\(\int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx\) [347]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [A] (verification not implemented)
Sympy [C] (verification not implemented)
Maxima [A] (verification not implemented)
Giac [B] (verification not implemented)
Mupad [B] (verification not implemented)
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 19, antiderivative size = 156 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx=-\frac {7 a^2 c^4 \sqrt {1-a^2 x^2}}{8 x^4}+\frac {7 a^4 c^4 \sqrt {1-a^2 x^2}}{16 x^2}-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {3 a c^4 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}+\frac {11 a^3 c^4 \left (1-a^2 x^2\right )^{3/2}}{15 x^3}+\frac {7}{16} a^6 c^4 \text {arctanh}\left (\sqrt {1-a^2 x^2}\right ) \] Output:

-7/8*a^2*c^4*(-a^2*x^2+1)^(1/2)/x^4+7/16*a^4*c^4*(-a^2*x^2+1)^(1/2)/x^2-1/ 
6*c^4*(-a^2*x^2+1)^(3/2)/x^6+3/5*a*c^4*(-a^2*x^2+1)^(3/2)/x^5+11/15*a^3*c^ 
4*(-a^2*x^2+1)^(3/2)/x^3+7/16*a^6*c^4*arctanh((-a^2*x^2+1)^(1/2))
 

Mathematica [A] (verified)

Time = 0.03 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.74 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx=\frac {c^4 \left (-40+144 a x-130 a^2 x^2-112 a^3 x^3+275 a^4 x^4-208 a^5 x^5-105 a^6 x^6+176 a^7 x^7+105 a^6 x^6 \sqrt {1-a^2 x^2} \text {arctanh}\left (\sqrt {1-a^2 x^2}\right )\right )}{240 x^6 \sqrt {1-a^2 x^2}} \] Input:

Integrate[(E^ArcTanh[a*x]*(c - a*c*x)^4)/x^7,x]
 

Output:

(c^4*(-40 + 144*a*x - 130*a^2*x^2 - 112*a^3*x^3 + 275*a^4*x^4 - 208*a^5*x^ 
5 - 105*a^6*x^6 + 176*a^7*x^7 + 105*a^6*x^6*Sqrt[1 - a^2*x^2]*ArcTanh[Sqrt 
[1 - a^2*x^2]]))/(240*x^6*Sqrt[1 - a^2*x^2])
 

Rubi [A] (verified)

Time = 0.47 (sec) , antiderivative size = 153, normalized size of antiderivative = 0.98, number of steps used = 14, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.684, Rules used = {6678, 27, 540, 27, 2338, 27, 539, 27, 534, 243, 51, 73, 221}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx\)

\(\Big \downarrow \) 6678

\(\displaystyle c \int \frac {c^3 (1-a x)^3 \sqrt {1-a^2 x^2}}{x^7}dx\)

\(\Big \downarrow \) 27

\(\displaystyle c^4 \int \frac {(1-a x)^3 \sqrt {1-a^2 x^2}}{x^7}dx\)

\(\Big \downarrow \) 540

\(\displaystyle c^4 \left (-\frac {1}{6} \int \frac {3 \sqrt {1-a^2 x^2} \left (2 x^2 a^3-7 x a^2+6 a\right )}{x^6}dx-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle c^4 \left (-\frac {1}{2} \int \frac {\sqrt {1-a^2 x^2} \left (2 x^2 a^3-7 x a^2+6 a\right )}{x^6}dx-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 2338

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} \int \frac {a^2 (35-22 a x) \sqrt {1-a^2 x^2}}{x^5}dx+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} a^2 \int \frac {(35-22 a x) \sqrt {1-a^2 x^2}}{x^5}dx+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 539

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} a^2 \left (-\frac {1}{4} \int \frac {a (88-35 a x) \sqrt {1-a^2 x^2}}{x^4}dx-\frac {35 \left (1-a^2 x^2\right )^{3/2}}{4 x^4}\right )+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} a^2 \left (-\frac {1}{4} a \int \frac {(88-35 a x) \sqrt {1-a^2 x^2}}{x^4}dx-\frac {35 \left (1-a^2 x^2\right )^{3/2}}{4 x^4}\right )+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 534

