Integrand size = 25, antiderivative size = 592 \[ \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx=-\frac {a \left (a^2+6 b^2\right ) e^{3/2} \arctan \left (\frac {\sqrt {b} \sqrt {e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{16 b^{3/2} \left (-a^2+b^2\right )^{11/4} d}-\frac {a \left (a^2+6 b^2\right ) e^{3/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{16 b^{3/2} \left (-a^2+b^2\right )^{11/4} d}-\frac {\left (3 a^2+4 b^2\right ) e^2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{24 b^2 \left (a^2-b^2\right )^2 d \sqrt {e \cos (c+d x)}}+\frac {a^2 \left (a^2+6 b^2\right ) e^2 \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {-a^2+b^2}},\frac {1}{2} (c+d x),2\right )}{16 b^2 \left (a^2-b^2\right )^2 \left (a^2-b \left (b-\sqrt {-a^2+b^2}\right )\right ) d \sqrt {e \cos (c+d x)}}+\frac {a^2 \left (a^2+6 b^2\right ) e^2 \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {-a^2+b^2}},\frac {1}{2} (c+d x),2\right )}{16 b^2 \left (a^2-b^2\right )^2 \left (a^2-b \left (b+\sqrt {-a^2+b^2}\right )\right ) d \sqrt {e \cos (c+d x)}}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}+\frac {a e \sqrt {e \cos (c+d x)}}{12 b \left (a^2-b^2\right ) d (a+b \sin (c+d x))^2}+\frac {\left (3 a^2+4 b^2\right ) e \sqrt {e \cos (c+d x)}}{24 b \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))} \] Output:
-1/16*a*(a^2+6*b^2)*e^(3/2)*arctan(b^(1/2)*(e*cos(d*x+c))^(1/2)/(-a^2+b^2) ^(1/4)/e^(1/2))/b^(3/2)/(-a^2+b^2)^(11/4)/d-1/16*a*(a^2+6*b^2)*e^(3/2)*arc tanh(b^(1/2)*(e*cos(d*x+c))^(1/2)/(-a^2+b^2)^(1/4)/e^(1/2))/b^(3/2)/(-a^2+ b^2)^(11/4)/d-1/24*(3*a^2+4*b^2)*e^2*cos(d*x+c)^(1/2)*InverseJacobiAM(1/2* d*x+1/2*c,2^(1/2))/b^2/(a^2-b^2)^2/d/(e*cos(d*x+c))^(1/2)+1/16*a^2*(a^2+6* b^2)*e^2*cos(d*x+c)^(1/2)*EllipticPi(sin(1/2*d*x+1/2*c),2*b/(b-(-a^2+b^2)^ (1/2)),2^(1/2))/b^2/(a^2-b^2)^2/(a^2-b*(b-(-a^2+b^2)^(1/2)))/d/(e*cos(d*x+ c))^(1/2)+1/16*a^2*(a^2+6*b^2)*e^2*cos(d*x+c)^(1/2)*EllipticPi(sin(1/2*d*x +1/2*c),2*b/(b+(-a^2+b^2)^(1/2)),2^(1/2))/b^2/(a^2-b^2)^2/(a^2-b*(b+(-a^2+ b^2)^(1/2)))/d/(e*cos(d*x+c))^(1/2)-1/3*e*(e*cos(d*x+c))^(1/2)/b/d/(a+b*si n(d*x+c))^3+1/12*a*e*(e*cos(d*x+c))^(1/2)/b/(a^2-b^2)/d/(a+b*sin(d*x+c))^2 +1/24*(3*a^2+4*b^2)*e*(e*cos(d*x+c))^(1/2)/b/(a^2-b^2)^2/d/(a+b*sin(d*x+c) )
