3.1.82 \(\int \frac {\operatorname {PolyLog}(3,a x^2)}{(d x)^{3/2}} \, dx\) [82]

3.1.82.1 Optimal result
3.1.82.2 Mathematica [C] (verified)
3.1.82.3 Rubi [A] (verified)
3.1.82.4 Maple [A] (verified)
3.1.82.5 Fricas [C] (verification not implemented)
3.1.82.6 Sympy [F]
3.1.82.7 Maxima [A] (verification not implemented)
3.1.82.8 Giac [F]
3.1.82.9 Mupad [F(-1)]

3.1.82.1 Optimal result

Integrand size = 15, antiderivative size = 122 \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{3/2}} \, dx=-\frac {64 \sqrt [4]{a} \arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{d^{3/2}}+\frac {64 \sqrt [4]{a} \text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{d^{3/2}}+\frac {32 \log \left (1-a x^2\right )}{d \sqrt {d x}}-\frac {8 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}} \]

output
-64*a^(1/4)*arctan(a^(1/4)*(d*x)^(1/2)/d^(1/2))/d^(3/2)+64*a^(1/4)*arctanh 
(a^(1/4)*(d*x)^(1/2)/d^(1/2))/d^(3/2)+32*ln(-a*x^2+1)/d/(d*x)^(1/2)-8*poly 
log(2,a*x^2)/d/(d*x)^(1/2)-2*polylog(3,a*x^2)/d/(d*x)^(1/2)
 
3.1.82.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 0.08 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.58 \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{3/2}} \, dx=\frac {x \operatorname {Gamma}\left (\frac {3}{4}\right ) \left (64 a x^2 \operatorname {Hypergeometric2F1}\left (\frac {3}{4},1,\frac {7}{4},a x^2\right )+48 \log \left (1-a x^2\right )-12 \operatorname {PolyLog}\left (2,a x^2\right )-3 \operatorname {PolyLog}\left (3,a x^2\right )\right )}{2 (d x)^{3/2} \operatorname {Gamma}\left (\frac {7}{4}\right )} \]

input
Integrate[PolyLog[3, a*x^2]/(d*x)^(3/2),x]
 
output
(x*Gamma[3/4]*(64*a*x^2*Hypergeometric2F1[3/4, 1, 7/4, a*x^2] + 48*Log[1 - 
 a*x^2] - 12*PolyLog[2, a*x^2] - 3*PolyLog[3, a*x^2]))/(2*(d*x)^(3/2)*Gamm 
a[7/4])
 
3.1.82.3 Rubi [A] (verified)

Time = 0.38 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.14, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.667, Rules used = {7145, 7145, 25, 2905, 8, 266, 27, 827, 218, 221}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{3/2}} \, dx\)

\(\Big \downarrow \) 7145

\(\displaystyle 4 \int \frac {\operatorname {PolyLog}\left (2,a x^2\right )}{(d x)^{3/2}}dx-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 7145

\(\displaystyle 4 \left (4 \int -\frac {\log \left (1-a x^2\right )}{(d x)^{3/2}}dx-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 25

\(\displaystyle 4 \left (-4 \int \frac {\log \left (1-a x^2\right )}{(d x)^{3/2}}dx-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 2905

\(\displaystyle 4 \left (-4 \left (-\frac {4 a \int \frac {x}{\sqrt {d x} \left (1-a x^2\right )}dx}{d}-\frac {2 \log \left (1-a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 8

\(\displaystyle 4 \left (-4 \left (-\frac {4 a \int \frac {\sqrt {d x}}{1-a x^2}dx}{d^2}-\frac {2 \log \left (1-a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 266

\(\displaystyle 4 \left (-4 \left (-\frac {8 a \int \frac {d^3 x}{d^2-a d^2 x^2}d\sqrt {d x}}{d^3}-\frac {2 \log \left (1-a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 27

\(\displaystyle 4 \left (-4 \left (-\frac {8 a \int \frac {d x}{d^2-a d^2 x^2}d\sqrt {d x}}{d}-\frac {2 \log \left (1-a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 827

\(\displaystyle 4 \left (-4 \left (-\frac {8 a \left (\frac {\int \frac {1}{d-\sqrt {a} d x}d\sqrt {d x}}{2 \sqrt {a}}-\frac {\int \frac {1}{\sqrt {a} x d+d}d\sqrt {d x}}{2 \sqrt {a}}\right )}{d}-\frac {2 \log \left (1-a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 218

\(\displaystyle 4 \left (-4 \left (-\frac {8 a \left (\frac {\int \frac {1}{d-\sqrt {a} d x}d\sqrt {d x}}{2 \sqrt {a}}-\frac {\arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 a^{3/4} \sqrt {d}}\right )}{d}-\frac {2 \log \left (1-a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