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} a^2 \left (-\frac {1}{4} a \left (-35 a \int \frac {\sqrt {1-a^2 x^2}}{x^3}dx-\frac {88 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {35 \left (1-a^2 x^2\right )^{3/2}}{4 x^4}\right )+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 243

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} a^2 \left (-\frac {1}{4} a \left (-\frac {35}{2} a \int \frac {\sqrt {1-a^2 x^2}}{x^4}dx^2-\frac {88 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {35 \left (1-a^2 x^2\right )^{3/2}}{4 x^4}\right )+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 51

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} a^2 \left (-\frac {1}{4} a \left (-\frac {35}{2} a \left (-\frac {1}{2} a^2 \int \frac {1}{x^2 \sqrt {1-a^2 x^2}}dx^2-\frac {\sqrt {1-a^2 x^2}}{x^2}\right )-\frac {88 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {35 \left (1-a^2 x^2\right )^{3/2}}{4 x^4}\right )+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 73

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} a^2 \left (-\frac {1}{4} a \left (-\frac {35}{2} a \left (\int \frac {1}{\frac {1}{a^2}-\frac {x^4}{a^2}}d\sqrt {1-a^2 x^2}-\frac {\sqrt {1-a^2 x^2}}{x^2}\right )-\frac {88 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {35 \left (1-a^2 x^2\right )^{3/2}}{4 x^4}\right )+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

\(\Big \downarrow \) 221

\(\displaystyle c^4 \left (\frac {1}{2} \left (\frac {1}{5} a^2 \left (-\frac {1}{4} a \left (-\frac {35}{2} a \left (a^2 \text {arctanh}\left (\sqrt {1-a^2 x^2}\right )-\frac {\sqrt {1-a^2 x^2}}{x^2}\right )-\frac {88 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {35 \left (1-a^2 x^2\right )^{3/2}}{4 x^4}\right )+\frac {6 a \left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{6 x^6}\right )\)

Input:

Int[(E^ArcTanh[a*x]*(c - a*c*x)^4)/x^7,x]
 

Output:

c^4*(-1/6*(1 - a^2*x^2)^(3/2)/x^6 + ((6*a*(1 - a^2*x^2)^(3/2))/(5*x^5) + ( 
a^2*((-35*(1 - a^2*x^2)^(3/2))/(4*x^4) - (a*((-88*(1 - a^2*x^2)^(3/2))/(3* 
x^3) - (35*a*(-(Sqrt[1 - a^2*x^2]/x^2) + a^2*ArcTanh[Sqrt[1 - a^2*x^2]]))/ 
2))/4))/5)/2)
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 51
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) 
Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d, n}, x 
] && ILtQ[m, -1] && FractionQ[n] && GtQ[n, 0]
 

rule 73
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 221
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 243
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[1/2   Subst[In 
t[x^((m - 1)/2)*(a + b*x)^p, x], x, x^2], x] /; FreeQ[{a, b, m, p}, x] && I 
ntegerQ[(m - 1)/2]
 

rule 534
Int[(x_)^(m_)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> 
Simp[(-c)*x^(m + 1)*((a + b*x^2)^(p + 1)/(2*a*(p + 1))), x] + Simp[d   Int[ 
x^(m + 1)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, m, p}, x] && ILtQ[m, 
0] && GtQ[p, -1] && EqQ[m + 2*p + 3, 0]
 

rule 539
Int[(x_)^(m_)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> 
Simp[c*x^(m + 1)*((a + b*x^2)^(p + 1)/(a*(m + 1))), x] + Simp[1/(a*(m + 1)) 
   Int[x^(m + 1)*(a + b*x^2)^p*(a*d*(m + 1) - b*c*(m + 2*p + 3)*x), x], x] 
/; FreeQ[{a, b, c, d, p}, x] && ILtQ[m, -1] && GtQ[p, -1] && IntegerQ[2*p]
 

