Integrand size = 15, antiderivative size = 161 \[ \int (d x)^{5/2} \operatorname {PolyLog}\left (3,a x^2\right ) \, dx=\frac {128 d (d x)^{3/2}}{1029 a}+\frac {128 (d x)^{7/2}}{2401 d}+\frac {64 d^{5/2} \arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{343 a^{7/4}}-\frac {64 d^{5/2} \text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{343 a^{7/4}}-\frac {32 (d x)^{7/2} \log \left (1-a x^2\right )}{343 d}-\frac {8 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{49 d}+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d} \]
128/1029*d*(d*x)^(3/2)/a+128/2401*(d*x)^(7/2)/d+64/343*d^(5/2)*arctan(a^(1 /4)*(d*x)^(1/2)/d^(1/2))/a^(7/4)-64/343*d^(5/2)*arctanh(a^(1/4)*(d*x)^(1/2 )/d^(1/2))/a^(7/4)-32/343*(d*x)^(7/2)*ln(-a*x^2+1)/d-8/49*(d*x)^(7/2)*poly log(2,a*x^2)/d+2/7*(d*x)^(7/2)*polylog(3,a*x^2)/d
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.10 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.55 \[ \int (d x)^{5/2} \operatorname {PolyLog}\left (3,a x^2\right ) \, dx=-\frac {11 d (d x)^{3/2} \operatorname {Gamma}\left (\frac {11}{4}\right ) \left (-448-192 a x^2+448 \operatorname {Hypergeometric2F1}\left (\frac {3}{4},1,\frac {7}{4},a x^2\right )+336 a x^2 \log \left (1-a x^2\right )+588 a x^2 \operatorname {PolyLog}\left (2,a x^2\right )-1029 a x^2 \operatorname {PolyLog}\left (3,a x^2\right )\right )}{14406 a \operatorname {Gamma}\left (\frac {15}{4}\right )} \]
(-11*d*(d*x)^(3/2)*Gamma[11/4]*(-448 - 192*a*x^2 + 448*Hypergeometric2F1[3 /4, 1, 7/4, a*x^2] + 336*a*x^2*Log[1 - a*x^2] + 588*a*x^2*PolyLog[2, a*x^2 ] - 1029*a*x^2*PolyLog[3, a*x^2]))/(14406*a*Gamma[15/4])
Time = 0.43 (sec) , antiderivative size = 198, normalized size of antiderivative = 1.23, number of steps used = 13, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.800, Rules used = {7145, 7145, 25, 2905, 8, 262, 262, 266, 27, 827, 218, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (d x)^{5/2} \operatorname {PolyLog}\left (3,a x^2\right ) \, dx\) |
\(\Big \downarrow \) 7145 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \int (d x)^{5/2} \operatorname {PolyLog}\left (2,a x^2\right )dx\) |
\(\Big \downarrow \) 7145 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}-\frac {4}{7} \int -(d x)^{5/2} \log \left (1-a x^2\right )dx\right )\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \int (d x)^{5/2} \log \left (1-a x^2\right )dx+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 2905 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \int \frac {x (d x)^{7/2}}{1-a x^2}dx}{7 d}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 8 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \int \frac {(d x)^{9/2}}{1-a x^2}dx}{7 d^2}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 262 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \left (\frac {d^2 \int \frac {(d x)^{5/2}}{1-a x^2}dx}{a}-\frac {2 d (d x)^{7/2}}{7 