\(\Big \downarrow \) 221

\(\displaystyle 4 \left (-4 \left (-\frac {8 a \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 a^{3/4} \sqrt {d}}-\frac {\arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 a^{3/4} \sqrt {d}}\right )}{d}-\frac {2 \log \left (1-a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{d \sqrt {d x}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{d \sqrt {d x}}\)

input
Int[PolyLog[3, a*x^2]/(d*x)^(3/2),x]
 
output
4*(-4*((-8*a*(-1/2*ArcTan[(a^(1/4)*Sqrt[d*x])/Sqrt[d]]/(a^(3/4)*Sqrt[d]) + 
 ArcTanh[(a^(1/4)*Sqrt[d*x])/Sqrt[d]]/(2*a^(3/4)*Sqrt[d])))/d - (2*Log[1 - 
 a*x^2])/(d*Sqrt[d*x])) - (2*PolyLog[2, a*x^2])/(d*Sqrt[d*x])) - (2*PolyLo 
g[3, a*x^2])/(d*Sqrt[d*x])
 

3.1.82.3.1 Defintions of rubi rules used

rule 8
Int[(u_.)*(x_)^(m_.)*((a_.)*(x_))^(p_), x_Symbol] :> Simp[1/a^m   Int[u*(a* 
x)^(m + p), x], x] /; FreeQ[{a, m, p}, x] && IntegerQ[m]
 

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 218
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R 
t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
 

rule 221
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 266
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De 
nominator[m]}, Simp[k/c   Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) 
^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I 
ntBinomialQ[a, b, c, 2, m, p, x]
 

rule 827
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 
 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2*b)   Int[1/(r + s*x^2), x], 
x] - Simp[s/(2*b)   Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !GtQ 
[a/b, 0]
 

rule 2905
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))*((f_.)*(x_))^ 
(m_.), x_Symbol] :> Simp[(f*x)^(m + 1)*((a + b*Log[c*(d + e*x^n)^p])/(f*(m 
+ 1))), x] - Simp[b*e*n*(p/(f*(m + 1)))   Int[x^(n - 1)*((f*x)^(m + 1)/(d + 
 e*x^n)), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && NeQ[m, -1]
 

rule 7145
Int[((d_.)*(x_))^(m_.)*PolyLog[n_, (a_.)*((b_.)*(x_)^(p_.))^(q_.)], x_Symbo 
l] :> Simp[(d*x)^(m + 1)*(PolyLog[n, a*(b*x^p)^q]/(d*(m + 1))), x] - Simp[p 
*(q/(m + 1))   Int[(d*x)^m*PolyLog[n - 1, a*(b*x^p)^q], x], x] /; FreeQ[{a, 
 b, d, m, p, q}, x] && NeQ[m, -1] && GtQ[n, 0]
 
3.1.82.4 Maple [A] (verified)

Time = 0.28 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.07

method result size
meijerg \(-\frac {x^{\frac {3}{2}} \left (-a \right )^{\frac {1}{4}} \left (-\frac {64 x^{\frac {3}{2}} \left (-a \right )^{\frac {3}{4}} \left (\ln \left (1-\left (a \,x^{2}\right )^{\frac {1}{4}}\right )-\ln \left (1+\left (a \,x^{2}\right )^{\frac {1}{4}}\right )+2 \arctan \left (\left (a \,x^{2}\right )^{\frac {1}{4}}\right )\right )}{\left (a \,x^{2}\right )^{\frac {3}{4}}}+\frac {64 \left (-a \right )^{\frac {3}{4}} \ln \left (-a \,x^{2}+1\right )}{\sqrt {x}\, a}-\frac {16 \left (-a \right )^{\frac {3}{4}} \operatorname {polylog}\left (2, a \,x^{2}\right )}{\sqrt {x}\, a}-\frac {4 \left (-a \right )^{\frac {3}{4}} \operatorname {polylog}\left (3, a \,x^{2}\right )}{\sqrt {x}\, a}\right )}{2 \left (d x \right )^{\frac {3}{2}}}\) \(131\)

input
int(polylog(3,a*x^2)/(d*x)^(3/2),x,method=_RETURNVERBOSE)
 
output
-1/2/(d*x)^(3/2)*x^(3/2)*(-a)^(1/4)*(-64*x^(3/2)*(-a)^(3/4)/(a*x^2)^(3/4)* 
(ln(1-(a*x^2)^(1/4))-ln(1+(a*x^2)^(1/4))+2*arctan((a*x^2)^(1/4)))+64/x^(1/ 
2)*(-a)^(3/4)*ln(-a*x^2+1)/a-16/x^(1/2)*(-a)^(3/4)/a*polylog(2,a*x^2)-4/x^ 
(1/2)*(-a)^(3/4)/a*polylog(3,a*x^2))
 
