Integrand size = 37, antiderivative size = 176 \[ \int \frac {\sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x)^2} \, dx=-\frac {4 \sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 e (d+e x)}-\frac {4 (a e+c d x)^{3/2} \left (\frac {c d (d+e x)}{e (a e+c d x)}\right )^{3/4} \operatorname {EllipticF}\left (\frac {1}{2} \arctan \left (\frac {\sqrt {c d^2-a e^2}}{\sqrt {e} \sqrt {a e+c d x}}\right ),2\right )}{3 \sqrt {e} \sqrt {c d^2-a e^2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/4}} \] Output:
-4/3*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/4)/e/(e*x+d)-4/3*(c*d*x+a*e)^(3/ 2)*(c*d*(e*x+d)/e/(c*d*x+a*e))^(3/4)*InverseJacobiAM(1/2*arctan((-a*e^2+c* d^2)^(1/2)/e^(1/2)/(c*d*x+a*e)^(1/2)),2^(1/2))/e^(1/2)/(-a*e^2+c*d^2)^(1/2 )/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/4)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.06 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.60 \[ \int \frac {\sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x)^2} \, dx=\frac {4 c d (a e+c d x) \sqrt [4]{(a e+c d x) (d+e x)} \operatorname {Hypergeometric2F1}\left (\frac {5}{4},\frac {7}{4},\frac {9}{4},\frac {e (a e+c d x)}{-c d^2+a e^2}\right )}{5 \left (c d^2-a e^2\right )^2 \sqrt [4]{\frac {c d (d+e x)}{c d^2-a e^2}}} \] Input:
Integrate[(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(1/4)/(d + e*x)^2,x]
Output:
(4*c*d*(a*e + c*d*x)*((a*e + c*d*x)*(d + e*x))^(1/4)*Hypergeometric2F1[5/4 , 7/4, 9/4, (e*(a*e + c*d*x))/(-(c*d^2) + a*e^2)])/(5*(c*d^2 - a*e^2)^2*(( c*d*(d + e*x))/(c*d^2 - a*e^2))^(1/4))
Time = 0.66 (sec) , antiderivative size = 235, normalized size of antiderivative = 1.34, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.189, Rules used = {1138, 57, 73, 768, 858, 807, 229}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt [4]{x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{(d+e x)^2} \, dx\) |
\(\Big \downarrow \) 1138 |
\(\displaystyle \frac {\sqrt [4]{x \left (a e^2+c d^2\right )+a d e+c d e x^2} \int \frac {\sqrt [4]{a e+c d x}}{\left (\frac {e x}{d}+1\right )^{7/4}}dx}{d^2 \sqrt [4]{\frac {e x}{d}+1} \sqrt [4]{a e+c d x}}\) |
\(\Big \downarrow \) 57 |
\(\displaystyle \frac {\sqrt [4]{x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (\frac {c d^2 \int \frac {1}{(a e+c d x)^{3/4} \left (\frac {e x}{d}+1\right )^{3/4}}dx}{3 e}-\frac {4 d \sqrt [4]{a e+c d x}}{3 e \left (\frac {e x}{d}+1\right )^{3/4}}\right )}{d^2 \sqrt [4]{\frac {e x}{d}+1} \sqrt [4]{a e+c d x}}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {\sqrt [4]{x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (\frac {4 d \int \frac {1}{\left (-\frac {a e^2}{c d^2}+\frac {(a e+c d x) e}{c d^2}+1\right )^{3/4}}d\sqrt [4]{a e+c d x}}{3 e}-\frac {4 d \sqrt [4]{a e+c d x}}{3 e \left (\frac {e x}{d}+1\right )^{3/4}}\right )}{d^2 \sqrt [4]{\frac {e x}{d}+1} \sqrt [4]{a e+c d x}}\) |
\(\Big \downarrow \) 768 |
\(\displaystyle \frac {\sqrt [4]{x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (\frac {4 d (a e+c d x)^{3/4} \left (\frac {c d^2-a e^2}{e (a e+c d x)}+1\right )^{3/4} \int \frac {1}{(a e+c d x)^{3/4} \left (\frac {c d^2-a e^2}{e (a e+c d x)}+1\right )^{3/4}}d\sqrt [4]{a e+c d x}}{3 e \left (-\frac {a e^2}{c d^2}+\frac {e (a e+c d x)}{c d^2}+1\right )^{3/4}}-\frac {4 d \sqrt [4]{a e+c d x}}{3 e \left (\frac {e x}{d}+1\right )^{3/4}}\right )}{d^2 \sqrt [4]{\frac {e x}{d}+1} \sqrt [4]{a e+c d x}}\) |
\(\Big \downarrow \) 858 |