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 22.78 (sec) , antiderivative size = 1263, normalized size of antiderivative = 2.13 \[ \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx =\text {Too large to display} \] Input:
Integrate[(e*Cos[c + d*x])^(3/2)/(a + b*Sin[c + d*x])^4,x]
Output:
((e*Cos[c + d*x])^(3/2)*Sec[c + d*x]*(-1/3*1/(b*(a + b*Sin[c + d*x])^3) - a/(12*b*(-a^2 + b^2)*(a + b*Sin[c + d*x])^2) + (3*a^2 + 4*b^2)/(24*b*(-a^2 + b^2)^2*(a + b*Sin[c + d*x]))))/d - ((e*Cos[c + d*x])^(3/2)*((28*a*b*(a + b*Sqrt[1 - Cos[c + d*x]^2])*((5*a*(a^2 - b^2)*AppellF1[1/4, 1/2, 1, 5/4, Cos[c + d*x]^2, (b^2*Cos[c + d*x]^2)/(-a^2 + b^2)]*Sqrt[Cos[c + d*x]])/(S qrt[1 - Cos[c + d*x]^2]*(5*(a^2 - b^2)*AppellF1[1/4, 1/2, 1, 5/4, Cos[c + d*x]^2, (b^2*Cos[c + d*x]^2)/(-a^2 + b^2)] - 2*(2*b^2*AppellF1[5/4, 1/2, 2 , 9/4, Cos[c + d*x]^2, (b^2*Cos[c + d*x]^2)/(-a^2 + b^2)] + (-a^2 + b^2)*A ppellF1[5/4, 3/2, 1, 9/4, Cos[c + d*x]^2, (b^2*Cos[c + d*x]^2)/(-a^2 + b^2 )])*Cos[c + d*x]^2)*(a^2 + b^2*(-1 + Cos[c + d*x]^2))) - ((1/8 - I/8)*Sqrt [b]*(2*ArcTan[1 - ((1 + I)*Sqrt[b]*Sqrt[Cos[c + d*x]])/(-a^2 + b^2)^(1/4)] - 2*ArcTan[1 + ((1 + I)*Sqrt[b]*Sqrt[Cos[c + d*x]])/(-a^2 + b^2)^(1/4)] + Log[Sqrt[-a^2 + b^2] - (1 + I)*Sqrt[b]*(-a^2 + b^2)^(1/4)*Sqrt[Cos[c + d* x]] + I*b*Cos[c + d*x]] - Log[Sqrt[-a^2 + b^2] + (1 + I)*Sqrt[b]*(-a^2 + b ^2)^(1/4)*Sqrt[Cos[c + d*x]] + I*b*Cos[c + d*x]]))/(-a^2 + b^2)^(3/4))*Sin [c + d*x])/(Sqrt[1 - Cos[c + d*x]^2]*(a + b*Sin[c + d*x])) - (2*(3*a^2 + 4 *b^2)*(a + b*Sqrt[1 - Cos[c + d*x]^2])*((5*b*(a^2 - b^2)*AppellF1[1/4, -1/ 2, 1, 5/4, Cos[c + d*x]^2, (b^2*Cos[c + d*x]^2)/(-a^2 + b^2)]*Sqrt[Cos[c + d*x]]*Sqrt[1 - Cos[c + d*x]^2])/((-5*(a^2 - b^2)*AppellF1[1/4, -1/2, 1, 5 /4, Cos[c + d*x]^2, (b^2*Cos[c + d*x]^2)/(-a^2 + b^2)] + 2*(2*b^2*Appel...