3.1.82.5 Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.28 (sec) , antiderivative size = 188, normalized size of antiderivative = 1.54 \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{3/2}} \, dx=\frac {2 \, {\left (16 \, d^{2} x \left (\frac {a}{d^{6}}\right )^{\frac {1}{4}} \log \left (32768 \, d^{5} \left (\frac {a}{d^{6}}\right )^{\frac {3}{4}} + 32768 \, \sqrt {d x} a\right ) - 16 i \, d^{2} x \left (\frac {a}{d^{6}}\right )^{\frac {1}{4}} \log \left (32768 i \, d^{5} \left (\frac {a}{d^{6}}\right )^{\frac {3}{4}} + 32768 \, \sqrt {d x} a\right ) + 16 i \, d^{2} x \left (\frac {a}{d^{6}}\right )^{\frac {1}{4}} \log \left (-32768 i \, d^{5} \left (\frac {a}{d^{6}}\right )^{\frac {3}{4}} + 32768 \, \sqrt {d x} a\right ) - 16 \, d^{2} x \left (\frac {a}{d^{6}}\right )^{\frac {1}{4}} \log \left (-32768 \, d^{5} \left (\frac {a}{d^{6}}\right )^{\frac {3}{4}} + 32768 \, \sqrt {d x} a\right ) - 4 \, \sqrt {d x} {\left ({\rm Li}_2\left (a x^{2}\right ) - 4 \, \log \left (-a x^{2} + 1\right )\right )} - \sqrt {d x} {\rm polylog}\left (3, a x^{2}\right )\right )}}{d^{2} x} \]

input
integrate(polylog(3,a*x^2)/(d*x)^(3/2),x, algorithm="fricas")
 
output
2*(16*d^2*x*(a/d^6)^(1/4)*log(32768*d^5*(a/d^6)^(3/4) + 32768*sqrt(d*x)*a) 
 - 16*I*d^2*x*(a/d^6)^(1/4)*log(32768*I*d^5*(a/d^6)^(3/4) + 32768*sqrt(d*x 
)*a) + 16*I*d^2*x*(a/d^6)^(1/4)*log(-32768*I*d^5*(a/d^6)^(3/4) + 32768*sqr 
t(d*x)*a) - 16*d^2*x*(a/d^6)^(1/4)*log(-32768*d^5*(a/d^6)^(3/4) + 32768*sq 
rt(d*x)*a) - 4*sqrt(d*x)*(dilog(a*x^2) - 4*log(-a*x^2 + 1)) - sqrt(d*x)*po 
lylog(3, a*x^2))/(d^2*x)
 
3.1.82.6 Sympy [F]

\[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{3/2}} \, dx=\int \frac {\operatorname {Li}_{3}\left (a x^{2}\right )}{\left (d x\right )^{\frac {3}{2}}}\, dx \]

input
integrate(polylog(3,a*x**2)/(d*x)**(3/2),x)
 
output
Integral(polylog(3, a*x**2)/(d*x)**(3/2), x)
 
3.1.82.7 Maxima [A] (verification not implemented)

Time = 0.27 (sec) , antiderivative size = 132, normalized size of antiderivative = 1.08 \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{3/2}} \, dx=-\frac {2 \, {\left (16 \, a {\left (\frac {2 \, \arctan \left (\frac {\sqrt {d x} \sqrt {a}}{\sqrt {\sqrt {a} d}}\right )}{\sqrt {\sqrt {a} d} \sqrt {a}} + \frac {\log \left (\frac {\sqrt {d x} \sqrt {a} - \sqrt {\sqrt {a} d}}{\sqrt {d x} \sqrt {a} + \sqrt {\sqrt {a} d}}\right )}{\sqrt {\sqrt {a} d} \sqrt {a}}\right )} + \frac {4 \, {\rm Li}_2\left (a x^{2}\right ) - 16 \, \log \left (-a d^{2} x^{2} + d^{2}\right ) + 32 \, \log \left (d\right ) + {\rm Li}_{3}(a x^{2})}{\sqrt {d x}}\right )}}{d} \]

input
integrate(polylog(3,a*x^2)/(d*x)^(3/2),x, algorithm="maxima")
 
output
-2*(16*a*(2*arctan(sqrt(d*x)*sqrt(a)/sqrt(sqrt(a)*d))/(sqrt(sqrt(a)*d)*sqr 
t(a)) + log((sqrt(d*x)*sqrt(a) - sqrt(sqrt(a)*d))/(sqrt(d*x)*sqrt(a) + sqr 
t(sqrt(a)*d)))/(sqrt(sqrt(a)*d)*sqrt(a))) + (4*dilog(a*x^2) - 16*log(-a*d^ 
2*x^2 + d^2) + 32*log(d) + polylog(3, a*x^2))/sqrt(d*x))/d
 
3.1.82.8 Giac [F]

\[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{3/2}} \, dx=\int { \frac {{\rm Li}_{3}(a x^{2})}{\left (d x\right )^{\frac {3}{2}}} \,d x } \]

input
integrate(polylog(3,a*x^2)/(d*x)^(3/2),x, algorithm="giac")
 
output
integrate(polylog(3, a*x^2)/(d*x)^(3/2), x)
 
3.1.82.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{3/2}} \, dx=\int \frac {\mathrm {polylog}\left (3,a\,x^2\right )}{{\left (d\,x\right )}^{3/2}} \,d x \]

input
int(polylog(3, a*x^2)/(d*x)^(3/2),x)
 
output
int(polylog(3, a*x^2)/(d*x)^(3/2), x)