Integrand size = 24, antiderivative size = 123 \[ \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx=\frac {7}{16} c^2 x \sqrt {c-a^2 c x^2}+\frac {7}{24} c x \left (c-a^2 c x^2\right )^{3/2}-\frac {2 \left (c-a^2 c x^2\right )^{5/2}}{5 a}-\frac {1}{6} x \left (c-a^2 c x^2\right )^{5/2}+\frac {7 c^{5/2} \arctan \left (\frac {a \sqrt {c} x}{\sqrt {c-a^2 c x^2}}\right )}{16 a} \] Output:
7/16*c^2*x*(-a^2*c*x^2+c)^(1/2)+7/24*c*x*(-a^2*c*x^2+c)^(3/2)-2/5*(-a^2*c* x^2+c)^(5/2)/a-1/6*x*(-a^2*c*x^2+c)^(5/2)+7/16*c^(5/2)*arctan(a*c^(1/2)*x/ (-a^2*c*x^2+c)^(1/2))/a
Time = 0.17 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.10 \[ \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx=\frac {c^2 \sqrt {c-a^2 c x^2} \left (\sqrt {1+a x} \left (-96+231 a x+57 a^2 x^2-182 a^3 x^3-106 a^4 x^4+56 a^5 x^5+40 a^6 x^6\right )-210 \sqrt {1-a x} \arcsin \left (\frac {\sqrt {1-a x}}{\sqrt {2}}\right )\right )}{240 a \sqrt {1-a x} \sqrt {1-a^2 x^2}} \] Input:
Integrate[E^(2*ArcTanh[a*x])*(c - a^2*c*x^2)^(5/2),x]
Output:
(c^2*Sqrt[c - a^2*c*x^2]*(Sqrt[1 + a*x]*(-96 + 231*a*x + 57*a^2*x^2 - 182* a^3*x^3 - 106*a^4*x^4 + 56*a^5*x^5 + 40*a^6*x^6) - 210*Sqrt[1 - a*x]*ArcSi n[Sqrt[1 - a*x]/Sqrt[2]]))/(240*a*Sqrt[1 - a*x]*Sqrt[1 - a^2*x^2])
Time = 0.54 (sec) , antiderivative size = 145, normalized size of antiderivative = 1.18, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {6691, 469, 455, 211, 211, 224, 216}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx\) |
\(\Big \downarrow \) 6691 |
\(\displaystyle c \int (a x+1)^2 \left (c-a^2 c x^2\right )^{3/2}dx\) |
\(\Big \downarrow \) 469 |
\(\displaystyle c \left (\frac {7}{6} \int (a x+1) \left (c-a^2 c x^2\right )^{3/2}dx-\frac {(a x+1) \left (c-a^2 c x^2\right )^{5/2}}{6 a c}\right )\) |
\(\Big \downarrow \) 455 |
\(\displaystyle c \left (\frac {7}{6} \left (\int \left (c-a^2 c x^2\right )^{3/2}dx-\frac {\left (c-a^2 c x^2\right )^{5/2}}{5 a c}\right )-\frac {(a x+1) \left (c-a^2 c x^2\right )^{5/2}}{6 a c}\right )\) |
\(\Big \downarrow \) 211 |
\(\displaystyle c \left (\frac {7}{6} \left (\frac {3}{4} c \int \sqrt {c-a^2 c x^2}dx-\frac {\left (c-a^2 c x^2\right )^{5/2}}{5 a c}+\frac {1}{4} x \left (c-a^2 c x^2\right )^{3/2}\right )-\frac {(a x+1) \left (c-a^2 c x^2\right )^{5/2}}{6 a c}\right )\) |
\(\Big \downarrow \) 211 |
\(\displaystyle c \left (\frac {7}{6} \left (\frac {3}{4} c \left (\frac {1}{2} c \int \frac {1}{\sqrt {c-a^2 c x^2}}dx+\frac {1}{2} x \sqrt {c-a^2 c x^2}\right )-\frac {\left (c-a^2 c x^2\right )^{5/2}}{5 a c}+\frac {1}{4} x \left (c-a^2 c x^2\right )^{3/2}\right )-\frac {(a x+1) \left (c-a^2 c x^2\right )^{5/2}}{6 a c}\right )\) |
\(\Big \downarrow \) 224 |