\(\displaystyle \frac {\sqrt [4]{x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (-\frac {4 d (a e+c d x)^{3/4} \left (\frac {c d^2-a e^2}{e (a e+c d x)}+1\right )^{3/4} \int \frac {1}{\sqrt [4]{a e+c d x} \left (\frac {\left (c d^2-a e^2\right ) (a e+c d x)}{e}+1\right )^{3/4}}d\frac {1}{\sqrt [4]{a e+c d x}}}{3 e \left (-\frac {a e^2}{c d^2}+\frac {e (a e+c d x)}{c d^2}+1\right )^{3/4}}-\frac {4 d \sqrt [4]{a e+c d x}}{3 e \left (\frac {e x}{d}+1\right )^{3/4}}\right )}{d^2 \sqrt [4]{\frac {e x}{d}+1} \sqrt [4]{a e+c d x}}\) |
\(\Big \downarrow \) 807 |
\(\displaystyle \frac {\sqrt [4]{x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (-\frac {2 d (a e+c d x)^{3/4} \left (\frac {c d^2-a e^2}{e (a e+c d x)}+1\right )^{3/4} \int \frac {1}{\left (\frac {\sqrt {a e+c d x} \left (c d^2-a e^2\right )}{e}+1\right )^{3/4}}d\sqrt {a e+c d x}}{3 e \left (-\frac {a e^2}{c d^2}+\frac {e (a e+c d x)}{c d^2}+1\right )^{3/4}}-\frac {4 d \sqrt [4]{a e+c d x}}{3 e \left (\frac {e x}{d}+1\right )^{3/4}}\right )}{d^2 \sqrt [4]{\frac {e x}{d}+1} \sqrt [4]{a e+c d x}}\) |
\(\Big \downarrow \) 229 |
\(\displaystyle \frac {\sqrt [4]{x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (-\frac {4 d (a e+c d x)^{3/4} \left (\frac {c d^2-a e^2}{e (a e+c d x)}+1\right )^{3/4} \operatorname {EllipticF}\left (\frac {1}{2} \arctan \left (\frac {\sqrt {c d^2-a e^2} \sqrt {a e+c d x}}{\sqrt {e}}\right ),2\right )}{3 \sqrt {e} \sqrt {c d^2-a e^2} \left (-\frac {a e^2}{c d^2}+\frac {e (a e+c d x)}{c d^2}+1\right )^{3/4}}-\frac {4 d \sqrt [4]{a e+c d x}}{3 e \left (\frac {e x}{d}+1\right )^{3/4}}\right )}{d^2 \sqrt [4]{\frac {e x}{d}+1} \sqrt [4]{a e+c d x}}\) |
Input:
Int[(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(1/4)/(d + e*x)^2,x]
Output:
((a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(1/4)*((-4*d*(a*e + c*d*x)^(1/4)) /(3*e*(1 + (e*x)/d)^(3/4)) - (4*d*(a*e + c*d*x)^(3/4)*(1 + (c*d^2 - a*e^2) /(e*(a*e + c*d*x)))^(3/4)*EllipticF[ArcTan[(Sqrt[c*d^2 - a*e^2]*Sqrt[a*e + c*d*x])/Sqrt[e]]/2, 2])/(3*Sqrt[e]*Sqrt[c*d^2 - a*e^2]*(1 - (a*e^2)/(c*d^ 2) + (e*(a*e + c*d*x))/(c*d^2))^(3/4))))/(d^2*(a*e + c*d*x)^(1/4)*(1 + (e* x)/d)^(1/4))
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] & & GtQ[n, 0] && LtQ[m, -1] && !(IntegerQ[n] && !IntegerQ[m]) && !(ILeQ[m + n + 2, 0] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c , d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-3/4), x_Symbol] :> Simp[(2/(a^(3/4)*Rt[b/a, 2]) )*EllipticF[(1/2)*ArcTan[Rt[b/a, 2]*x], 2], x] /; FreeQ[{a, b}, x] && GtQ[a , 0] && PosQ[b/a]
Int[((a_) + (b_.)*(x_)^4)^(-3/4), x_Symbol] :> Simp[x^3*((1 + a/(b*x^4))^(3 /4)/(a + b*x^4)^(3/4)) Int[1/(x^3*(1 + a/(b*x^4))^(3/4)), x], x] /; FreeQ [{a, b}, x]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Simp[1/k Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Subst[Int[(a + b/x^n)^p/x^(m + 2), x], x, 1/x] /; FreeQ[{a, b, p}, x] && ILtQ[n, 0] && Int egerQ[m]
Int[((d_) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Sy mbol] :> Simp[d^m*((a + b*x + c*x^2)^FracPart[p]/((1 + e*(x/d))^FracPart[p] *(a/d + (c*x)/e)^FracPart[p])) Int[(1 + e*(x/d))^(m + p)*(a/d + (c/e)*x)^ p, x], x] /; FreeQ[{a, b, c, d, e, m}, x] && EqQ[c*d^2 - b*d*e + a*e^2, 0] && (IntegerQ[m] || GtQ[d, 0]) && !(IGtQ[m, 0] && (IntegerQ[3*p] || Integer Q[4*p]))
\[\int \frac {{\left (a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d \,x^{2} e \right )}^{\frac {1}{4}}}{\left (e x +d \right )^{2}}d x\]
Input:
int((a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/4)/(e*x+d)^2,x)
Output:
int((a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/4)/(e*x+d)^2,x)
\[ \int \frac {\sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x)^2} \, dx=\int { \frac {{\left (c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x\right )}^{\frac {1}{4}}}{{\left (e x + d\right )}^{2}} \,d x } \] Input:
integrate((a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/4)/(e*x+d)^2,x, algorithm=" fricas")
Output:
integral((c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)^(1/4)/(e^2*x^2 + 2*d*e*x + d^2), x)
\[ \int \frac {\sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x)^2} \, dx=\int \frac {\sqrt [4]{\left (d + e x\right ) \left (a e + c d x\right )}}{\left (d + e x\right )^{2}}\, dx \] Input:
integrate((a*d*e+(a*e**2+c*d**2)*x+c*d*e*x**2)**(1/4)/(e*x+d)**2,x)
Output:
Integral(((d + e*x)*(a*e + c*d*x))**(1/4)/(d + e*x)**2, x)
\[ \int \frac {\sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x)^2} \, dx=\int { \frac {{\left (c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x\right )}^{\frac {1}{4}}}{{\left (e x + d\right )}^{2}} \,d x } \] Input:
integrate((a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/4)/(e*x+d)^2,x, algorithm=" maxima")
Output:
integrate((c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)^(1/4)/(e*x + d)^2, x)
\[ \int \frac {\sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x)^2} \, dx=\int { \frac {{\left (c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x\right )}^{\frac {1}{4}}}{{\left (e x + d\right )}^{2}} \,d x } \] Input:
integrate((a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/4)/(e*x+d)^2,x, algorithm=" giac")
Output:
integrate((c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)^(1/4)/(e*x + d)^2, x)
Timed out. \[ \int \frac {\sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x)^2} \, dx=\int \frac {{\left (c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e\right )}^{1/4}}{{\left (d+e\,x\right )}^2} \,d x \] Input:
int((x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(1/4)/(d + e*x)^2,x)
Output:
int((x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(1/4)/(d + e*x)^2, x)
\[ \int \frac {\sqrt [4]{a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x)^2} \, dx =\text {Too large to display} \] Input:
int((a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/4)/(e*x+d)^2,x)
Output:
( - 4*(a*d*e + a*e**2*x + c*d**2*x + c*d*e*x**2)**(1/4)*a*e + 3*int(((a*d* e + a*e**2*x + c*d**2*x + c*d*e*x**2)**(1/4)*x)/(3*a**2*d**2*e**3 + 6*a**2 *d*e**4*x + 3*a**2*e**5*x**2 - a*c*d**4*e + a*c*d**3*e**2*x + 5*a*c*d**2*e **3*x**2 + 3*a*c*d*e**4*x**3 - c**2*d**5*x - 2*c**2*d**4*e*x**2 - c**2*d** 3*e**2*x**3),x)*a**2*c*d**2*e**4 + 3*int(((a*d*e + a*e**2*x + c*d**2*x + c *d*e*x**2)**(1/4)*x)/(3*a**2*d**2*e**3 + 6*a**2*d*e**4*x + 3*a**2*e**5*x** 2 - a*c*d**4*e + a*c*d**3*e**2*x + 5*a*c*d**2*e**3*x**2 + 3*a*c*d*e**4*x** 3 - c**2*d**5*x - 2*c**2*d**4*e*x**2 - c**2*d**3*e**2*x**3),x)*a**2*c*d*e* *5*x - 4*int(((a*d*e + a*e**2*x + c*d**2*x + c*d*e*x**2)**(1/4)*x)/(3*a**2 *d**2*e**3 + 6*a**2*d*e**4*x + 3*a**2*e**5*x**2 - a*c*d**4*e + a*c*d**3*e* *2*x + 5*a*c*d**2*e**3*x**2 + 3*a*c*d*e**4*x**3 - c**2*d**5*x - 2*c**2*d** 4*e*x**2 - c**2*d**3*e**2*x**3),x)*a*c**2*d**4*e**2 - 4*int(((a*d*e + a*e* *2*x + c*d**2*x + c*d*e*x**2)**(1/4)*x)/(3*a**2*d**2*e**3 + 6*a**2*d*e**4* x + 3*a**2*e**5*x**2 - a*c*d**4*e + a*c*d**3*e**2*x + 5*a*c*d**2*e**3*x**2 + 3*a*c*d*e**4*x**3 - c**2*d**5*x - 2*c**2*d**4*e*x**2 - c**2*d**3*e**2*x **3),x)*a*c**2*d**3*e**3*x + int(((a*d*e + a*e**2*x + c*d**2*x + c*d*e*x** 2)**(1/4)*x)/(3*a**2*d**2*e**3 + 6*a**2*d*e**4*x + 3*a**2*e**5*x**2 - a*c* d**4*e + a*c*d**3*e**2*x + 5*a*c*d**2*e**3*x**2 + 3*a*c*d*e**4*x**3 - c**2 *d**5*x - 2*c**2*d**4*e*x**2 - c**2*d**3*e**2*x**3),x)*c**3*d**6 + int(((a *d*e + a*e**2*x + c*d**2*x + c*d*e*x**2)**(1/4)*x)/(3*a**2*d**2*e**3 + ...