Time = 2.57 (sec) , antiderivative size = 551, normalized size of antiderivative = 0.93, number of steps used = 24, number of rules used = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.920, Rules used = {3042, 3172, 3042, 3343, 27, 3042, 3343, 27, 3042, 3346, 3042, 3121, 3042, 3120, 3181, 266, 756, 218, 221, 3042, 3286, 3042, 3284}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4}dx\) |
| \(\Big \downarrow \) 3172 |
| \(\displaystyle -\frac {e^2 \int \frac {\sin (c+d x)}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^3}dx}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {e^2 \int \frac {\sin (c+d x)}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^3}dx}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3343 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\int \frac {4 b-3 a \sin (c+d x)}{2 \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}dx}{2 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\int \frac {4 b-3 a \sin (c+d x)}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}dx}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\int \frac {4 b-3 a \sin (c+d x)}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}dx}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3343 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}-\frac {\int -\frac {14 a b-\left (3 a^2+4 b^2\right ) \sin (c+d x)}{2 \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}dx}{a^2-b^2}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\int \frac {14 a b-\left (3 a^2+4 b^2\right ) \sin (c+d x)}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}dx}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\int \frac {14 a b-\left (3 a^2+4 b^2\right ) \sin (c+d x)}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}dx}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3346 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \int \frac {1}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}dx}{b}-\frac {\left (3 a^2+4 b^2\right ) \int \frac {1}{\sqrt {e \cos (c+d x)}}dx}{b}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \int \frac {1}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}dx}{b}-\frac {\left (3 a^2+4 b^2\right ) \int \frac {1}{\sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3121 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \int \frac {1}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}dx}{b}-\frac {\left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\cos (c+d x)}}dx}{b \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \int \frac {1}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}dx}{b}-\frac {\left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3120 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \int \frac {1}{\sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}dx}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3181 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (\frac {b e \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b^2 \cos ^2(c+d x) e^2+\left (a^2-b^2\right ) e^2\right )}d(e \cos (c+d x))}{d}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 \sqrt {b^2-a^2}}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 \sqrt {b^2-a^2}}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 266 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (\frac {2 b e \int \frac {1}{b^2 e^4 \cos ^4(c+d x)+\left (a^2-b^2\right ) e^2}d\sqrt {e \cos (c+d x)}}{d}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 \sqrt {b^2-a^2}}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 \sqrt {b^2-a^2}}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 756 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (\frac {2 b e \left (-\frac {\int \frac {1}{\sqrt {b^2-a^2} e-b e^2 \cos ^2(c+d x)}d\sqrt {e \cos (c+d