Integrand size = 26, antiderivative size = 82 \[ \int \frac {(c+d x)^q \left (a x^n+b x^{1+n}\right )^p}{x} \, dx=\frac {\left (1+\frac {b x}{a}\right )^{-p} (c+d x)^q \left (1+\frac {d x}{c}\right )^{-q} \left (a x^n+b x^{1+n}\right )^p \operatorname {AppellF1}\left (n p,-p,-q,1+n p,-\frac {b x}{a},-\frac {d x}{c}\right )}{n p} \] Output:
(d*x+c)^q*(a*x^n+b*x^(1+n))^p*AppellF1(n*p,-p,-q,n*p+1,-b*x/a,-d*x/c)/n/p/ ((1+b*x/a)^p)/((1+d*x/c)^q)
Time = 0.19 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.98 \[ \int \frac {(c+d x)^q \left (a x^n+b x^{1+n}\right )^p}{x} \, dx=\frac {\left (\frac {a+b x}{a}\right )^{-p} \left (x^n (a+b x)\right )^p (c+d x)^q \left (\frac {c+d x}{c}\right )^{-q} \operatorname {AppellF1}\left (n p,-p,-q,1+n p,-\frac {b x}{a},-\frac {d x}{c}\right )}{n p} \] Input:
Integrate[((c + d*x)^q*(a*x^n + b*x^(1 + n))^p)/x,x]
Output:
((x^n*(a + b*x))^p*(c + d*x)^q*AppellF1[n*p, -p, -q, 1 + n*p, -((b*x)/a), -((d*x)/c)])/(n*p*((a + b*x)/a)^p*((c + d*x)/c)^q)
Time = 0.39 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {1948, 152, 152, 150}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(c+d x)^q \left (a x^n+b x^{n+1}\right )^p}{x} \, dx\) |
\(\Big \downarrow \) 1948 |
\(\displaystyle x^{-n p} (a+b x)^{-p} \left (a x^n+b x^{n+1}\right )^p \int x^{n p-1} (a+b x)^p (c+d x)^qdx\) |
\(\Big \downarrow \) 152 |
\(\displaystyle x^{-n p} \left (\frac {b x}{a}+1\right )^{-p} \left (a x^n+b x^{n+1}\right )^p \int x^{n p-1} \left (\frac {b x}{a}+1\right )^p (c+d x)^qdx\) |
\(\Big \downarrow \) 152 |
\(\displaystyle x^{-n p} \left (\frac {b x}{a}+1\right )^{-p} (c+d x)^q \left (\frac {d x}{c}+1\right )^{-q} \left (a x^n+b x^{n+1}\right )^p \int x^{n p-1} \left (\frac {b x}{a}+1\right )^p \left (\frac {d x}{c}+1\right )^qdx\) |
\(\Big \downarrow \) 150 |
\(\displaystyle \frac {\left (\frac {b x}{a}+1\right )^{-p} (c+d x)^q \left (\frac {d x}{c}+1\right )^{-q} \left (a x^n+b x^{n+1}\right )^p \operatorname {AppellF1}\left (n p,-p,-q,n p+1,-\frac {b x}{a},-\frac {d x}{c}\right )}{n p}\) |
Input:
Int[((c + d*x)^q*(a*x^n + b*x^(1 + n))^p)/x,x]
Output:
((c + d*x)^q*(a*x^n + b*x^(1 + n))^p*AppellF1[n*p, -p, -q, 1 + n*p, -((b*x )/a), -((d*x)/c)])/(n*p*(1 + (b*x)/a)^p*(1 + (d*x)/c)^q)
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ ] :> Simp[c^n*e^p*((b*x)^(m + 1)/(b*(m + 1)))*AppellF1[m + 1, -n, -p, m + 2 , (-d)*(x/c), (-f)*(x/e)], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] && !In tegerQ[m] && !IntegerQ[n] && GtQ[c, 0] && (IntegerQ[p] || GtQ[e, 0])
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ ] :> Simp[c^IntPart[n]*((c + d*x)^FracPart[n]/(1 + d*(x/c))^FracPart[n]) Int[(b*x)^m*(1 + d*(x/c))^n*(e + f*x)^p, x], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] && !IntegerQ[m] && !IntegerQ[n] && !GtQ[c, 0]
Int[((e_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(jn_.))^(p_)*((c_) + (d_.)*(x_)^(n_.))^(q_.), x_Symbol] :> Simp[e^IntPart[m]*(e*x)^FracPart[m]*( (a*x^j + b*x^(j + n))^FracPart[p]/(x^(FracPart[m] + j*FracPart[p])*(a + b*x ^n)^FracPart[p])) Int[x^(m + j*p)*(a + b*x^n)^p*(c + d*x^n)^q, x], x] /; FreeQ[{a, b, c, d, e, j, m, n, p, q}, x] && EqQ[jn, j + n] && !IntegerQ[p] && NeQ[b*c - a*d, 0] && !(EqQ[n, 1] && EqQ[j, 1])
