c + (a*x + sqrt(a^2*x^2 - b))^(1/4))^(2/3) + (c + (a*x + sqrt(a^2*x^2 - b))^(1/4))^(1/3)*c^(1/3) + c^(2/3)) + 3640*b^2 *c^(2/3)*log((c + (a*x + sqrt(a^2*x^2 - b))^(1/4))^(1/3) - c^(1/3)) + 3*(6 561*b*c^8 - 2106*a*b*c^4*x + 2106*sqrt(a^2*x^2 - b)*b*c^4 + 8*(486*a^2*c^5 *x^2 - 243*b*c^5 + 455*a*b*c*x - (486*a*c^5*x + 455*b*c)*sqrt(a^2*x^2 - b) )*(a*x + sqrt(a^2*x^2 - b))^(3/4) + 15*(243*b*c^6 - 182*a*b*c^2*x + 182*sq rt(a^2*x^2 - b)*b*c^2)*sqrt(a*x + sqrt(a^2*x^2 - b)) - 18*(243*b*c^7 - 130 *a*b*c^3*x + 130*sqrt(a^2*x^2 - b)*b*c^3)*(a*x + sqrt(a^2*x^2 - b))^(1/4)) *(c + (a*x + sqrt(a^2*x^2 - b))^(1/4))^(2/3))/(a*b*c^6), 1/14580*(10920*sq rt(1/3)*b^2*c^(2/3)*arctan(sqrt(1/3) + 2*sqrt(1/3)*(c + (a*x + sqrt(a^2*x^ 2 - b))^(1/4))^(1/3)/c^(1/3)) - 1820*b^2*c^(2/3)*log((c + (a*x + sqrt(a^2* x^2 - b))^(1/4))^(2/3) + (c + (a*x + sqrt(a^2*x^2 - b))^(1/4))^(1/3)*c^(1/ 3) + c^(2/3)) + 3640*b^2*c^(2/3)*log((c + (a*x + sqrt(a^2*x^2 - b))^(1/...
\[ \int \frac {1}{\sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}} \, dx=\int \frac {1}{\sqrt [3]{c + \sqrt [4]{a x + \sqrt {a^{2} x^{2} - b}}} \sqrt [4]{a x + \sqrt {a^{2} x^{2} - b}}}\, dx \]
integrate(1/(a*x+(a**2*x**2-b)**(1/2))**(1/4)/(c+(a*x+(a**2*x**2-b)**(1/2) )**(1/4))**(1/3),x)
Integral(1/((c + (a*x + sqrt(a**2*x**2 - b))**(1/4))**(1/3)*(a*x + sqrt(a* *2*x**2 - b))**(1/4)), x)
\[ \int \frac {1}{\sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}} \, dx=\int { \frac {1}{{\left (a x + \sqrt {a^{2} x^{2} - b}\right )}^{\frac {1}{4}} {\left (c + {\left (a x + \sqrt {a^{2} x^{2} - b}\right )}^{\frac {1}{4}}\right )}^{\frac {1}{3}}} \,d x } \]
integrate(1/(a*x+(a^2*x^2-b)^(1/2))^(1/4)/(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4) )^(1/3),x, algorithm="maxima")
integrate(1/((a*x + sqrt(a^2*x^2 - b))^(1/4)*(c + (a*x + sqrt(a^2*x^2 - b) )^(1/4))^(1/3)), x)
Timed out. \[ \int \frac {1}{\sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}} \, dx=\text {Timed out} \]
integrate(1/(a*x+(a^2*x^2-b)^(1/2))^(1/4)/(c+(a*x+(a^2*x^2-b)^(1/2))^(1/4) )^(1/3),x, algorithm="giac")
Timed out. \[ \int \frac {1}{\sqrt [4]{a x+\sqrt {-b+a^2 x^2}} \sqrt [3]{c+\sqrt [4]{a x+\sqrt {-b+a^2 x^2}}}} \, dx=\int \frac {1}{{\left (a\,x+\sqrt {a^2\,x^2-b}\right )}^{1/4}\,{\left (c+{\left (a\,x+\sqrt {a^2\,x^2-b}\right )}^{1/4}\right )}^{1/3}} \,d x \]