\(\displaystyle c \left (\frac {7}{6} \left (\frac {3}{4} c \left (\frac {1}{2} c \int \frac {1}{\frac {a^2 c x^2}{c-a^2 c x^2}+1}d\frac {x}{\sqrt {c-a^2 c x^2}}+\frac {1}{2} x \sqrt {c-a^2 c x^2}\right )-\frac {\left (c-a^2 c x^2\right )^{5/2}}{5 a c}+\frac {1}{4} x \left (c-a^2 c x^2\right )^{3/2}\right )-\frac {(a x+1) \left (c-a^2 c x^2\right )^{5/2}}{6 a c}\right )\) |
\(\Big \downarrow \) 216 |
\(\displaystyle c \left (\frac {7}{6} \left (\frac {3}{4} c \left (\frac {\sqrt {c} \arctan \left (\frac {a \sqrt {c} x}{\sqrt {c-a^2 c x^2}}\right )}{2 a}+\frac {1}{2} x \sqrt {c-a^2 c x^2}\right )-\frac {\left (c-a^2 c x^2\right )^{5/2}}{5 a c}+\frac {1}{4} x \left (c-a^2 c x^2\right )^{3/2}\right )-\frac {(a x+1) \left (c-a^2 c x^2\right )^{5/2}}{6 a c}\right )\) |
Input:
Int[E^(2*ArcTanh[a*x])*(c - a^2*c*x^2)^(5/2),x]
Output:
c*(-1/6*((1 + a*x)*(c - a^2*c*x^2)^(5/2))/(a*c) + (7*((x*(c - a^2*c*x^2)^( 3/2))/4 - (c - a^2*c*x^2)^(5/2)/(5*a*c) + (3*c*((x*Sqrt[c - a^2*c*x^2])/2 + (Sqrt[c]*ArcTan[(a*Sqrt[c]*x)/Sqrt[c - a^2*c*x^2]])/(2*a)))/4))/6)
Int[((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[x*((a + b*x^2)^p/(2*p + 1 )), x] + Simp[2*a*(p/(2*p + 1)) Int[(a + b*x^2)^(p - 1), x], x] /; FreeQ[ {a, b}, x] && GtQ[p, 0] && (IntegerQ[4*p] || IntegerQ[6*p])
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a , 0] || GtQ[b, 0])
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a, b}, x] && !GtQ[a, 0]
Int[((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[d*(( a + b*x^2)^(p + 1)/(2*b*(p + 1))), x] + Simp[c Int[(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, p}, x] && !LeQ[p, -1]
Int[((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[ d*(c + d*x)^(n - 1)*((a + b*x^2)^(p + 1)/(b*(n + 2*p + 1))), x] + Simp[2*c* ((n + p)/(n + 2*p + 1)) Int[(c + d*x)^(n - 1)*(a + b*x^2)^p, x], x] /; Fr eeQ[{a, b, c, d, p}, x] && EqQ[b*c^2 + a*d^2, 0] && GtQ[n, 0] && NeQ[n + 2* p + 1, 0] && IntegerQ[2*p]
Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[c^(n/2) Int[(c + d*x^2)^(p - n/2)*(1 + a*x)^n, x], x] /; FreeQ[{a, c , d, p}, x] && EqQ[a^2*c + d, 0] && !(IntegerQ[p] || GtQ[c, 0]) && IGtQ[n/ 2, 0]
Time = 0.16 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.86
method | result | size |
risch | \(\frac {\left (40 a^{5} x^{5}+96 a^{4} x^{4}-10 a^{3} x^{3}-192 a^{2} x^{2}-135 a x +96\right ) \left (a^{2} x^{2}-1\right ) c^{3}}{240 a \sqrt {-c \left (a^{2} x^{2}-1\right )}}+\frac {7 \arctan \left (\frac {\sqrt {a^{2} c}\, x}{\sqrt {-a^{2} c \,x^{2}+c}}\right ) c^{3}}{16 \sqrt {a^{2} c}}\) | \(106\) |