a}\right )}{7 d^2}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 262 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \left (\frac {d^2 \left (\frac {d^2 \int \frac {\sqrt {d x}}{1-a x^2}dx}{a}-\frac {2 d (d x)^{3/2}}{3 a}\right )}{a}-\frac {2 d (d x)^{7/2}}{7 a}\right )}{7 d^2}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 266 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \left (\frac {d^2 \left (\frac {2 d \int \frac {d^3 x}{d^2-a d^2 x^2}d\sqrt {d x}}{a}-\frac {2 d (d x)^{3/2}}{3 a}\right )}{a}-\frac {2 d (d x)^{7/2}}{7 a}\right )}{7 d^2}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \left (\frac {d^2 \left (\frac {2 d^3 \int \frac {d x}{d^2-a d^2 x^2}d\sqrt {d x}}{a}-\frac {2 d (d x)^{3/2}}{3 a}\right )}{a}-\frac {2 d (d x)^{7/2}}{7 a}\right )}{7 d^2}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 827 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \left (\frac {d^2 \left (\frac {2 d^3 \left (\frac {\int \frac {1}{d-\sqrt {a} d x}d\sqrt {d x}}{2 \sqrt {a}}-\frac {\int \frac {1}{\sqrt {a} x d+d}d\sqrt {d x}}{2 \sqrt {a}}\right )}{a}-\frac {2 d (d x)^{3/2}}{3 a}\right )}{a}-\frac {2 d (d x)^{7/2}}{7 a}\right )}{7 d^2}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 218 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \left (\frac {d^2 \left (\frac {2 d^3 \left (\frac {\int \frac {1}{d-\sqrt {a} d x}d\sqrt {d x}}{2 \sqrt {a}}-\frac {\arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 a^{3/4} \sqrt {d}}\right )}{a}-\frac {2 d (d x)^{3/2}}{3 a}\right )}{a}-\frac {2 d (d x)^{7/2}}{7 a}\right )}{7 d^2}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
\(\Big \downarrow \) 221 |
\(\displaystyle \frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (3,a x^2\right )}{7 d}-\frac {4}{7} \left (\frac {4}{7} \left (\frac {4 a \left (\frac {d^2 \left (\frac {2 d^3 \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 a^{3/4} \sqrt {d}}-\frac {\arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 a^{3/4} \sqrt {d}}\right )}{a}-\frac {2 d (d x)^{3/2}}{3 a}\right )}{a}-\frac {2 d (d x)^{7/2}}{7 a}\right )}{7 d^2}+\frac {2 (d x)^{7/2} \log \left (1-a x^2\right )}{7 d}\right )+\frac {2 (d x)^{7/2} \operatorname {PolyLog}\left (2,a x^2\right )}{7 d}\right )\) |
(-4*((4*((4*a*((-2*d*(d*x)^(7/2))/(7*a) + (d^2*((-2*d*(d*x)^(3/2))/(3*a) + (2*d^3*(-1/2*ArcTan[(a^(1/4)*Sqrt[d*x])/Sqrt[d]]/(a^(3/4)*Sqrt[d]) + ArcT anh[(a^(1/4)*Sqrt[d*x])/Sqrt[d]]/(2*a^(3/4)*Sqrt[d])))/a))/a))/(7*d^2) + ( 2*(d*x)^(7/2)*Log[1 - a*x^2])/(7*d)))/7 + (2*(d*x)^(7/2)*PolyLog[2, a*x^2] )/(7*d)))/7 + (2*(d*x)^(7/2)*PolyLog[3, a*x^2])/(7*d)
3.1.78.3.1 Defintions of rubi rules used
Int[(u_.)*(x_)^(m_.)*((a_.)*(x_))^(p_), x_Symbol] :> Simp[1/a^m Int[u*(a* x)^(m + p), x], x] /; FreeQ[{a, m, p}, x] && IntegerQ[m]
