Integrand size = 23, antiderivative size = 213 \[ \int (d \csc (e+f x))^n (a+b \sin (e+f x))^2 \, dx=\frac {a^2 d^2 \cot (e+f x) (d \csc (e+f x))^{-2+n}}{f (1-n)}+\frac {2 a b d^2 \cos (e+f x) (d \csc (e+f x))^{-2+n} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2-n}{2},\frac {4-n}{2},\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}+\frac {d^3 \left (b^2 (1-n)+a^2 (2-n)\right ) \cos (e+f x) (d \csc (e+f x))^{-3+n} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3-n}{2},\frac {5-n}{2},\sin ^2(e+f x)\right )}{f (1-n) (3-n) \sqrt {\cos ^2(e+f x)}} \] Output:
a^2*d^2*cot(f*x+e)*(d*csc(f*x+e))^(-2+n)/f/(1-n)+2*a*b*d^2*cos(f*x+e)*(d*c sc(f*x+e))^(-2+n)*hypergeom([1/2, 1-1/2*n],[2-1/2*n],sin(f*x+e)^2)/f/(2-n) /(cos(f*x+e)^2)^(1/2)+d^3*(b^2*(1-n)+a^2*(2-n))*cos(f*x+e)*(d*csc(f*x+e))^ (-3+n)*hypergeom([1/2, 3/2-1/2*n],[5/2-1/2*n],sin(f*x+e)^2)/f/(1-n)/(3-n)/ (cos(f*x+e)^2)^(1/2)
Time = 2.17 (sec) , antiderivative size = 135, normalized size of antiderivative = 0.63 \[ \int (d \csc (e+f x))^n (a+b \sin (e+f x))^2 \, dx=-\frac {d \cos (e+f x) (d \csc (e+f x))^{-1+n} \sin ^2(e+f x)^{\frac {1}{2} (-1+n)} \left (b^2 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2} (-1+n),\frac {3}{2},\cos ^2(e+f x)\right )+a \left (a \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+n}{2},\frac {3}{2},\cos ^2(e+f x)\right )+2 b \csc (e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {n}{2},\frac {3}{2},\cos ^2(e+f x)\right ) \sqrt {\sin ^2(e+f x)}\right )\right )}{f} \] Input:
Integrate[(d*Csc[e + f*x])^n*(a + b*Sin[e + f*x])^2,x]
Output:
-((d*Cos[e + f*x]*(d*Csc[e + f*x])^(-1 + n)*(Sin[e + f*x]^2)^((-1 + n)/2)* (b^2*Hypergeometric2F1[1/2, (-1 + n)/2, 3/2, Cos[e + f*x]^2] + a*(a*Hyperg eometric2F1[1/2, (1 + n)/2, 3/2, Cos[e + f*x]^2] + 2*b*Csc[e + f*x]*Hyperg eometric2F1[1/2, n/2, 3/2, Cos[e + f*x]^2]*Sqrt[Sin[e + f*x]^2])))/f)
Time = 0.99 (sec) , antiderivative size = 203, normalized size of antiderivative = 0.95, number of steps used = 13, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.565, Rules used = {3042, 3717, 3042, 4275, 3042, 4259, 3042, 3122, 4534, 3042, 4259, 3042, 3122}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (a+b \sin (e+f x))^2 (d \csc (e+f x))^n \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int (a+b \sin (e+f x))^2 (d \csc (e+f x))^ndx\) |
\(\Big \downarrow \) 3717 |
\(\displaystyle d^2 \int (d \csc (e+f x))^{n-2} (b+a \csc (e+f x))^2dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle d^2 \int (d \csc (e+f x))^{n-2} (b+a \csc (e+f x))^2dx\) |
\(\Big \downarrow \) 4275 |
\(\displaystyle d^2 \left (\int (d \csc (e+f x))^{n-2} \left (b^2+a^2 \csc ^2(e+f x)\right )dx+\frac {2 a b \int (d \csc (e+f x))^{n-1}dx}{d}\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle d^2 \left (\int (d \csc (e+f x))^{n-2} \left (b^2+a^2 \csc (e+f x)^2\right )dx+\frac {2 a b \int (d \csc (e+f x))^{n-1}dx}{d}\right )\) |
\(\Big \downarrow \) 4259 |
\(\displaystyle d^2 \left (\int (d \csc (e+f x))^{n-2} \left (b^2+a^2 \csc (e+f x)^2\right )dx+\frac {2 a b \left (\frac {\sin (e+f x)}{d}\right )^n (d \csc (e+f x))^n \int \left (\frac {\sin (e+f x)}{d}\right )^{1-n}dx}{d}\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle d^2 \left (\int (d \csc (e+f x))^{n-2} \left (b^2+a^2 \csc (e+f x)^2\right )dx+\frac {2 a b \left (\frac {\sin (e+f x)}{d}\right )^n (d \csc (e+f x))^n \int \left (\frac {\sin (e+f x)}{d}\right )^{1-n}dx}{d}\right )\) |
\(\Big \downarrow \) 3122 |
\(\displaystyle d^2 \left (\int (d \csc (e+f x))^{n-2} \left (b^2+a^2 \csc (e+f x)^2\right )dx+\frac {2 a b \cos (e+f x) (d \csc (e+f x))^{n-2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2-n}{2},\frac {4-n}{2},\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}\right )\) |
\(\Big \downarrow \) 4534 |