rule 540
Int[(x_)^(m_)*((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol 
] :> With[{Qx = PolynomialQuotient[(c + d*x)^n, x, x], R = PolynomialRemain 
der[(c + d*x)^n, x, x]}, Simp[R*x^(m + 1)*((a + b*x^2)^(p + 1)/(a*(m + 1))) 
, x] + Simp[1/(a*(m + 1))   Int[x^(m + 1)*(a + b*x^2)^p*ExpandToSum[a*(m + 
1)*Qx - b*R*(m + 2*p + 3)*x, x], x], x]] /; FreeQ[{a, b, c, d, p}, x] && IG 
tQ[n, 1] && ILtQ[m, -1] && GtQ[p, -1] && IntegerQ[2*p]
 

rule 2338
Int[(Pq_)*((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{ 
Q = PolynomialQuotient[Pq, c*x, x], R = PolynomialRemainder[Pq, c*x, x]}, S 
imp[R*(c*x)^(m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] + Simp[1/(a*c*( 
m + 1))   Int[(c*x)^(m + 1)*(a + b*x^2)^p*ExpandToSum[a*c*(m + 1)*Q - b*R*( 
m + 2*p + 3)*x, x], x], x]] /; FreeQ[{a, b, c, p}, x] && PolyQ[Pq, x] && Lt 
Q[m, -1] && (IntegerQ[2*p] || NeQ[Expon[Pq, x], 1])
 

rule 6678
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_.)*((e_.) + (f_.)* 
(x_))^(m_.), x_Symbol] :> Simp[c^n   Int[(e + f*x)^m*(c + d*x)^(p - n)*(1 - 
 a^2*x^2)^(n/2), x], x] /; FreeQ[{a, c, d, e, f, m, p}, x] && EqQ[a*c + d, 
0] && IntegerQ[(n - 1)/2] && (IntegerQ[p] || EqQ[p, n/2] || EqQ[p - n/2 - 1 
, 0]) && IntegerQ[2*p]
 
Maple [A] (verified)

Time = 0.32 (sec) , antiderivative size = 97, normalized size of antiderivative = 0.62