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[c*(c*x) ^(m - 1)*((a + b*x^2)^(p + 1)/(b*(m + 2*p + 1))), x] - Simp[a*c^2*((m - 1)/ (b*(m + 2*p + 1))) Int[(c*x)^(m - 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b , c, p}, x] && GtQ[m, 2 - 1] && NeQ[m + 2*p + 1, 0] && IntBinomialQ[a, b, c , 2, m, p, x]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2*b) Int[1/(r + s*x^2), x], x] - Simp[s/(2*b) Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] && !GtQ [a/b, 0]
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))*((f_.)*(x_))^ (m_.), x_Symbol] :> Simp[(f*x)^(m + 1)*((a + b*Log[c*(d + e*x^n)^p])/(f*(m + 1))), x] - Simp[b*e*n*(p/(f*(m + 1))) Int[x^(n - 1)*((f*x)^(m + 1)/(d + e*x^n)), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && NeQ[m, -1]
Int[((d_.)*(x_))^(m_.)*PolyLog[n_, (a_.)*((b_.)*(x_)^(p_.))^(q_.)], x_Symbo l] :> Simp[(d*x)^(m + 1)*(PolyLog[n, a*(b*x^p)^q]/(d*(m + 1))), x] - Simp[p *(q/(m + 1)) Int[(d*x)^m*PolyLog[n - 1, a*(b*x^p)^q], x], x] /; FreeQ[{a, b, d, m, p, q}, x] && NeQ[m, -1] && GtQ[n, 0]
Time = 0.20 (sec) , antiderivative size = 155, normalized size of antiderivative = 0.96
method | result | size |
meijerg | \(-\frac {\left (d x \right )^{\frac {5}{2}} \left (\frac {4 x^{\frac {3}{2}} \left (-a \right )^{\frac {11}{4}} \left (2112 a \,x^{2}+4928\right )}{79233 a^{2}}+\frac {64 x^{\frac {3}{2}} \left (-a \right )^{\frac {11}{4}} \left (\ln \left (1-\left (a \,x^{2}\right )^{\frac {1}{4}}\right )-\ln \left (1+\left (a \,x^{2}\right )^{\frac {1}{4}}\right )+2 \arctan \left (\left (a \,x^{2}\right )^{\frac {1}{4}}\right )\right )}{343 a^{2} \left (a \,x^{2}\right )^{\frac {3}{4}}}-\frac {64 x^{\frac {7}{2}} \left (-a \right )^{\frac {11}{4}} \ln \left (-a \,x^{2}+1\right )}{343 a}-\frac {16 x^{\frac {7}{2}} \left (-a \right )^{\frac {11}{4}} \operatorname {polylog}\left (2, a \,x^{2}\right )}{49 a}+\frac {4 x^{\frac {7}{2}} \left (-a \right )^{\frac {11}{4}} \operatorname {polylog}\left (3, a \,x^{2}\right )}{7 a}\right )}{2 x^{\frac {5}{2}} \left (-a \right )^{\frac {7}{4}}}\) | \(155\) |
-1/2*(d*x)^(5/2)/x^(5/2)/(-a)^(7/4)*(4/79233*x^(3/2)*(-a)^(11/4)*(2112*a*x ^2+4928)/a^2+64/343*x^(3/2)*(-a)^(11/4)/a^2/(a*x^2)^(3/4)*(ln(1-(a*x^2)^(1 /4))-ln(1+(a*x^2)^(1/4))+2*arctan((a*x^2)^(1/4)))-64/343*x^(7/2)*(-a)^(11/ 4)*ln(-a*x^2+1)/a-16/49*x^(7/2)*(-a)^(11/4)/a*polylog(2,a*x^2)+4/7*x^(7/2) *(-a)^(11/4)/a*polylog(3,a*x^2))
Result contains complex when optimal does not.
Time = 0.29 (sec) , antiderivative size = 235, normalized size of antiderivative = 1.46 \[ \int (d x)^{5/2} \operatorname {PolyLog}\left (3,a x^2\right ) \, dx=\frac {2 \, {\left (1029 \, \sqrt {d x} a d^{2} x^{3} {\rm polylog}\left (3, a x^{2}\right ) - 336 \, \left (\frac {d^{10}}{a^{7}}\right )^{\frac {1}{4}} a \log \left (32768 \, \sqrt {d x} d^{7} + 32768 \, \left (\frac {d^{10}}{a^{7}}\right )^{\frac {3}{4}} a^{5}\right ) + 336 i \, \left (\frac {d^{10}}{a^{7}}\right )^{\frac {1}{4}} a \log \left (32768 \, \sqrt {d x} d^{7} + 