x)}}{2 e \sqrt {b^2-a^2}}-\frac {\int \frac {1}{b e^2 \cos ^2(c+d x)+\sqrt {b^2-a^2} e}d\sqrt {e \cos (c+d x)}}{2 e \sqrt {b^2-a^2}}\right )}{d}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 \sqrt {b^2-a^2}}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 \sqrt {b^2-a^2}}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 218 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (\frac {2 b e \left (-\frac {\int \frac {1}{\sqrt {b^2-a^2} e-b e^2 \cos ^2(c+d x)}d\sqrt {e \cos (c+d x)}}{2 e \sqrt {b^2-a^2}}-\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}\right )}{d}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 \sqrt {b^2-a^2}}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 \sqrt {b^2-a^2}}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 221 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 \sqrt {b^2-a^2}}-\frac {a \int \frac {1}{\sqrt {e \cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 \sqrt {b^2-a^2}}+\frac {2 b e \left (-\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}\right )}{d}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (-\frac {a \int \frac {1}{\sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )} \left (\sqrt {b^2-a^2}-b \sin \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{2 \sqrt {b^2-a^2}}-\frac {a \int \frac {1}{\sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )} \left (b \sin \left (c+d x+\frac {\pi }{2}\right )+\sqrt {b^2-a^2}\right )}dx}{2 \sqrt {b^2-a^2}}+\frac {2 b e \left (-\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}\right )}{d}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3286 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (-\frac {a \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\cos (c+d x)} \left (\sqrt {b^2-a^2}-b \cos (c+d x)\right )}dx}{2 \sqrt {b^2-a^2} \sqrt {e \cos (c+d x)}}-\frac {a \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\cos (c+d x)} \left (b \cos (c+d x)+\sqrt {b^2-a^2}\right )}dx}{2 \sqrt {b^2-a^2} \sqrt {e \cos (c+d x)}}+\frac {2 b e \left (-\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}\right )}{d}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (-\frac {a \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )} \left (\sqrt {b^2-a^2}-b \sin \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{2 \sqrt {b^2-a^2} \sqrt {e \cos (c+d x)}}-\frac {a \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )} \left (b \sin \left (c+d x+\frac {\pi }{2}\right )+\sqrt {b^2-a^2}\right )}dx}{2 \sqrt {b^2-a^2} \sqrt {e \cos (c+d x)}}+\frac {2 b e \left (-\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}\right )}{d}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
| \(\Big \downarrow \) 3284 |
| \(\displaystyle -\frac {e^2 \left (-\frac {\frac {\frac {3 a \left (a^2+6 b^2\right ) \left (\frac {2 b e \left (-\frac {\arctan \left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} \sqrt {e} \cos (c+d x)}{\sqrt [4]{b^2-a^2}}\right )}{2 \sqrt {b} e^{3/2} \left (b^2-a^2\right )^{3/4}}\right )}{d}+\frac {a \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b-\sqrt {b^2-a^2}},\frac {1}{2} (c+d x),2\right )}{d \sqrt {b^2-a^2} \left (b-\sqrt {b^2-a^2}\right ) \sqrt {e \cos (c+d x)}}-\frac {a \sqrt {\cos (c+d x)} \operatorname {EllipticPi}\left (\frac {2 b}{b+\sqrt {b^2-a^2}},\frac {1}{2} (c+d x),2\right )}{d \sqrt {b^2-a^2} \left (\sqrt {b^2-a^2}+b\right ) \sqrt {e \cos (c+d x)}}\right )}{b}-\frac {2 \left (3 a^2+4 b^2\right ) \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{b d \sqrt {e \cos (c+d x)}}}{2 \left (a^2-b^2\right )}+\frac {\left (3 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{d e \left (a^2-b^2\right ) (a+b \sin (c+d x))}}{4 \left (a^2-b^2\right )}-\frac {a \sqrt {e \cos (c+d x)}}{2 d e \left (a^2-b^2\right ) (a+b \sin (c+d x))^2}\right )}{6 b}-\frac {e \sqrt {e \cos (c+d x)}}{3 b d (a+b \sin (c+d x))^3}\) |