method result size
risch \(\frac {\left (176 a^{7} x^{7}-105 x^{6} a^{6}-208 a^{5} x^{5}+275 a^{4} x^{4}-112 a^{3} x^{3}-130 a^{2} x^{2}+144 a x -40\right ) c^{4}}{240 x^{6} \sqrt {-a^{2} x^{2}+1}}+\frac {7 a^{6} \operatorname {arctanh}\left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right ) c^{4}}{16}\) \(97\)
default \(c^{4} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{6 x^{6}}+\frac {17 a^{2} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{4 x^{4}}+\frac {3 a^{2} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{2 x^{2}}-\frac {a^{2} \operatorname {arctanh}\left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )}{2}\right )}{4}\right )}{6}-\frac {a^{5} \sqrt {-a^{2} x^{2}+1}}{x}-3 a \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{5 x^{5}}+\frac {4 a^{2} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{3 x^{3}}-\frac {2 a^{2} \sqrt {-a^{2} x^{2}+1}}{3 x}\right )}{5}\right )+2 a^{3} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{3 x^{3}}-\frac {2 a^{2} \sqrt {-a^{2} x^{2}+1}}{3 x}\right )-3 a^{4} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{2 x^{2}}-\frac {a^{2} \operatorname {arctanh}\left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )}{2}\right )\right )\) \(255\)
meijerg \(-\frac {a^{5} c^{4} \sqrt {-a^{2} x^{2}+1}}{x}+\frac {3 a^{6} c^{4} \left (\frac {\sqrt {\pi }}{x^{2} a^{2}}-\frac {\left (1-2 \ln \left (2\right )+2 \ln \left (x \right )+\ln \left (-a^{2}\right )\right ) \sqrt {\pi }}{2}-\frac {\sqrt {\pi }\, \left (-4 a^{2} x^{2}+8\right )}{8 a^{2} x^{2}}+\frac {\sqrt {\pi }\, \sqrt {-a^{2} x^{2}+1}}{a^{2} x^{2}}+\sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-a^{2} x^{2}+1}}{2}\right )\right )}{2 \sqrt {\pi }}-\frac {2 a^{3} c^{4} \left (2 a^{2} x^{2}+1\right ) \sqrt {-a^{2} x^{2}+1}}{3 x^{3}}+\frac {a^{6} c^{4} \left (-\frac {\sqrt {\pi }}{2 x^{4} a^{4}}-\frac {\sqrt {\pi }}{2 x^{2} a^{2}}+\frac {3 \left (\frac {7}{6}-2 \ln \left (2\right )+2 \ln \left (x \right )+\ln \left (-a^{2}\right )\right ) \sqrt {\pi }}{8}+\frac {\sqrt {\pi }\, \left (-7 a^{4} x^{4}+8 a^{2} x^{2}+8\right )}{16 a^{4} x^{4}}-\frac {\sqrt {\pi }\, \left (12 a^{2} x^{2}+8\right ) \sqrt {-a^{2} x^{2}+1}}{16 a^{4} x^{4}}-\frac {3 \sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-a^{2} x^{2}+1}}{2}\right )}{4}\right )}{\sqrt {\pi }}+\frac {3 a \,c^{4} \left (\frac {8}{3} a^{4} x^{4}+\frac {4}{3} a^{2} x^{2}+1\right ) \sqrt {-a^{2} x^{2}+1}}{5 x^{5}}-\frac {a^{6} c^{4} \left (\frac {\sqrt {\pi }}{3 x^{6} a^{6}}+\frac {\sqrt {\pi }}{4 x^{4} a^{4}}+\frac {3 \sqrt {\pi }}{8 x^{2} a^{2}}-\frac {5 \left (\frac {37}{30}-2 \ln \left (2\right )+2 \ln \left (x \right )+\ln \left (-a^{2}\right )\right ) \sqrt {\pi }}{16}-\frac {\sqrt {\pi }\, \left (-148 x^{6} a^{6}+144 a^{4} x^{4}+96 a^{2} x^{2}+128\right )}{384 a^{6} x^{6}}+\frac {\sqrt {\pi }\, \left (240 a^{4} x^{4}+160 a^{2} x^{2}+128\right ) \sqrt {-a^{2} x^{2}+1}}{384 a^{6} x^{6}}+\frac {5 \sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-a^{2} x^{2}+1}}{2}\right )}{8}\right )}{2 \sqrt {\pi }}\) \(508\)

Input:

int((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^4/x^7,x,method=_RETURNVERBOSE)
                                                                                    
                                                                                    
 

Output:

1/240*(176*a^7*x^7-105*a^6*x^6-208*a^5*x^5+275*a^4*x^4-112*a^3*x^3-130*a^2 
*x^2+144*a*x-40)/x^6/(-a^2*x^2+1)^(1/2)*c^4+7/16*a^6*arctanh(1/(-a^2*x^2+1 
)^(1/2))*c^4
 

Fricas [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.68 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx=-\frac {105 \, a^{6} c^{4} x^{6} \log \left (\frac {\sqrt {-a^{2} x^{2} + 1} - 1}{x}\right ) + {\left (176 \, a^{5} c^{4} x^{5} - 105 \, a^{4} c^{4} x^{4} - 32 \, a^{3} c^{4} x^{3} + 170 \, a^{2} c^{4} x^{2} - 144 \, a c^{4} x + 40 \, c^{4}\right )} \sqrt {-a^{2} x^{2} + 1}}{240 \, x^{6}} \] Input:

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^4/x^7,x, algorithm="fricas 
")
 

Output:

-1/240*(105*a^6*c^4*x^6*log((sqrt(-a^2*x^2 + 1) - 1)/x) + (176*a^5*c^4*x^5 
 - 105*a^4*c^4*x^4 - 32*a^3*c^4*x^3 + 170*a^2*c^4*x^2 - 144*a*c^4*x + 40*c 
^4)*sqrt(-a^2*x^2 + 1))/x^6
 

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 12.03 (sec) , antiderivative size = 799, normalized size of antiderivative = 5.12 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx =\text {Too large to display} \] Input:

integrate((a*x+1)/(-a**2*x**2+1)**(1/2)*(-a*c*x+c)**4/x**7,x)
 

Output:

a**5*c**4*Piecewise((-I*sqrt(a**2*x**2 - 1)/x, Abs(a**2*x**2) > 1), (-sqrt 
(-a**2*x**2 + 1)/x, True)) - 3*a**4*c**4*Piecewise((-a**2*acosh(1/(a*x))/2 
 + a/(2*x*sqrt(-1 + 1/(a**2*x**2))) - 1/(2*a*x**3*sqrt(-1 + 1/(a**2*x**2)) 
), 1/Abs(a**2*x**2) > 1), (I*a**2*asin(1/(a*x))/2 - I*a*sqrt(1 - 1/(a**2*x 
**2))/(2*x), True)) + 2*a**3*c**4*Piecewise((-2*I*a**2*sqrt(a**2*x**2 - 1) 
/(3*x) - I*sqrt(a**2*x**2 - 1)/(3*x**3), Abs(a**2*x**2) > 1), (-2*a**2*sqr 
t(-a**2*x**2 + 1)/(3*x) - sqrt(-a**2*x**2 + 1)/(3*x**3), True)) + 2*a**2*c 
**4*Piecewise((-3*a**4*acosh(1/(a*x))/8 + 3*a**3/(8*x*sqrt(-1 + 1/(a**2*x* 
*2))) - a/(8*x**3*sqrt(-1 + 1/(a**2*x**2))) - 1/(4*a*x**5*sqrt(-1 + 1/(a** 
2*x**2))), 1/Abs(a**2*x**2) > 1), (3*I*a**4*asin(1/(a*x))/8 - 3*I*a**3/(8* 
x*sqrt(1 - 1/(a**2*x**2))) + I*a/(8*x**3*sqrt(1 - 1/(a**2*x**2))) + I/(4*a 
*x**5*sqrt(1 - 1/(a**2*x**2))), True)) - 3*a*c**4*Piecewise((-8*a**5*sqrt( 
-1 + 1/(a**2*x**2))/15 - 4*a**3*sqrt(-1 + 1/(a**2*x**2))/(15*x**2) - a*sqr 
t(-1 + 1/(a**2*x**2))/(5*x**4), 1/Abs(a**2*x**2) > 1), (-8*I*a**5*sqrt(1 - 
 1/(a**2*x**2))/15 - 4*I*a**3*sqrt(1 - 1/(a**2*x**2))/(15*x**2) - I*a*sqrt 
(1 - 1/(a**2*x**2))/(5*x**4), True)) + c**4*Piecewise((-5*a**6*acosh(1/(a* 
x))/16 + 5*a**5/(16*x*sqrt(-1 + 1/(a**2*x**2))) - 5*a**3/(48*x**3*sqrt(-1 
+ 1/(a**2*x**2))) - a/(24*x**5*sqrt(-1 + 1/(a**2*x**2))) - 1/(6*a*x**7*sqr 
t(-1 + 1/(a**2*x**2))), 1/Abs(a**2*x**2) > 1), (5*I*a**6*asin(1/(a*x))/16 
- 5*I*a**5/(16*x*sqrt(1 - 1/(a**2*x**2))) + 5*I*a**3/(48*x**3*sqrt(1 - ...
 