default | \(-\frac {x \left (-a^{2} c \,x^{2}+c \right )^{\frac {5}{2}}}{6}-\frac {5 c \left (\frac {x \left (-a^{2} c \,x^{2}+c \right )^{\frac {3}{2}}}{4}+\frac {3 c \left (\frac {x \sqrt {-a^{2} c \,x^{2}+c}}{2}+\frac {c \arctan \left (\frac {\sqrt {a^{2} c}\, x}{\sqrt {-a^{2} c \,x^{2}+c}}\right )}{2 \sqrt {a^{2} c}}\right )}{4}\right )}{6}-\frac {2 \left (\frac {\left (-\left (x -\frac {1}{a}\right )^{2} a^{2} c -2 \left (x -\frac {1}{a}\right ) a c \right )^{\frac {5}{2}}}{5}-a c \left (-\frac {\left (-2 \left (x -\frac {1}{a}\right ) a^{2} c -2 a c \right ) \left (-\left (x -\frac {1}{a}\right )^{2} a^{2} c -2 \left (x -\frac {1}{a}\right ) a c \right )^{\frac {3}{2}}}{8 a^{2} c}+\frac {3 c \left (-\frac {\left (-2 \left (x -\frac {1}{a}\right ) a^{2} c -2 a c \right ) \sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2} c -2 \left (x -\frac {1}{a}\right ) a c}}{4 a^{2} c}+\frac {c \arctan \left (\frac {\sqrt {a^{2} c}\, x}{\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2} c -2 \left (x -\frac {1}{a}\right ) a c}}\right )}{2 \sqrt {a^{2} c}}\right )}{4}\right )\right )}{a}\) | \(296\) |
Input:
int((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2),x,method=_RETURNVERBOSE)
Output:
1/240*(40*a^5*x^5+96*a^4*x^4-10*a^3*x^3-192*a^2*x^2-135*a*x+96)*(a^2*x^2-1 )/a/(-c*(a^2*x^2-1))^(1/2)*c^3+7/16/(a^2*c)^(1/2)*arctan((a^2*c)^(1/2)*x/( -a^2*c*x^2+c)^(1/2))*c^3
Time = 0.15 (sec) , antiderivative size = 241, normalized size of antiderivative = 1.96 \[ \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx=\left [\frac {105 \, \sqrt {-c} c^{2} \log \left (2 \, a^{2} c x^{2} + 2 \, \sqrt {-a^{2} c x^{2} + c} a \sqrt {-c} x - c\right ) - 2 \, {\left (40 \, a^{5} c^{2} x^{5} + 96 \, a^{4} c^{2} x^{4} - 10 \, a^{3} c^{2} x^{3} - 192 \, a^{2} c^{2} x^{2} - 135 \, a c^{2} x + 96 \, c^{2}\right )} \sqrt {-a^{2} c x^{2} + c}}{480 \, a}, -\frac {105 \, c^{\frac {5}{2}} \arctan \left (\frac {\sqrt {-a^{2} c x^{2} + c} a \sqrt {c} x}{a^{2} c x^{2} - c}\right ) + {\left (40 \, a^{5} c^{2} x^{5} + 96 \, a^{4} c^{2} x^{4} - 10 \, a^{3} c^{2} x^{3} - 192 \, a^{2} c^{2} x^{2} - 135 \, a c^{2} x + 96 \, c^{2}\right )} \sqrt {-a^{2} c x^{2} + c}}{240 \, a}\right ] \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2),x, algorithm="fricas ")
Output:
[1/480*(105*sqrt(-c)*c^2*log(2*a^2*c*x^2 + 2*sqrt(-a^2*c*x^2 + c)*a*sqrt(- c)*x - c) - 2*(40*a^5*c^2*x^5 + 96*a^4*c^2*x^4 - 10*a^3*c^2*x^3 - 192*a^2* c^2*x^2 - 135*a*c^2*x + 96*c^2)*sqrt(-a^2*c*x^2 + c))/a, -1/240*(105*c^(5/ 2)*arctan(sqrt(-a^2*c*x^2 + c)*a*sqrt(c)*x/(a^2*c*x^2 - c)) + (40*a^5*c^2* x^5 + 96*a^4*c^2*x^4 - 10*a^3*c^2*x^3 - 192*a^2*c^2*x^2 - 135*a*c^2*x + 96 *c^2)*sqrt(-a^2*c*x^2 + c))/a]
