Integrand size = 15, antiderivative size = 132 \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{5/2}} \, dx=\frac {64 a^{3/4} \arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{27 d^{5/2}}+\frac {64 a^{3/4} \text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{27 d^{5/2}}+\frac {32 \log \left (1-a x^2\right )}{27 d (d x)^{3/2}}-\frac {8 \operatorname {PolyLog}\left (2,a x^2\right )}{9 d (d x)^{3/2}}-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}} \]
64/27*a^(3/4)*arctan(a^(1/4)*(d*x)^(1/2)/d^(1/2))/d^(5/2)+64/27*a^(3/4)*ar ctanh(a^(1/4)*(d*x)^(1/2)/d^(1/2))/d^(5/2)+32/27*ln(-a*x^2+1)/d/(d*x)^(3/2 )-8/9*polylog(2,a*x^2)/d/(d*x)^(3/2)-2/3*polylog(3,a*x^2)/d/(d*x)^(3/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.09 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.54 \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{5/2}} \, dx=\frac {x \operatorname {Gamma}\left (\frac {1}{4}\right ) \left (64 a x^2 \operatorname {Hypergeometric2F1}\left (\frac {1}{4},1,\frac {5}{4},a x^2\right )+16 \log \left (1-a x^2\right )-12 \operatorname {PolyLog}\left (2,a x^2\right )-9 \operatorname {PolyLog}\left (3,a x^2\right )\right )}{54 (d x)^{5/2} \operatorname {Gamma}\left (\frac {5}{4}\right )} \]
(x*Gamma[1/4]*(64*a*x^2*Hypergeometric2F1[1/4, 1, 5/4, a*x^2] + 16*Log[1 - a*x^2] - 12*PolyLog[2, a*x^2] - 9*PolyLog[3, a*x^2]))/(54*(d*x)^(5/2)*Gam ma[5/4])
Time = 0.38 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.14, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {7145, 7145, 25, 2905, 8, 266, 756, 218, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{5/2}} \, dx\) |
| \(\Big \downarrow \) 7145 |
| \(\displaystyle \frac {4}{3} \int \frac {\operatorname {PolyLog}\left (2,a x^2\right )}{(d x)^{5/2}}dx-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
| \(\Big \downarrow \) 7145 |
| \(\displaystyle \frac {4}{3} \left (\frac {4}{3} \int -\frac {\log \left (1-a x^2\right )}{(d x)^{5/2}}dx-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {4}{3} \left (-\frac {4}{3} \int \frac {\log \left (1-a x^2\right )}{(d x)^{5/2}}dx-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
| \(\Big \downarrow \) 2905 |
| \(\displaystyle \frac {4}{3} \left (-\frac {4}{3} \left (-\frac {4 a \int \frac {x}{(d x)^{3/2} \left (1-a x^2\right )}dx}{3 d}-\frac {2 \log \left (1-a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
| \(\Big \downarrow \) 8 |
| \(\displaystyle \frac {4}{3} \left (-\frac {4}{3} \left (-\frac {4 a \int \frac {1}{\sqrt {d x} \left (1-a x^2\right )}dx}{3 d^2}-\frac {2 \log \left (1-a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
| \(\Big \downarrow \) 266 |
| \(\displaystyle \frac {4}{3} \left (-\frac {4}{3} \left (-\frac {8 a \int \frac {1}{1-a x^2}d\sqrt {d x}}{3 d^3}-\frac {2 \log \left (1-a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
| \(\Big \downarrow \) 756 |
| \(\displaystyle \frac {4}{3} \left (-\frac {4}{3} \left (-\frac {8 a \left (\frac {1}{2} d \int \frac {1}{d-\sqrt {a} d x}d\sqrt {d x}+\frac {1}{2} d \int \frac {1}{\sqrt {a} x d+d}d\sqrt {d x}\right )}{3 d^3}-\frac {2 \log \left (1-a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
| \(\Big \downarrow \) 218 |