Maxima [A] (verification not implemented)

Time = 0.11 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.08 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx=\frac {7}{16} \, a^{6} c^{4} \log \left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1}}{{\left | x \right |}} + \frac {2}{{\left | x \right |}}\right ) - \frac {11 \, \sqrt {-a^{2} x^{2} + 1} a^{5} c^{4}}{15 \, x} + \frac {7 \, \sqrt {-a^{2} x^{2} + 1} a^{4} c^{4}}{16 \, x^{2}} + \frac {2 \, \sqrt {-a^{2} x^{2} + 1} a^{3} c^{4}}{15 \, x^{3}} - \frac {17 \, \sqrt {-a^{2} x^{2} + 1} a^{2} c^{4}}{24 \, x^{4}} + \frac {3 \, \sqrt {-a^{2} x^{2} + 1} a c^{4}}{5 \, x^{5}} - \frac {\sqrt {-a^{2} x^{2} + 1} c^{4}}{6 \, x^{6}} \] Input:

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^4/x^7,x, algorithm="maxima 
")
 

Output:

7/16*a^6*c^4*log(2*sqrt(-a^2*x^2 + 1)/abs(x) + 2/abs(x)) - 11/15*sqrt(-a^2 
*x^2 + 1)*a^5*c^4/x + 7/16*sqrt(-a^2*x^2 + 1)*a^4*c^4/x^2 + 2/15*sqrt(-a^2 
*x^2 + 1)*a^3*c^4/x^3 - 17/24*sqrt(-a^2*x^2 + 1)*a^2*c^4/x^4 + 3/5*sqrt(-a 
^2*x^2 + 1)*a*c^4/x^5 - 1/6*sqrt(-a^2*x^2 + 1)*c^4/x^6
 

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 424 vs. \(2 (132) = 264\).

Time = 0.13 (sec) , antiderivative size = 424, normalized size of antiderivative = 2.72 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx=\frac {{\left (5 \, a^{7} c^{4} - \frac {36 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )} a^{5} c^{4}}{x} + \frac {105 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{2} a^{3} c^{4}}{x^{2}} - \frac {140 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{3} a c^{4}}{x^{3}} - \frac {15 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{4} c^{4}}{a x^{4}} + \frac {600 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{5} c^{4}}{a^{3} x^{5}}\right )} a^{12} x^{6}}{1920 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{6} {\left | a \right |}} + \frac {7 \, a^{7} c^{4} \log \left (\frac {{\left | -2 \, \sqrt {-a^{2} x^{2} + 1} {\left | a \right |} - 2 \, a \right |}}{2 \, a^{2} {\left | x \right |}}\right )}{16 \, {\left | a \right |}} - \frac {\frac {600 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )} a^{9} c^{4} {\left | a \right |}}{x} - \frac {15 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{2} a^{7} c^{4} {\left | a \right |}}{x^{2}} - \frac {140 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{3} a^{5} c^{4} {\left | a \right |}}{x^{3}} + \frac {105 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{4} a^{3} c^{4} {\left | a \right |}}{x^{4}} - \frac {36 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{5} a c^{4} {\left | a \right |}}{x^{5}} + \frac {5 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{6} c^{4} {\left | a \right |}}{a x^{6}}}{1920 \, a^{6}} \] Input:

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^4/x^7,x, algorithm="giac")
 

Output:

1/1920*(5*a^7*c^4 - 36*(sqrt(-a^2*x^2 + 1)*abs(a) + a)*a^5*c^4/x + 105*(sq 
rt(-a^2*x^2 + 1)*abs(a) + a)^2*a^3*c^4/x^2 - 140*(sqrt(-a^2*x^2 + 1)*abs(a 
) + a)^3*a*c^4/x^3 - 15*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^4*c^4/(a*x^4) + 60 
0*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^5*c^4/(a^3*x^5))*a^12*x^6/((sqrt(-a^2*x^ 
2 + 1)*abs(a) + a)^6*abs(a)) + 7/16*a^7*c^4*log(1/2*abs(-2*sqrt(-a^2*x^2 + 
 1)*abs(a) - 2*a)/(a^2*abs(x)))/abs(a) - 1/1920*(600*(sqrt(-a^2*x^2 + 1)*a 
bs(a) + a)*a^9*c^4*abs(a)/x - 15*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^2*a^7*c^4 
*abs(a)/x^2 - 140*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^3*a^5*c^4*abs(a)/x^3 + 1 
05*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^4*a^3*c^4*abs(a)/x^4 - 36*(sqrt(-a^2*x^ 
2 + 1)*abs(a) + a)^5*a*c^4*abs(a)/x^5 + 5*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^ 
6*c^4*abs(a)/(a*x^6))/a^6
 