Time = 4.03 (sec) , antiderivative size = 325, normalized size of antiderivative = 2.64 \[ \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx=- a^{4} c^{2} \left (\begin {cases} \sqrt {- a^{2} c x^{2} + c} \left (\frac {x^{5}}{6} - \frac {x^{3}}{24 a^{2}} - \frac {x}{16 a^{4}}\right ) + \frac {c \left (\begin {cases} \frac {\log {\left (- 2 a^{2} c x + 2 \sqrt {- a^{2} c} \sqrt {- a^{2} c x^{2} + c} \right )}}{\sqrt {- a^{2} c}} & \text {for}\: c \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {- a^{2} c x^{2}}} & \text {otherwise} \end {cases}\right )}{16 a^{4}} & \text {for}\: a^{2} c \neq 0 \\\frac {\sqrt {c} x^{5}}{5} & \text {otherwise} \end {cases}\right ) - 2 a^{3} c^{2} \left (\begin {cases} \sqrt {- a^{2} c x^{2} + c} \left (\frac {x^{4}}{5} - \frac {x^{2}}{15 a^{2}} - \frac {2}{15 a^{4}}\right ) & \text {for}\: a^{2} c \neq 0 \\\frac {\sqrt {c} x^{4}}{4} & \text {otherwise} \end {cases}\right ) + 2 a c^{2} \left (\begin {cases} \left (\frac {x^{2}}{3} - \frac {1}{3 a^{2}}\right ) \sqrt {- a^{2} c x^{2} + c} & \text {for}\: a^{2} c \neq 0 \\\frac {\sqrt {c} x^{2}}{2} & \text {otherwise} \end {cases}\right ) + c^{2} \left (\begin {cases} \frac {c \left (\begin {cases} \frac {\log {\left (- 2 a^{2} c x + 2 \sqrt {- a^{2} c} \sqrt {- a^{2} c x^{2} + c} \right )}}{\sqrt {- a^{2} c}} & \text {for}\: c \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {- a^{2} c x^{2}}} & \text {otherwise} \end {cases}\right )}{2} + \frac {x \sqrt {- a^{2} c x^{2} + c}}{2} & \text {for}\: a^{2} c \neq 0 \\\sqrt {c} x & \text {otherwise} \end {cases}\right ) \] Input:
integrate((a*x+1)**2/(-a**2*x**2+1)*(-a**2*c*x**2+c)**(5/2),x)
Output:
-a**4*c**2*Piecewise((sqrt(-a**2*c*x**2 + c)*(x**5/6 - x**3/(24*a**2) - x/ (16*a**4)) + c*Piecewise((log(-2*a**2*c*x + 2*sqrt(-a**2*c)*sqrt(-a**2*c*x **2 + c))/sqrt(-a**2*c), Ne(c, 0)), (x*log(x)/sqrt(-a**2*c*x**2), True))/( 16*a**4), Ne(a**2*c, 0)), (sqrt(c)*x**5/5, True)) - 2*a**3*c**2*Piecewise( (sqrt(-a**2*c*x**2 + c)*(x**4/5 - x**2/(15*a**2) - 2/(15*a**4)), Ne(a**2*c , 0)), (sqrt(c)*x**4/4, True)) + 2*a*c**2*Piecewise(((x**2/3 - 1/(3*a**2)) *sqrt(-a**2*c*x**2 + c), Ne(a**2*c, 0)), (sqrt(c)*x**2/2, True)) + c**2*Pi ecewise((c*Piecewise((log(-2*a**2*c*x + 2*sqrt(-a**2*c)*sqrt(-a**2*c*x**2 + c))/sqrt(-a**2*c), Ne(c, 0)), (x*log(x)/sqrt(-a**2*c*x**2), True))/2 + x *sqrt(-a**2*c*x**2 + c)/2, Ne(a**2*c, 0)), (sqrt(c)*x, True))
Time = 0.20 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.40 \[ \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx=-\frac {1}{240} \, {\left (\frac {40 \, {\left (-a^{2} c x^{2} + c\right )}^{\frac {5}{2}} x}{a} - \frac {70 \, {\left (-a^{2} c x^{2} + c\right )}^{\frac {3}{2}} c x}{a} - \frac {180 \, \sqrt {a^{2} c x^{2} - 4 \, a c x + 3 \, c} c^{2} x}{a} + \frac {75 \, \sqrt {-a^{2} c