Input:
Int[(e*Cos[c + d*x])^(3/2)/(a + b*Sin[c + d*x])^4,x]
Output:
-1/3*(e*Sqrt[e*Cos[c + d*x]])/(b*d*(a + b*Sin[c + d*x])^3) - (e^2*(-1/2*(a *Sqrt[e*Cos[c + d*x]])/((a^2 - b^2)*d*e*(a + b*Sin[c + d*x])^2) - (((-2*(3 *a^2 + 4*b^2)*Sqrt[Cos[c + d*x]]*EllipticF[(c + d*x)/2, 2])/(b*d*Sqrt[e*Co s[c + d*x]]) + (3*a*(a^2 + 6*b^2)*((2*b*e*(-1/2*ArcTan[(Sqrt[b]*Sqrt[e]*Co s[c + d*x])/(-a^2 + b^2)^(1/4)]/(Sqrt[b]*(-a^2 + b^2)^(3/4)*e^(3/2)) - Arc Tanh[(Sqrt[b]*Sqrt[e]*Cos[c + d*x])/(-a^2 + b^2)^(1/4)]/(2*Sqrt[b]*(-a^2 + b^2)^(3/4)*e^(3/2))))/d + (a*Sqrt[Cos[c + d*x]]*EllipticPi[(2*b)/(b - Sqr t[-a^2 + b^2]), (c + d*x)/2, 2])/(Sqrt[-a^2 + b^2]*(b - Sqrt[-a^2 + b^2])* d*Sqrt[e*Cos[c + d*x]]) - (a*Sqrt[Cos[c + d*x]]*EllipticPi[(2*b)/(b + Sqrt [-a^2 + b^2]), (c + d*x)/2, 2])/(Sqrt[-a^2 + b^2]*(b + Sqrt[-a^2 + b^2])*d *Sqrt[e*Cos[c + d*x]])))/b)/(2*(a^2 - b^2)) + ((3*a^2 + 4*b^2)*Sqrt[e*Cos[ c + d*x]])/((a^2 - b^2)*d*e*(a + b*Sin[c + d*x])))/(4*(a^2 - b^2))))/(6*b)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2 ]], s = Denominator[Rt[-a/b, 2]]}, Simp[r/(2*a) Int[1/(r - s*x^2), x], x] + Simp[r/(2*a) Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] && !GtQ[a /b, 0]
Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2 )*(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
Int[((b_)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*Sin[c + d*x]) ^n/Sin[c + d*x]^n Int[Sin[c + d*x]^n, x], x] /; FreeQ[{b, c, d}, x] && Lt Q[-1, n, 1] && IntegerQ[2*n]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[g*(g*Cos[e + f*x])^(p - 1)*((a + b*Sin[e + f*x ])^(m + 1)/(b*f*(m + 1))), x] + Simp[g^2*((p - 1)/(b*(m + 1))) Int[(g*Cos [e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 1)*Sin[e + f*x], x], x] /; Fre eQ[{a, b, e, f, g}, x] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] && GtQ[p, 1] && I ntegersQ[2*m, 2*p]
Int[1/(Sqrt[cos[(e_.) + (f_.)*(x_)]*(g_.)]*((a_) + (b_.)*sin[(e_.) + (f_.)* (x_)])), x_Symbol] :> With[{q = Rt[-a^2 + b^2, 2]}, Simp[-a/(2*q) Int[1/( Sqrt[g*Cos[e + f*x]]*(q + b*Cos[e + f*x])), x], x] + (Simp[b*(g/f) Subst[ Int[1/(Sqrt[x]*(g^2*(a^2 - b^2) + b^2*x^2)), x], x, g*Cos[e + f*x]], x] - S imp[a/(2*q) Int[1/(Sqrt[g*Cos[e + f*x]]*(q - b*Cos[e + f*x])), x], x])] / ; FreeQ[{a, b, e, f, g}, x] && NeQ[a^2 - b^2, 0]
Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]]), x_Symbol] :> Simp[(2/(f*(a + b)*Sqrt[c + d]))*EllipticPi[ 2*(b/(a + b)), (1/2)*(e - Pi/2 + f*x), 2*(d/(c + d))], x] /; FreeQ[{a, b, c , d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[c + d, 0]
Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]]), x_Symbol] :> Simp[Sqrt[(c + d*Sin[e + f*x])/(c + d)]/Sqrt [c + d*Sin[e + f*x]] Int[1/((a + b*Sin[e + f*x])*Sqrt[c/(c + d) + (d/(c + d))*Sin[e + f*x]]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a* d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && !GtQ[c + d, 0]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-(b*c - a*d))*(g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^(m + 1)/(f*g*(a^2 - b^2)*(m + 1))), x] + Simp[1/((a^2 - b^2)*(m + 1)) Int[(g*Cos[e + f*x])^p *(a + b*Sin[e + f*x])^(m + 1)*Simp[(a*c - b*d)*(m + 1) - (b*c - a*d)*(m + p + 2)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && NeQ [a^2 - b^2, 0] && LtQ[m, -1] && IntegerQ[2*m]
Int[((cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((c_.) + (d_.)*sin[(e_.) + (f_.)* (x_)]))/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[d/b Int [(g*Cos[e + f*x])^p, x], x] + Simp[(b*c - a*d)/b Int[(g*Cos[e + f*x])^p/( a + b*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[a^2 - b^2, 0]
Leaf count of result is larger than twice the leaf count of optimal. \(3935\) vs. \(2(527)=1054\).
