Integrand size = 125, antiderivative size = 27 \[ \int \frac {-7500+e^{4 x}+4600 x+2600 x^2-19900 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (-300+100 x+2 x^2+50 x^4\right )}{2500+e^{4 x}+5000 x+2600 x^2+100 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (100+100 x+2 x^2+50 x^4\right )} \, dx=x+\frac {8}{2+2 x+x^4+\frac {1}{25} \left (e^{2 x}+x^2\right )} \] Output:
4/(x+1+1/2*x^4+1/50*x^2+1/50*exp(x)^2)+x
Time = 2.70 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.70 \[ \int \frac {-7500+e^{4 x}+4600 x+2600 x^2-19900 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (-300+100 x+2 x^2+50 x^4\right )}{2500+e^{4 x}+5000 x+2600 x^2+100 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (100+100 x+2 x^2+50 x^4\right )} \, dx=\frac {200+50 x+e^{2 x} x+50 x^2+x^3+25 x^5}{50+e^{2 x}+50 x+x^2+25 x^4} \] Input:
Integrate[(-7500 + E^(4*x) + 4600*x + 2600*x^2 - 19900*x^3 + 2501*x^4 + 25 00*x^5 + 50*x^6 + 625*x^8 + E^(2*x)*(-300 + 100*x + 2*x^2 + 50*x^4))/(2500 + E^(4*x) + 5000*x + 2600*x^2 + 100*x^3 + 2501*x^4 + 2500*x^5 + 50*x^6 + 625*x^8 + E^(2*x)*(100 + 100*x + 2*x^2 + 50*x^4)),x]
Output:
(200 + 50*x + E^(2*x)*x + 50*x^2 + x^3 + 25*x^5)/(50 + E^(2*x) + 50*x + x^ 2 + 25*x^4)
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {625 x^8+50 x^6+2500 x^5+2501 x^4-19900 x^3+2600 x^2+e^{2 x} \left (50 x^4+2 x^2+100 x-300\right )+4600 x+e^{4 x}-7500}{625 x^8+50 x^6+2500 x^5+2501 x^4+100 x^3+2600 x^2+e^{2 x} \left (50 x^4+2 x^2+100 x+100\right )+5000 x+e^{4 x}+2500} \, dx\) |
\(\Big \downarrow \) 7292 |
\(\displaystyle \int \frac {625 x^8+50 x^6+2500 x^5+2501 x^4-19900 x^3+2600 x^2+e^{2 x} \left (50 x^4+2 x^2+100 x-300\right )+4600 x+e^{4 x}-7500}{\left (25 x^4+x^2+50 x+e^{2 x}+50\right )^2}dx\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \int \left (-\frac {400}{25 x^4+x^2+50 x+e^{2 x}+50}+\frac {400 \left (25 x^4-50 x^3+x^2+49 x+25\right )}{\left (25 x^4+x^2+50 x+e^{2 x}+50\right )^2}+1\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle 10000 \int \frac {1}{\left (25 x^4+x^2+50 x+e^{2 x}+50\right )^2}dx+19600 \int \frac {x}{\left (25 x^4+x^2+50 x+e^{2 x}+50\right )^2}dx+400 \int \frac {x^2}{\left (25 x^4+x^2+50 x+e^{2 x}+50\right )^2}dx+10000 \int \frac {x^4}{\left (25 x^4+x^2+50 x+e^{2 x}+50\right )^2}dx-400 \int \frac {1}{25 x^4+x^2+50 x+e^{2 x}+50}dx-20000 \int \frac {x^3}{\left (25 x^4+x^2+50 x+e^{2 x}+50\right )^2}dx+x\) |
Input:
Int[(-7500 + E^(4*x) + 4600*x + 2600*x^2 - 19900*x^3 + 2501*x^4 + 2500*x^5 + 50*x^6 + 625*x^8 + E^(2*x)*(-300 + 100*x + 2*x^2 + 50*x^4))/(2500 + E^( 4*x) + 5000*x + 2600*x^2 + 100*x^3 + 2501*x^4 + 2500*x^5 + 50*x^6 + 625*x^ 8 + E^(2*x)*(100 + 100*x + 2*x^2 + 50*x^4)),x]
Output:
$Aborted
Time = 0.60 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.89
method | result | size |
risch | \(x +\frac {200}{25 x^{4}+{\mathrm e}^{2 x}+x^{2}+50 x +50}\) | \(24\) |
parallelrisch | \(\frac {25 x^{5}+x^{3}+x \,{\mathrm e}^{2 x}+50 x^{2}+50 x +200}{25 x^{4}+{\mathrm e}^{2 x}+x^{2}+50 x +50}\) | \(45\) |
Input:
int((exp(x)^4+(50*x^4+2*x^2+100*x-300)*exp(x)^2+625*x^8+50*x^6+2500*x^5+25 01*x^4-19900*x^3+2600*x^2+4600*x-7500)/(exp(x)^4+(50*x^4+2*x^2+100*x+100)* exp(x)^2+625*x^8+50*x^6+2500*x^5+2501*x^4+100*x^3+2600*x^2+5000*x+2500),x, method=_RETURNVERBOSE)
Output:
x+200/(25*x^4+exp(2*x)+x^2+50*x+50)
Time = 0.09 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.63 \[ \int \frac {-7500+e^{4 x}+4600 x+2600 x^2-19900 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (-300+100 x+2 x^2+50 x^4\right )}{2500+e^{4 x}+5000 x+2600 x^2+100 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (100+100 x+2 x^2+50 x^4\right )} \, dx=\frac {25 \, x^{5} + x^{3} + 50 \, x^{2} + x e^{\left (2 \, x\right )} + 50 \, x + 200}{25 \, x^{4} + x^{2} + 50 \, x + e^{\left (2 \, x\right )} + 50} \] Input:
integrate((exp(x)^4+(50*x^4+2*x^2+100*x-300)*exp(x)^2+625*x^8+50*x^6+2500* x^5+2501*x^4-19900*x^3+2600*x^2+4600*x-7500)/(exp(x)^4+(50*x^4+2*x^2+100*x +100)*exp(x)^2+625*x^8+50*x^6+2500*x^5+2501*x^4+100*x^3+2600*x^2+5000*x+25 00),x, algorithm="fricas")
Output:
(25*x^5 + x^3 + 50*x^2 + x*e^(2*x) + 50*x + 200)/(25*x^4 + x^2 + 50*x + e^ (2*x) + 50)
Time = 0.07 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.74 \[ \int \frac {-7500+e^{4 x}+4600 x+2600 x^2-19900 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (-300+100 x+2 x^2+50 x^4\right )}{2500+e^{4 x}+5000 x+2600 x^2+100 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (100+100 x+2 x^2+50 x^4\right )} \, dx=x + \frac {200}{25 x^{4} + x^{2} + 50 x + e^{2 x} + 50} \] Input:
integrate((exp(x)**4+(50*x**4+2*x**2+100*x-300)*exp(x)**2+625*x**8+50*x**6 +2500*x**5+2501*x**4-19900*x**3+2600*x**2+4600*x-7500)/(exp(x)**4+(50*x**4 +2*x**2+100*x+100)*exp(x)**2+625*x**8+50*x**6+2500*x**5+2501*x**4+100*x**3 +2600*x**2+5000*x+2500),x)
Output:
x + 200/(25*x**4 + x**2 + 50*x + exp(2*x) + 50)
Time = 0.08 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.63 \[ \int \frac {-7500+e^{4 x}+4600 x+2600 x^2-19900 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (-300+100 x+2 x^2+50 x^4\right )}{2500+e^{4 x}+5000 x+2600 x^2+100 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (100+100 x+2 x^2+50 x^4\right )} \, dx=\frac {25 \, x^{5} + x^{3} + 50 \, x^{2} + x e^{\left (2 \, x\right )} + 50 \, x + 200}{25 \, x^{4} + x^{2} + 50 \, x + e^{\left (2 \, x\right )} + 50} \] Input:
integrate((exp(x)^4+(50*x^4+2*x^2+100*x-300)*exp(x)^2+625*x^8+50*x^6+2500* x^5+2501*x^4-19900*x^3+2600*x^2+4600*x-7500)/(exp(x)^4+(50*x^4+2*x^2+100*x +100)*exp(x)^2+625*x^8+50*x^6+2500*x^5+2501*x^4+100*x^3+2600*x^2+5000*x+25 00),x, algorithm="maxima")
Output:
(25*x^5 + x^3 + 50*x^2 + x*e^(2*x) + 50*x + 200)/(25*x^4 + x^2 + 50*x + e^ (2*x) + 50)
Time = 0.12 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.63 \[ \int \frac {-7500+e^{4 x}+4600 x+2600 x^2-19900 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (-300+100 x+2 x^2+50 x^4\right )}{2500+e^{4 x}+5000 x+2600 x^2+100 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (100+100 x+2 x^2+50 x^4\right )} \, dx=\frac {25 \, x^{5} + x^{3} + 50 \, x^{2} + x e^{\left (2 \, x\right )} + 50 \, x + 200}{25 \, x^{4} + x^{2} + 50 \, x + e^{\left (2 \, x\right )} + 50} \] Input:
integrate((exp(x)^4+(50*x^4+2*x^2+100*x-300)*exp(x)^2+625*x^8+50*x^6+2500* x^5+2501*x^4-19900*x^3+2600*x^2+4600*x-7500)/(exp(x)^4+(50*x^4+2*x^2+100*x +100)*exp(x)^2+625*x^8+50*x^6+2500*x^5+2501*x^4+100*x^3+2600*x^2+5000*x+25 00),x, algorithm="giac")
Output:
(25*x^5 + x^3 + 50*x^2 + x*e^(2*x) + 50*x + 200)/(25*x^4 + x^2 + 50*x + e^ (2*x) + 50)
Time = 8.21 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.85 \[ \int \frac {-7500+e^{4 x}+4600 x+2600 x^2-19900 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (-300+100 x+2 x^2+50 x^4\right )}{2500+e^{4 x}+5000 x+2600 x^2+100 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (100+100 x+2 x^2+50 x^4\right )} \, dx=x+\frac {200}{50\,x+{\mathrm {e}}^{2\,x}+x^2+25\,x^4+50} \] Input:
int((4600*x + exp(4*x) + exp(2*x)*(100*x + 2*x^2 + 50*x^4 - 300) + 2600*x^ 2 - 19900*x^3 + 2501*x^4 + 2500*x^5 + 50*x^6 + 625*x^8 - 7500)/(5000*x + e xp(4*x) + exp(2*x)*(100*x + 2*x^2 + 50*x^4 + 100) + 2600*x^2 + 100*x^3 + 2 501*x^4 + 2500*x^5 + 50*x^6 + 625*x^8 + 2500),x)
Output:
x + 200/(50*x + exp(2*x) + x^2 + 25*x^4 + 50)
\[ \int \frac {-7500+e^{4 x}+4600 x+2600 x^2-19900 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (-300+100 x+2 x^2+50 x^4\right )}{2500+e^{4 x}+5000 x+2600 x^2+100 x^3+2501 x^4+2500 x^5+50 x^6+625 x^8+e^{2 x} \left (100+100 x+2 x^2+50 x^4\right )} \, dx =\text {Too large to display} \] Input:
int((exp(x)^4+(50*x^4+2*x^2+100*x-300)*exp(x)^2+625*x^8+50*x^6+2500*x^5+25 01*x^4-19900*x^3+2600*x^2+4600*x-7500)/(exp(x)^4+(50*x^4+2*x^2+100*x+100)* exp(x)^2+625*x^8+50*x^6+2500*x^5+2501*x^4+100*x^3+2600*x^2+5000*x+2500),x)
Output:
int(e**(4*x)/(e**(4*x) + 50*e**(2*x)*x**4 + 2*e**(2*x)*x**2 + 100*e**(2*x) *x + 100*e**(2*x) + 625*x**8 + 50*x**6 + 2500*x**5 + 2501*x**4 + 100*x**3 + 2600*x**2 + 5000*x + 2500),x) - 300*int(e**(2*x)/(e**(4*x) + 50*e**(2*x) *x**4 + 2*e**(2*x)*x**2 + 100*e**(2*x)*x + 100*e**(2*x) + 625*x**8 + 50*x* *6 + 2500*x**5 + 2501*x**4 + 100*x**3 + 2600*x**2 + 5000*x + 2500),x) + 62 5*int(x**8/(e**(4*x) + 50*e**(2*x)*x**4 + 2*e**(2*x)*x**2 + 100*e**(2*x)*x + 100*e**(2*x) + 625*x**8 + 50*x**6 + 2500*x**5 + 2501*x**4 + 100*x**3 + 2600*x**2 + 5000*x + 2500),x) + 50*int(x**6/(e**(4*x) + 50*e**(2*x)*x**4 + 2*e**(2*x)*x**2 + 100*e**(2*x)*x + 100*e**(2*x) + 625*x**8 + 50*x**6 + 25 00*x**5 + 2501*x**4 + 100*x**3 + 2600*x**2 + 5000*x + 2500),x) + 2500*int( x**5/(e**(4*x) + 50*e**(2*x)*x**4 + 2*e**(2*x)*x**2 + 100*e**(2*x)*x + 100 *e**(2*x) + 625*x**8 + 50*x**6 + 2500*x**5 + 2501*x**4 + 100*x**3 + 2600*x **2 + 5000*x + 2500),x) + 2501*int(x**4/(e**(4*x) + 50*e**(2*x)*x**4 + 2*e **(2*x)*x**2 + 100*e**(2*x)*x + 100*e**(2*x) + 625*x**8 + 50*x**6 + 2500*x **5 + 2501*x**4 + 100*x**3 + 2600*x**2 + 5000*x + 2500),x) - 19900*int(x** 3/(e**(4*x) + 50*e**(2*x)*x**4 + 2*e**(2*x)*x**2 + 100*e**(2*x)*x + 100*e* *(2*x) + 625*x**8 + 50*x**6 + 2500*x**5 + 2501*x**4 + 100*x**3 + 2600*x**2 + 5000*x + 2500),x) + 2600*int(x**2/(e**(4*x) + 50*e**(2*x)*x**4 + 2*e**( 2*x)*x**2 + 100*e**(2*x)*x + 100*e**(2*x) + 625*x**8 + 50*x**6 + 2500*x**5 + 2501*x**4 + 100*x**3 + 2600*x**2 + 5000*x + 2500),x) + 50*int((e**(2...