32768 i \, \left (\frac {d^{10}}{a^{7}}\right )^{\frac {3}{4}} a^{5}\right ) - 336 i \, \left (\frac {d^{10}}{a^{7}}\right )^{\frac {1}{4}} a \log \left (32768 \, \sqrt {d x} d^{7} - 32768 i \, \left (\frac {d^{10}}{a^{7}}\right )^{\frac {3}{4}} a^{5}\right ) + 336 \, \left (\frac {d^{10}}{a^{7}}\right )^{\frac {1}{4}} a \log \left (32768 \, \sqrt {d x} d^{7} - 32768 \, \left (\frac {d^{10}}{a^{7}}\right )^{\frac {3}{4}} a^{5}\right ) - 4 \, {\left (147 \, a d^{2} x^{3} {\rm Li}_2\left (a x^{2}\right ) + 84 \, a d^{2} x^{3} \log \left (-a x^{2} + 1\right ) - 48 \, a d^{2} x^{3} - 112 \, d^{2} x\right )} \sqrt {d x}\right )}}{7203 \, a} \]
2/7203*(1029*sqrt(d*x)*a*d^2*x^3*polylog(3, a*x^2) - 336*(d^10/a^7)^(1/4)* a*log(32768*sqrt(d*x)*d^7 + 32768*(d^10/a^7)^(3/4)*a^5) + 336*I*(d^10/a^7) ^(1/4)*a*log(32768*sqrt(d*x)*d^7 + 32768*I*(d^10/a^7)^(3/4)*a^5) - 336*I*( d^10/a^7)^(1/4)*a*log(32768*sqrt(d*x)*d^7 - 32768*I*(d^10/a^7)^(3/4)*a^5) + 336*(d^10/a^7)^(1/4)*a*log(32768*sqrt(d*x)*d^7 - 32768*(d^10/a^7)^(3/4)* a^5) - 4*(147*a*d^2*x^3*dilog(a*x^2) + 84*a*d^2*x^3*log(-a*x^2 + 1) - 48*a *d^2*x^3 - 112*d^2*x)*sqrt(d*x))/a
\[ \int (d x)^{5/2} \operatorname {PolyLog}\left (3,a x^2\right ) \, dx=\int \left (d x\right )^{\frac {5}{2}} \operatorname {Li}_{3}\left (a x^{2}\right )\, dx \]
Time = 0.27 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.11 \[ \int (d x)^{5/2} \operatorname {PolyLog}\left (3,a x^2\right ) \, dx=\frac {2 \, {\left (\frac {336 \, d^{4} {\left (\frac {2 \, \arctan \left (\frac {\sqrt {d x} \sqrt {a}}{\sqrt {\sqrt {a} d}}\right )}{\sqrt {\sqrt {a} d} \sqrt {a}} + \frac {\log \left (\frac {\sqrt {d x} \sqrt {a} - \sqrt {\sqrt {a} d}}{\sqrt {d x} \sqrt {a} + \sqrt {\sqrt {a} d}}\right )}{\sqrt {\sqrt {a} d} \sqrt {a}}\right )}}{a} - \frac {588 \, \left (d x\right )^{\frac {7}{2}} a {\rm Li}_2\left (a x^{2}\right ) + 336 \, \left (d x\right )^{\frac {7}{2}} a \log \left (-a d^{2} x^{2} + d^{2}\right ) - 1029 \, \left (d x\right )^{\frac {7}{2}} a {\rm Li}_{3}(a x^{2}) - 96 \, \left (d x\right )^{\frac {7}{2}} {\left (7 \, a \log \left (d\right ) + 2 \, a\right )} - 448 \, \left (d x\right )^{\frac {3}{2}} d^{2}}{a}\right )}}{7203 \, d} \]
2/7203*(336*d^4*(2*arctan(sqrt(d*x)*sqrt(a)/sqrt(sqrt(a)*d))/(sqrt(sqrt(a) *d)*sqrt(a)) + log((sqrt(d*x)*sqrt(a) - sqrt(sqrt(a)*d))/(sqrt(d*x)*sqrt(a ) + sqrt(sqrt(a)*d)))/(sqrt(sqrt(a)*d)*sqrt(a)))/a - (588*(d*x)^(7/2)*a*di log(a*x^2) + 336*(d*x)^(7/2)*a*log(-a*d^2*x^2 + d^2) - 1029*(d*x)^(7/2)*a* polylog(3, a*x^2) - 96*(d*x)^(7/2)*(7*a*log(d) + 2*a) - 448*(d*x)^(3/2)*d^ 2)/a)/d
\[ \int (d x)^{5/2} \operatorname {PolyLog}\left (3,a x^2\right ) \, dx=\int { \left (d x\right )^{\frac {5}{2}} {\rm Li}_{3}(a x^{2}) \,d x } \]
Timed out. \[ \int (d x)^{5/2} \operatorname {PolyLog}\left (3,a x^2\right ) \, dx=\int \mathrm {polylog}\left (3,a\,x^2\right )\,{\left (d\,x\right )}^{5/2} \,d x \]