Time = 10.44 (sec) , antiderivative size = 3936, normalized size of antiderivative = 6.65
Input:
int((e*cos(d*x+c))^(3/2)/(a+b*sin(d*x+c))^4,x,method=_RETURNVERBOSE)
Output:
(-16*e^2*a*b*(1/64/b^2*(6*(arctan((2^(1/2)*(2*e*cos(1/2*d*x+1/2*c)^2-e)^(1 /2)-(e^2*(a^2-b^2)/b^2)^(1/4))/(e^2*(a^2-b^2)/b^2)^(1/4))+arctan((2^(1/2)* (2*e*cos(1/2*d*x+1/2*c)^2-e)^(1/2)+(e^2*(a^2-b^2)/b^2)^(1/4))/(e^2*(a^2-b^ 2)/b^2)^(1/4))+1/2*ln((2*e*cos(1/2*d*x+1/2*c)^2-e+(e^2*(a^2-b^2)/b^2)^(1/4 )*(2*e*cos(1/2*d*x+1/2*c)^2-e)^(1/2)*2^(1/2)+(e^2*(a^2-b^2)/b^2)^(1/2))/(2 *e*cos(1/2*d*x+1/2*c)^2-e-(e^2*(a^2-b^2)/b^2)^(1/4)*(2*e*cos(1/2*d*x+1/2*c )^2-e)^(1/2)*2^(1/2)+(e^2*(a^2-b^2)/b^2)^(1/2))))*(4*b^2*cos(1/2*d*x+1/2*c )^4-4*b^2*cos(1/2*d*x+1/2*c)^2+a^2)*2^(1/2)*(e^2*(a^2-b^2)/b^2)^(1/4)+(8*a ^2-8*b^2)*(2*e*cos(1/2*d*x+1/2*c)^2-e)^(1/2))/e/(a-b)^2/(a+b)^2/(4*b^2*cos (1/2*d*x+1/2*c)^4-4*b^2*cos(1/2*d*x+1/2*c)^2+a^2)-1/512*(3*a^2-b^2)/b^2*(2 1*(e^2*(a^2-b^2)/b^2)^(1/4)*(4*b^2*sin(1/2*d*x+1/2*c)^4-4*sin(1/2*d*x+1/2* c)^2*b^2+a^2)^2*2^(1/2)*ln((2*e*cos(1/2*d*x+1/2*c)^2-e+(e^2*(a^2-b^2)/b^2) ^(1/4)*(2*e*cos(1/2*d*x+1/2*c)^2-e)^(1/2)*2^(1/2)+(e^2*(a^2-b^2)/b^2)^(1/2 ))/(2*e*cos(1/2*d*x+1/2*c)^2-e-(e^2*(a^2-b^2)/b^2)^(1/4)*(2*e*cos(1/2*d*x+ 1/2*c)^2-e)^(1/2)*2^(1/2)+(e^2*(a^2-b^2)/b^2)^(1/2)))-42*(e^2*(a^2-b^2)/b^ 2)^(1/4)*(4*b^2*sin(1/2*d*x+1/2*c)^4-4*sin(1/2*d*x+1/2*c)^2*b^2+a^2)^2*2^( 1/2)*arctan(-2^(1/2)/(e^2*(a^2-b^2)/b^2)^(1/4)*(2*e*cos(1/2*d*x+1/2*c)^2-e )^(1/2)+1)+42*(e^2*(a^2-b^2)/b^2)^(1/4)*(4*b^2*sin(1/2*d*x+1/2*c)^4-4*sin( 1/2*d*x+1/2*c)^2*b^2+a^2)^2*2^(1/2)*arctan(2^(1/2)/(e^2*(a^2-b^2)/b^2)^(1/ 4)*(2*e*cos(1/2*d*x+1/2*c)^2-e)^(1/2)+1)+88*(2*e*cos(1/2*d*x+1/2*c)^2-e...
