Integrand size = 20, antiderivative size = 81 \[ \int (b x)^m (c+d x)^n (e+f x)^p \, dx=\frac {(b x)^{1+m} (c+d x)^n \left (1+\frac {d x}{c}\right )^{-n} (e+f x)^p \left (1+\frac {f x}{e}\right )^{-p} \operatorname {AppellF1}\left (1+m,-n,-p,2+m,-\frac {d x}{c},-\frac {f x}{e}\right )}{b (1+m)} \] Output:
(b*x)^(1+m)*(d*x+c)^n*(f*x+e)^p*AppellF1(1+m,-n,-p,2+m,-d*x/c,-f*x/e)/b/(1 +m)/((1+d*x/c)^n)/((1+f*x/e)^p)
Time = 0.15 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.98 \[ \int (b x)^m (c+d x)^n (e+f x)^p \, dx=\frac {x (b x)^m (c+d x)^n \left (\frac {c+d x}{c}\right )^{-n} (e+f x)^p \left (\frac {e+f x}{e}\right )^{-p} \operatorname {AppellF1}\left (1+m,-n,-p,2+m,-\frac {d x}{c},-\frac {f x}{e}\right )}{1+m} \] Input:
Integrate[(b*x)^m*(c + d*x)^n*(e + f*x)^p,x]
Output:
(x*(b*x)^m*(c + d*x)^n*(e + f*x)^p*AppellF1[1 + m, -n, -p, 2 + m, -((d*x)/ c), -((f*x)/e)])/((1 + m)*((c + d*x)/c)^n*((e + f*x)/e)^p)
Time = 0.25 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {152, 152, 150}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (b x)^m (c+d x)^n (e+f x)^p \, dx\) |
\(\Big \downarrow \) 152 |
\(\displaystyle (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} \int (b x)^m \left (\frac {d x}{c}+1\right )^n (e+f x)^pdx\) |
\(\Big \downarrow \) 152 |
\(\displaystyle (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} (e+f x)^p \left (\frac {f x}{e}+1\right )^{-p} \int (b x)^m \left (\frac {d x}{c}+1\right )^n \left (\frac {f x}{e}+1\right )^pdx\) |
\(\Big \downarrow \) 150 |
\(\displaystyle \frac {(b x)^{m+1} (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} (e+f x)^p \left (\frac {f x}{e}+1\right )^{-p} \operatorname {AppellF1}\left (m+1,-n,-p,m+2,-\frac {d x}{c},-\frac {f x}{e}\right )}{b (m+1)}\) |
Input:
Int[(b*x)^m*(c + d*x)^n*(e + f*x)^p,x]
Output:
((b*x)^(1 + m)*(c + d*x)^n*(e + f*x)^p*AppellF1[1 + m, -n, -p, 2 + m, -((d *x)/c), -((f*x)/e)])/(b*(1 + m)*(1 + (d*x)/c)^n*(1 + (f*x)/e)^p)
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ ] :> Simp[c^n*e^p*((b*x)^(m + 1)/(b*(m + 1)))*AppellF1[m + 1, -n, -p, m + 2 , (-d)*(x/c), (-f)*(x/e)], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] && !In tegerQ[m] && !IntegerQ[n] && GtQ[c, 0] && (IntegerQ[p] || GtQ[e, 0])
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ ] :> Simp[c^IntPart[n]*((c + d*x)^FracPart[n]/(1 + d*(x/c))^FracPart[n]) Int[(b*x)^m*(1 + d*(x/c))^n*(e + f*x)^p, x], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] && !IntegerQ[m] && !IntegerQ[n] && !GtQ[c, 0]
\[\int \left (b x \right )^{m} \left (x d +c \right )^{n} \left (f x +e \right )^{p}d x\]
Input:
int((b*x)^m*(d*x+c)^n*(f*x+e)^p,x)
Output:
int((b*x)^m*(d*x+c)^n*(f*x+e)^p,x)