| \(\displaystyle \frac {4}{3} \left (-\frac {4}{3} \left (-\frac {8 a \left (\frac {1}{2} d \int \frac {1}{d-\sqrt {a} d x}d\sqrt {d x}+\frac {\sqrt {d} \arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{a}}\right )}{3 d^3}-\frac {2 \log \left (1-a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
| \(\Big \downarrow \) 221 |
| \(\displaystyle \frac {4}{3} \left (-\frac {4}{3} \left (-\frac {8 a \left (\frac {\sqrt {d} \arctan \left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{a}}+\frac {\sqrt {d} \text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{a}}\right )}{3 d^3}-\frac {2 \log \left (1-a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^2\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (3,a x^2\right )}{3 d (d x)^{3/2}}\) |
(4*((-4*((-8*a*((Sqrt[d]*ArcTan[(a^(1/4)*Sqrt[d*x])/Sqrt[d]])/(2*a^(1/4)) + (Sqrt[d]*ArcTanh[(a^(1/4)*Sqrt[d*x])/Sqrt[d]])/(2*a^(1/4))))/(3*d^3) - ( 2*Log[1 - a*x^2])/(3*d*(d*x)^(3/2))))/3 - (2*PolyLog[2, a*x^2])/(3*d*(d*x) ^(3/2))))/3 - (2*PolyLog[3, a*x^2])/(3*d*(d*x)^(3/2))
3.1.83.3.1 Defintions of rubi rules used
Int[(u_.)*(x_)^(m_.)*((a_.)*(x_))^(p_), x_Symbol] :> Simp[1/a^m Int[u*(a* x)^(m + p), x], x] /; FreeQ[{a, m, p}, x] && IntegerQ[m]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2 ]], s = Denominator[Rt[-a/b, 2]]}, Simp[r/(2*a) Int[1/(r - s*x^2), x], x] + Simp[r/(2*a) Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] && !GtQ[a /b, 0]
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))*((f_.)*(x_))^ (m_.), x_Symbol] :> Simp[(f*x)^(m + 1)*((a + b*Log[c*(d + e*x^n)^p])/(f*(m + 1))), x] - Simp[b*e*n*(p/(f*(m + 1))) Int[x^(n - 1)*((f*x)^(m + 1)/(d + e*x^n)), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && NeQ[m, -1]
Int[((d_.)*(x_))^(m_.)*PolyLog[n_, (a_.)*((b_.)*(x_)^(p_.))^(q_.)], x_Symbo l] :> Simp[(d*x)^(m + 1)*(PolyLog[n, a*(b*x^p)^q]/(d*(m + 1))), x] - Simp[p *(q/(m + 1)) Int[(d*x)^m*PolyLog[n - 1, a*(b*x^p)^q], x], x] /; FreeQ[{a, b, d, m, p, q}, x] && NeQ[m, -1] && GtQ[n, 0]
Time = 0.28 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.99
| method | result | size |
| meijerg | \(-\frac {x^{\frac {5}{2}} \left (-a \right )^{\frac {3}{4}} \left (-\frac {64 \sqrt {x}\, \left (-a \right )^{\frac {1}{4}} \left (\ln \left (1-\left (a \,x^{2}\right )^{\frac {1}{4}}\right )-\ln \left (1+\left (a \,x^{2}\right )^{\frac {1}{4}}\right )-2 \arctan \left (\left (a \,x^{2}\right )^{\frac {1}{4}}\right )\right )}{27 \left (a \,x^{2}\right )^{\frac {1}{4}}}+\frac {64 \left (-a \right )^{\frac {1}{4}} \ln \left (-a \,x^{2}+1\right )}{27 x^{\frac {3}{2}} a}-\frac {16 \left (-a \right )^{\frac {1}{4}} \operatorname {polylog}\left (2, a \,x^{2}\right )}{9 x^{\frac {3}{2}} a}-\frac {4 \left (-a \right )^{\frac {1}{4}} \operatorname {polylog}\left (3, a \,x^{2}\right )}{3 x^{\frac {3}{2}} a}\right )}{2 \left (d x \right )^{\frac {5}{2}}}\) | \(131\) |
-1/2/(d*x)^(5/2)*x^(5/2)*(-a)^(3/4)*(-64/27*x^(1/2)*(-a)^(1/4)/(a*x^2)^(1/ 4)*(ln(1-(a*x^2)^(1/4))-ln(1+(a*x^2)^(1/4))-2*arctan((a*x^2)^(1/4)))+64/27 /x^(3/2)*(-a)^(1/4)*ln(-a*x^2+1)/a-16/9/x^(3/2)*(-a)^(1/4)/a*polylog(2,a*x ^2)-4/3/x^(3/2)*(-a)^(1/4)/a*polylog(3,a*x^2))
Result contains complex when optimal does not.