\[ \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx=\int { \frac {\left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{4}} \,d x } \] Input:
integrate((e*cos(d*x+c))^(3/2)/(a+b*sin(d*x+c))^4,x, algorithm="fricas")
Output:
integral(sqrt(e*cos(d*x + c))*e*cos(d*x + c)/(b^4*cos(d*x + c)^4 + a^4 + 6 *a^2*b^2 + b^4 - 2*(3*a^2*b^2 + b^4)*cos(d*x + c)^2 - 4*(a*b^3*cos(d*x + c )^2 - a^3*b - a*b^3)*sin(d*x + c)), x)
Timed out. \[ \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx=\text {Timed out} \] Input:
integrate((e*cos(d*x+c))**(3/2)/(a+b*sin(d*x+c))**4,x)
Output:
Timed out
\[ \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx=\int { \frac {\left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{4}} \,d x } \] Input:
integrate((e*cos(d*x+c))^(3/2)/(a+b*sin(d*x+c))^4,x, algorithm="maxima")
Output:
integrate((e*cos(d*x + c))^(3/2)/(b*sin(d*x + c) + a)^4, x)
\[ \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx=\int { \frac {\left (e \cos \left (d x + c\right )\right )^{\frac {3}{2}}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{4}} \,d x } \] Input:
integrate((e*cos(d*x+c))^(3/2)/(a+b*sin(d*x+c))^4,x, algorithm="giac")
Output:
integrate((e*cos(d*x + c))^(3/2)/(b*sin(d*x + c) + a)^4, x)
Timed out. \[ \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx=\int \frac {{\left (e\,\cos \left (c+d\,x\right )\right )}^{3/2}}{{\left (a+b\,\sin \left (c+d\,x\right )\right )}^4} \,d x \] Input:
int((e*cos(c + d*x))^(3/2)/(a + b*sin(c + d*x))^4,x)
Output:
int((e*cos(c + d*x))^(3/2)/(a + b*sin(c + d*x))^4, x)
\[ \int \frac {(e \cos (c+d x))^{3/2}}{(a+b \sin (c+d x))^4} \, dx =\text {Too large to display} \] Input:
int((e*cos(d*x+c))^(3/2)/(a+b*sin(d*x+c))^4,x)
Output:
(sqrt(e)*e*(2*sqrt(cos(c + d*x))*sin(c + d*x)**3*b**2 + 6*sqrt(cos(c + d*x ))*sin(c + d*x)**2*a*b + 6*sqrt(cos(c + d*x))*sin(c + d*x)*a**2 + int((sqr t(cos(c + d*x))*sin(c + d*x)**4)/(cos(c + d*x)*sin(c + d*x)**3*b**3 + 3*co s(c + d*x)*sin(c + d*x)**2*a*b**2 + 3*cos(c + d*x)*sin(c + d*x)*a**2*b + c os(c + d*x)*a**3),x)*sin(c + d*x)**3*b**5*d + 3*int((sqrt(cos(c + d*x))*si n(c + d*x)**4)/(cos(c + d*x)*sin(c + d*x)**3*b**3 + 3*cos(c + d*x)*sin(c + d*x)**2*a*b**2 + 3*cos(c + d*x)*sin(c + d*x)*a**2*b + cos(c + d*x)*a**3), x)*sin(c + d*x)**2*a*b**4*d + 3*int((sqrt(cos(c + d*x))*sin(c + d*x)**4)/( cos(c + d*x)*sin(c + d*x)**3*b**3 + 3*cos(c + d*x)*sin(c + d*x)**2*a*b**2 + 3*cos(c + d*x)*sin(c + d*x)*a**2*b + cos(c + d*x)*a**3),x)*sin(c + d*x)* a**2*b**3*d + int((sqrt(cos(c + d*x))*sin(c + d*x)**4)/(cos(c + d*x)*sin(c + d*x)**3*b**3 + 3*cos(c + d*x)*sin(c + d*x)**2*a*b**2 + 3*cos(c + d*x)*s in(c + d*x)*a**2*b + cos(c + d*x)*a**3),x)*a**3*b**2*d + 3*int((sqrt(cos(c + d*x))*sin(c + d*x)**3)/(cos(c + d*x)*sin(c + d*x)**3*b**3 + 3*cos(c + d *x)*sin(c + d*x)**2*a*b**2 + 3*cos(c + d*x)*sin(c + d*x)*a**2*b + cos(c + d*x)*a**3),x)*sin(c + d*x)**3*a*b**4*d + 9*int((sqrt(cos(c + d*x))*sin(c + d*x)**3)/(cos(c + d*x)*sin(c + d*x)**3*b**3 + 3*cos(c + d*x)*sin(c + d*x) **2*a*b**2 + 3*cos(c + d*x)*sin(c + d*x)*a**2*b + cos(c + d*x)*a**3),x)*si n(c + d*x)**2*a**2*b**3*d + 9*int((sqrt(cos(c + d*x))*sin(c + d*x)**3)/(co s(c + d*x)*sin(c + d*x)**3*b**3 + 3*cos(c + d*x)*sin(c + d*x)**2*a*b**2...