\[ \int (b x)^m (c+d x)^n (e+f x)^p \, dx=\int { \left (b x\right )^{m} {\left (d x + c\right )}^{n} {\left (f x + e\right )}^{p} \,d x } \] Input:
integrate((b*x)^m*(d*x+c)^n*(f*x+e)^p,x, algorithm="fricas")
Output:
integral((b*x)^m*(d*x + c)^n*(f*x + e)^p, x)
Timed out. \[ \int (b x)^m (c+d x)^n (e+f x)^p \, dx=\text {Timed out} \] Input:
integrate((b*x)**m*(d*x+c)**n*(f*x+e)**p,x)
Output:
Timed out
\[ \int (b x)^m (c+d x)^n (e+f x)^p \, dx=\int { \left (b x\right )^{m} {\left (d x + c\right )}^{n} {\left (f x + e\right )}^{p} \,d x } \] Input:
integrate((b*x)^m*(d*x+c)^n*(f*x+e)^p,x, algorithm="maxima")
Output:
integrate((b*x)^m*(d*x + c)^n*(f*x + e)^p, x)
\[ \int (b x)^m (c+d x)^n (e+f x)^p \, dx=\int { \left (b x\right )^{m} {\left (d x + c\right )}^{n} {\left (f x + e\right )}^{p} \,d x } \] Input:
integrate((b*x)^m*(d*x+c)^n*(f*x+e)^p,x, algorithm="giac")
Output:
integrate((b*x)^m*(d*x + c)^n*(f*x + e)^p, x)
Timed out. \[ \int (b x)^m (c+d x)^n (e+f x)^p \, dx=\int {\left (e+f\,x\right )}^p\,{\left (b\,x\right )}^m\,{\left (c+d\,x\right )}^n \,d x \] Input:
int((e + f*x)^p*(b*x)^m*(c + d*x)^n,x)
Output:
int((e + f*x)^p*(b*x)^m*(c + d*x)^n, x)
\[ \int (b x)^m (c+d x)^n (e+f x)^p \, dx=\text {too large to display} \] Input:
int((b*x)^m*(d*x+c)^n*(f*x+e)^p,x)
Output:
(b**m*(x**m*(e + f*x)**p*(c + d*x)**n*c*e*n + x**m*(e + f*x)**p*(c + d*x)* *n*c*e*p + x**m*(e + f*x)**p*(c + d*x)**n*c*f*m*x + x**m*(e + f*x)**p*(c + d*x)**n*c*f*p*x + x**m*(e + f*x)**p*(c + d*x)**n*d*e*m*x + x**m*(e + f*x) **p*(c + d*x)**n*d*e*n*x + int((x**m*(e + f*x)**p*(c + d*x)**n*x)/(c**2*e* f*m**2 + c**2*e*f*m*n + 2*c**2*e*f*m*p + c**2*e*f*m + c**2*e*f*n*p + c**2* e*f*p**2 + c**2*e*f*p + c**2*f**2*m**2*x + c**2*f**2*m*n*x + 2*c**2*f**2*m *p*x + c**2*f**2*m*x + c**2*f**2*n*p*x + c**2*f**2*p**2*x + c**2*f**2*p*x + c*d*e**2*m**2 + 2*c*d*e**2*m*n + c*d*e**2*m*p + c*d*e**2*m + c*d*e**2*n* *2 + c*d*e**2*n*p + c*d*e**2*n + 2*c*d*e*f*m**2*x + 3*c*d*e*f*m*n*x + 3*c* d*e*f*m*p*x + 2*c*d*e*f*m*x + c*d*e*f*n**2*x + 2*c*d*e*f*n*p*x + c*d*e*f*n *x + c*d*e*f*p**2*x + c*d*e*f*p*x + c*d*f**2*m**2*x**2 + c*d*f**2*m*n*x**2 + 2*c*d*f**2*m*p*x**2 + c*d*f**2*m*x**2 + c*d*f**2*n*p*x**2 + c*d*f**2*p* *2*x**2 + c*d*f**2*p*x**2 + d**2*e**2*m**2*x + 2*d**2*e**2*m*n*x + d**2*e* *2*m*p*x + d**2*e**2*m*x + d**2*e**2*n**2*x + d**2*e**2*n*p*x + d**2*e**2* n*x + d**2*e*f*m**2*x**2 + 2*d**2*e*f*m*n*x**2 + d**2*e*f*m*p*x**2 + d**2* e*f*m*x**2 + d**2*e*f*n**2*x**2 + d**2*e*f*n*p*x**2 + d**2*e*f*n*x**2),x)* c**3*f**3*m**3*n + int((x**m*(e + f*x)**p*(c + d*x)**n*x)/(c**2*e*f*m**2 + c**2*e*f*m*n + 2*c**2*e*f*m*p + c**2*e*f*m + c**2*e*f*n*p + c**2*e*f*p**2 + c**2*e*f*p + c**2*f**2*m**2*x + c**2*f**2*m*n*x + 2*c**2*f**2*m*p*x + c **2*f**2*m*x + c**2*f**2*n*p*x + c**2*f**2*p**2*x + c**2*f**2*p*x + c*d...