Time = 0.28 (sec) , antiderivative size = 214, normalized size of antiderivative = 1.62 \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{5/2}} \, dx=\frac {2 \, {\left (16 \, d^{3} x^{2} \left (\frac {a^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (32 \, d^{3} \left (\frac {a^{3}}{d^{10}}\right )^{\frac {1}{4}} + 32 \, \sqrt {d x} a\right ) + 16 i \, d^{3} x^{2} \left (\frac {a^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (32 i \, d^{3} \left (\frac {a^{3}}{d^{10}}\right )^{\frac {1}{4}} + 32 \, \sqrt {d x} a\right ) - 16 i \, d^{3} x^{2} \left (\frac {a^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (-32 i \, d^{3} \left (\frac {a^{3}}{d^{10}}\right )^{\frac {1}{4}} + 32 \, \sqrt {d x} a\right ) - 16 \, d^{3} x^{2} \left (\frac {a^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (-32 \, d^{3} \left (\frac {a^{3}}{d^{10}}\right )^{\frac {1}{4}} + 32 \, \sqrt {d x} a\right ) - 4 \, \sqrt {d x} {\left (3 \, {\rm Li}_2\left (a x^{2}\right ) - 4 \, \log \left (-a x^{2} + 1\right )\right )} - 9 \, \sqrt {d x} {\rm polylog}\left (3, a x^{2}\right )\right )}}{27 \, d^{3} x^{2}} \]
2/27*(16*d^3*x^2*(a^3/d^10)^(1/4)*log(32*d^3*(a^3/d^10)^(1/4) + 32*sqrt(d* x)*a) + 16*I*d^3*x^2*(a^3/d^10)^(1/4)*log(32*I*d^3*(a^3/d^10)^(1/4) + 32*s qrt(d*x)*a) - 16*I*d^3*x^2*(a^3/d^10)^(1/4)*log(-32*I*d^3*(a^3/d^10)^(1/4) + 32*sqrt(d*x)*a) - 16*d^3*x^2*(a^3/d^10)^(1/4)*log(-32*d^3*(a^3/d^10)^(1 /4) + 32*sqrt(d*x)*a) - 4*sqrt(d*x)*(3*dilog(a*x^2) - 4*log(-a*x^2 + 1)) - 9*sqrt(d*x)*polylog(3, a*x^2))/(d^3*x^2)
\[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{5/2}} \, dx=\int \frac {\operatorname {Li}_{3}\left (a x^{2}\right )}{\left (d x\right )^{\frac {5}{2}}}\, dx \]
Time = 0.28 (sec) , antiderivative size = 134, normalized size of antiderivative = 1.02 \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{5/2}} \, dx=\frac {2 \, {\left (\frac {32 \, a \arctan \left (\frac {\sqrt {d x} \sqrt {a}}{\sqrt {\sqrt {a} d}}\right )}{\sqrt {\sqrt {a} d} d} - \frac {16 \, a \log \left (\frac {\sqrt {d x} \sqrt {a} - \sqrt {\sqrt {a} d}}{\sqrt {d x} \sqrt {a} + \sqrt {\sqrt {a} d}}\right )}{\sqrt {\sqrt {a} d} d} - \frac {12 \, {\rm Li}_2\left (a x^{2}\right ) - 16 \, \log \left (-a d^{2} x^{2} + d^{2}\right ) + 32 \, \log \left (d\right ) + 9 \, {\rm Li}_{3}(a x^{2})}{\left (d x\right )^{\frac {3}{2}}}\right )}}{27 \, d} \]
2/27*(32*a*arctan(sqrt(d*x)*sqrt(a)/sqrt(sqrt(a)*d))/(sqrt(sqrt(a)*d)*d) - 16*a*log((sqrt(d*x)*sqrt(a) - sqrt(sqrt(a)*d))/(sqrt(d*x)*sqrt(a) + sqrt( sqrt(a)*d)))/(sqrt(sqrt(a)*d)*d) - (12*dilog(a*x^2) - 16*log(-a*d^2*x^2 + d^2) + 32*log(d) + 9*polylog(3, a*x^2))/(d*x)^(3/2))/d
\[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{5/2}} \, dx=\int { \frac {{\rm Li}_{3}(a x^{2})}{\left (d x\right )^{\frac {5}{2}}} \,d x } \]
Timed out. \[ \int \frac {\operatorname {PolyLog}\left (3,a x^2\right )}{(d x)^{5/2}} \, dx=\int \frac {\mathrm {polylog}\left (3,a\,x^2\right )}{{\left (d\,x\right )}^{5/2}} \,d x \]