\[\int \frac {\left (d x +c \right )^{q} \left (a \,x^{n}+b \,x^{1+n}\right )^{p}}{x}d x\]
Input:
int((d*x+c)^q*(a*x^n+b*x^(1+n))^p/x,x)
Output:
int((d*x+c)^q*(a*x^n+b*x^(1+n))^p/x,x)
\[ \int \frac {(c+d x)^q \left (a x^n+b x^{1+n}\right )^p}{x} \, dx=\int { \frac {{\left (b x^{n + 1} + a x^{n}\right )}^{p} {\left (d x + c\right )}^{q}}{x} \,d x } \] Input:
integrate((d*x+c)^q*(a*x^n+b*x^(1+n))^p/x,x, algorithm="fricas")
Output:
integral((b*x^(n + 1) + a*x^n)^p*(d*x + c)^q/x, x)
Timed out. \[ \int \frac {(c+d x)^q \left (a x^n+b x^{1+n}\right )^p}{x} \, dx=\text {Timed out} \] Input:
integrate((d*x+c)**q*(a*x**n+b*x**(1+n))**p/x,x)
Output:
Timed out
\[ \int \frac {(c+d x)^q \left (a x^n+b x^{1+n}\right )^p}{x} \, dx=\int { \frac {{\left (b x^{n + 1} + a x^{n}\right )}^{p} {\left (d x + c\right )}^{q}}{x} \,d x } \] Input:
integrate((d*x+c)^q*(a*x^n+b*x^(1+n))^p/x,x, algorithm="maxima")
Output:
integrate((b*x^(n + 1) + a*x^n)^p*(d*x + c)^q/x, x)
\[ \int \frac {(c+d x)^q \left (a x^n+b x^{1+n}\right )^p}{x} \, dx=\int { \frac {{\left (b x^{n + 1} + a x^{n}\right )}^{p} {\left (d x + c\right )}^{q}}{x} \,d x } \] Input:
integrate((d*x+c)^q*(a*x^n+b*x^(1+n))^p/x,x, algorithm="giac")
Output:
integrate((b*x^(n + 1) + a*x^n)^p*(d*x + c)^q/x, x)
Timed out. \[ \int \frac {(c+d x)^q \left (a x^n+b x^{1+n}\right )^p}{x} \, dx=\int \frac {{\left (a\,x^n+b\,x^{n+1}\right )}^p\,{\left (c+d\,x\right )}^q}{x} \,d x \] Input:
int(((a*x^n + b*x^(n + 1))^p*(c + d*x)^q)/x,x)
Output:
int(((a*x^n + b*x^(n + 1))^p*(c + d*x)^q)/x, x)
\[ \int \frac {(c+d x)^q \left (a x^n+b x^{1+n}\right )^p}{x} \, dx=\text {too large to display} \] Input:
int((d*x+c)^q*(a*x^n+b*x^(1+n))^p/x,x)
Output:
((c + d*x)**q*(x**n*a + x**n*b*x)**p*a*d + (c + d*x)**q*(x**n*a + x**n*b*x )**p*b*c - int(((c + d*x)**q*(x**n*a + x**n*b*x)**p*x)/(a**2*c*d*n*p + a** 2*c*d*q + a**2*d**2*n*p*x + a**2*d**2*q*x + a*b*c**2*n*p + a*b*c**2*p + 2* a*b*c*d*n*p*x + a*b*c*d*p*x + a*b*c*d*q*x + a*b*d**2*n*p*x**2 + a*b*d**2*q *x**2 + b**2*c**2*n*p*x + b**2*c**2*p*x + b**2*c*d*n*p*x**2 + b**2*c*d*p*x **2),x)*a**2*b*d**3*n*p**2 - int(((c + d*x)**q*(x**n*a + x**n*b*x)**p*x)/( a**2*c*d*n*p + a**2*c*d*q + a**2*d**2*n*p*x + a**2*d**2*q*x + a*b*c**2*n*p + a*b*c**2*p + 2*a*b*c*d*n*p*x + a*b*c*d*p*x + a*b*c*d*q*x + a*b*d**2*n*p *x**2 + a*b*d**2*q*x**2 + b**2*c**2*n*p*x + b**2*c**2*p*x + b**2*c*d*n*p*x **2 + b**2*c*d*p*x**2),x)*a**2*b*d**3*p*q - int(((c + d*x)**q*(x**n*a + x* *n*b*x)**p*x)/(a**2*c*d*n*p + a**2*c*d*q + a**2*d**2*n*p*x + a**2*d**2*q*x + a*b*c**2*n*p + a*b*c**2*p + 2*a*b*c*d*n*p*x + a*b*c*d*p*x + a*b*c*d*q*x + a*b*d**2*n*p*x**2 + a*b*d**2*q*x**2 + b**2*c**2*n*p*x + b**2*c**2*p*x + b**2*c*d*n*p*x**2 + b**2*c*d*p*x**2),x)*a*b**2*c*d**2*n*p**2 - int(((c + d*x)**q*(x**n*a + x**n*b*x)**p*x)/(a**2*c*d*n*p + a**2*c*d*q + a**2*d**2*n *p*x + a**2*d**2*q*x + a*b*c**2*n*p + a*b*c**2*p + 2*a*b*c*d*n*p*x + a*b*c *d*p*x + a*b*c*d*q*x + a*b*d**2*n*p*x**2 + a*b*d**2*q*x**2 + b**2*c**2*n*p *x + b**2*c**2*p*x + b**2*c*d*n*p*x**2 + b**2*c*d*p*x**2),x)*a*b**2*c*d**2 *n*p*q - int(((c + d*x)**q*(x**n*a + x**n*b*x)**p*x)/(a**2*c*d*n*p + a**2* c*d*q + a**2*d**2*n*p*x + a**2*d**2*q*x + a*b*c**2*n*p + a*b*c**2*p + 2...