x^{2} + c} c^{2} x}{a} + \frac {75 \, c^{\frac {5}{2}} \arcsin \left (a x\right )}{a^{2}} + \frac {96 \, {\left (-a^{2} c x^{2} + c\right )}^{\frac {5}{2}}}{a^{2}} + \frac {360 \, \sqrt {a^{2} c x^{2} - 4 \, a c x + 3 \, c} c^{2}}{a^{2}} - \frac {180 \, c^{4} \arcsin \left (a x - 2\right )}{a^{5} \left (-\frac {c}{a^{2}}\right )^{\frac {3}{2}}}\right )} a \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2),x, algorithm="maxima ")
Output:
-1/240*(40*(-a^2*c*x^2 + c)^(5/2)*x/a - 70*(-a^2*c*x^2 + c)^(3/2)*c*x/a - 180*sqrt(a^2*c*x^2 - 4*a*c*x + 3*c)*c^2*x/a + 75*sqrt(-a^2*c*x^2 + c)*c^2* x/a + 75*c^(5/2)*arcsin(a*x)/a^2 + 96*(-a^2*c*x^2 + c)^(5/2)/a^2 + 360*sqr t(a^2*c*x^2 - 4*a*c*x + 3*c)*c^2/a^2 - 180*c^4*arcsin(a*x - 2)/(a^5*(-c/a^ 2)^(3/2)))*a
Time = 0.17 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.94 \[ \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx=-\frac {7 \, c^{3} \log \left ({\left | -\sqrt {-a^{2} c} x + \sqrt {-a^{2} c x^{2} + c} \right |}\right )}{16 \, \sqrt {-c} {\left | a \right |}} + \frac {1}{240} \, \sqrt {-a^{2} c x^{2} + c} {\left ({\left (135 \, c^{2} + 2 \, {\left (96 \, a c^{2} + {\left (5 \, a^{2} c^{2} - 4 \, {\left (5 \, a^{4} c^{2} x + 12 \, a^{3} c^{2}\right )} x\right )} x\right )} x\right )} x - \frac {96 \, c^{2}}{a}\right )} \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2),x, algorithm="giac")
Output:
-7/16*c^3*log(abs(-sqrt(-a^2*c)*x + sqrt(-a^2*c*x^2 + c)))/(sqrt(-c)*abs(a )) + 1/240*sqrt(-a^2*c*x^2 + c)*((135*c^2 + 2*(96*a*c^2 + (5*a^2*c^2 - 4*( 5*a^4*c^2*x + 12*a^3*c^2)*x)*x)*x)*x - 96*c^2/a)
Timed out. \[ \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx=\int -\frac {{\left (c-a^2\,c\,x^2\right )}^{5/2}\,{\left (a\,x+1\right )}^2}{a^2\,x^2-1} \,d x \] Input:
int(-((c - a^2*c*x^2)^(5/2)*(a*x + 1)^2)/(a^2*x^2 - 1),x)
Output:
int(-((c - a^2*c*x^2)^(5/2)*(a*x + 1)^2)/(a^2*x^2 - 1), x)
Time = 0.15 (sec) , antiderivative size = 122, normalized size of antiderivative = 0.99 \[ \int e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{5/2} \, dx=\frac {\sqrt {c}\, c^{2} \left (105 \mathit {asin} \left (a x \right )-40 \sqrt {-a^{2} x^{2}+1}\, a^{5} x^{5}-96 \sqrt {-a^{2} x^{2}+1}\, a^{4} x^{4}+10 \sqrt {-a^{2} x^{2}+1}\, a^{3} x^{3}+192 \sqrt {-a^{2} x^{2}+1}\, a^{2} x^{2}+135 \sqrt {-a^{2} x^{2}+1}\, a x -96 \sqrt {-a^{2} x^{2}+1}+96\right )}{240 a} \] Input:
int((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2),x)
Output:
(sqrt(c)*c**2*(105*asin(a*x) - 40*sqrt( - a**2*x**2 + 1)*a**5*x**5 - 96*sq rt( - a**2*x**2 + 1)*a**4*x**4 + 10*sqrt( - a**2*x**2 + 1)*a**3*x**3 + 192 *sqrt( - a**2*x**2 + 1)*a**2*x**2 + 135*sqrt( - a**2*x**2 + 1)*a*x - 96*sq rt( - a**2*x**2 + 1) + 96))/(240*a)