Mupad [B] (verification not implemented)

Time = 0.03 (sec) , antiderivative size = 159, normalized size of antiderivative = 1.02 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx=\frac {3\,a\,c^4\,\sqrt {1-a^2\,x^2}}{5\,x^5}-\frac {c^4\,\sqrt {1-a^2\,x^2}}{6\,x^6}-\frac {17\,a^2\,c^4\,\sqrt {1-a^2\,x^2}}{24\,x^4}+\frac {2\,a^3\,c^4\,\sqrt {1-a^2\,x^2}}{15\,x^3}+\frac {7\,a^4\,c^4\,\sqrt {1-a^2\,x^2}}{16\,x^2}-\frac {11\,a^5\,c^4\,\sqrt {1-a^2\,x^2}}{15\,x}-\frac {a^6\,c^4\,\mathrm {atan}\left (\sqrt {1-a^2\,x^2}\,1{}\mathrm {i}\right )\,7{}\mathrm {i}}{16} \] Input:

int(((c - a*c*x)^4*(a*x + 1))/(x^7*(1 - a^2*x^2)^(1/2)),x)
 

Output:

(3*a*c^4*(1 - a^2*x^2)^(1/2))/(5*x^5) - (c^4*(1 - a^2*x^2)^(1/2))/(6*x^6) 
- (a^6*c^4*atan((1 - a^2*x^2)^(1/2)*1i)*7i)/16 - (17*a^2*c^4*(1 - a^2*x^2) 
^(1/2))/(24*x^4) + (2*a^3*c^4*(1 - a^2*x^2)^(1/2))/(15*x^3) + (7*a^4*c^4*( 
1 - a^2*x^2)^(1/2))/(16*x^2) - (11*a^5*c^4*(1 - a^2*x^2)^(1/2))/(15*x)
 

Reduce [B] (verification not implemented)

Time = 0.15 (sec) , antiderivative size = 129, normalized size of antiderivative = 0.83 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^4}{x^7} \, dx=\frac {c^{4} \left (-176 \sqrt {-a^{2} x^{2}+1}\, a^{5} x^{5}+105 \sqrt {-a^{2} x^{2}+1}\, a^{4} x^{4}+32 \sqrt {-a^{2} x^{2}+1}\, a^{3} x^{3}-170 \sqrt {-a^{2} x^{2}+1}\, a^{2} x^{2}+144 \sqrt {-a^{2} x^{2}+1}\, a x -40 \sqrt {-a^{2} x^{2}+1}-105 \,\mathrm {log}\left (\tan \left (\frac {\mathit {asin} \left (a x \right )}{2}\right )\right ) a^{6} x^{6}\right )}{240 x^{6}} \] Input:

int((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^4/x^7,x)
 

Output:

(c**4*( - 176*sqrt( - a**2*x**2 + 1)*a**5*x**5 + 105*sqrt( - a**2*x**2 + 1 
)*a**4*x**4 + 32*sqrt( - a**2*x**2 + 1)*a**3*x**3 - 170*sqrt( - a**2*x**2 
+ 1)*a**2*x**2 + 144*sqrt( - a**2*x**2 + 1)*a*x - 40*sqrt( - a**2*x**2 + 1 
) - 105*log(tan(asin(a*x)/2))*a**6*x**6))/(240*x**6)