\(\displaystyle d^2 \left (\left (\frac {a^2 (2-n)}{1-n}+b^2\right ) \int (d \csc (e+f x))^{n-2}dx+\frac {a^2 \cot (e+f x) (d \csc (e+f x))^{n-2}}{f (1-n)}+\frac {2 a b \cos (e+f x) (d \csc (e+f x))^{n-2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2-n}{2},\frac {4-n}{2},\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle d^2 \left (\left (\frac {a^2 (2-n)}{1-n}+b^2\right ) \int (d \csc (e+f x))^{n-2}dx+\frac {a^2 \cot (e+f x) (d \csc (e+f x))^{n-2}}{f (1-n)}+\frac {2 a b \cos (e+f x) (d \csc (e+f x))^{n-2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2-n}{2},\frac {4-n}{2},\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}\right )\) |
\(\Big \downarrow \) 4259 |
\(\displaystyle d^2 \left (\left (\frac {a^2 (2-n)}{1-n}+b^2\right ) \left (\frac {\sin (e+f x)}{d}\right )^n (d \csc (e+f x))^n \int \left (\frac {\sin (e+f x)}{d}\right )^{2-n}dx+\frac {a^2 \cot (e+f x) (d \csc (e+f x))^{n-2}}{f (1-n)}+\frac {2 a b \cos (e+f x) (d \csc (e+f x))^{n-2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2-n}{2},\frac {4-n}{2},\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle d^2 \left (\left (\frac {a^2 (2-n)}{1-n}+b^2\right ) \left (\frac {\sin (e+f x)}{d}\right )^n (d \csc (e+f x))^n \int \left (\frac {\sin (e+f x)}{d}\right )^{2-n}dx+\frac {a^2 \cot (e+f x) (d \csc (e+f x))^{n-2}}{f (1-n)}+\frac {2 a b \cos (e+f x) (d \csc (e+f x))^{n-2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2-n}{2},\frac {4-n}{2},\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}\right )\) |
\(\Big \downarrow \) 3122 |
\(\displaystyle d^2 \left (\frac {d \left (\frac {a^2 (2-n)}{1-n}+b^2\right ) \cos (e+f x) (d \csc (e+f x))^{n-3} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3-n}{2},\frac {5-n}{2},\sin ^2(e+f x)\right )}{f (3-n) \sqrt {\cos ^2(e+f x)}}+\frac {a^2 \cot (e+f x) (d \csc (e+f x))^{n-2}}{f (1-n)}+\frac {2 a b \cos (e+f x) (d \csc (e+f x))^{n-2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2-n}{2},\frac {4-n}{2},\sin ^2(e+f x)\right )}{f (2-n) \sqrt {\cos ^2(e+f x)}}\right )\) |
Input:
Int[(d*Csc[e + f*x])^n*(a + b*Sin[e + f*x])^2,x]
Output:
d^2*((a^2*Cot[e + f*x]*(d*Csc[e + f*x])^(-2 + n))/(f*(1 - n)) + (2*a*b*Cos [e + f*x]*(d*Csc[e + f*x])^(-2 + n)*Hypergeometric2F1[1/2, (2 - n)/2, (4 - n)/2, Sin[e + f*x]^2])/(f*(2 - n)*Sqrt[Cos[e + f*x]^2]) + (d*(b^2 + (a^2* (2 - n))/(1 - n))*Cos[e + f*x]*(d*Csc[e + f*x])^(-3 + n)*Hypergeometric2F1 [1/2, (3 - n)/2, (5 - n)/2, Sin[e + f*x]^2])/(f*(3 - n)*Sqrt[Cos[e + f*x]^ 2]))
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*(( b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]))*Hypergeometric2 F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2], x] /; FreeQ[{b, c, d, n}, x] && !IntegerQ[2*n]
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(m_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)]^(n_.))^(p_.), x_Symbol] :> Simp[d^(n*p) Int[(d*Csc[e + f*x])^(m - n*p )*(b + a*Csc[e + f*x]^n)^p, x], x] /; FreeQ[{a, b, d, e, f, m, n, p}, x] && !IntegerQ[m] && IntegersQ[n, p]
Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[(b*Csc[c + d*x] )^(n - 1)*((Sin[c + d*x]/b)^(n - 1) Int[1/(Sin[c + d*x]/b)^n, x]), x] /; FreeQ[{b, c, d, n}, x] && !IntegerQ[n]
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^2, x_Symbol] :> Simp[2*a*(b/d) Int[(d*Csc[e + f*x])^(n + 1), x], x] + Int[(d*Csc[e + f*x])^n*(a^2 + b^2*Csc[e + f*x]^2), x] /; FreeQ[{a, b, d, e, f, n}, x]
Int[(csc[(e_.) + (f_.)*(x_)]*(b_.))^(m_.)*(csc[(e_.) + (f_.)*(x_)]^2*(C_.) + (A_)), x_Symbol] :> Simp[(-C)*Cot[e + f*x]*((b*Csc[e + f*x])^m/(f*(m + 1) )), x] + Simp[(C*m + A*(m + 1))/(m + 1) Int[(b*Csc[e + f*x])^m, x], x] /; FreeQ[{b, e, f, A, C, m}, x] && NeQ[C*m + A*(m + 1), 0] && !LeQ[m, -1]
\[\int \left (d \csc \left (f x +e \right )\right )^{n} \left (a +b \sin \left (f x +e \right )\right )^{2}d x\]
Input:
int((d*csc(f*x+e))^n*(a+b*sin(f*x+e))^2,x)
Output:
int((d*csc(f*x+e))^n*(a+b*sin(f*x+e))^2,x)
\[ \int (d \csc (e+f x))^n (a+b \sin (e+f x))^2 \, dx=\int { {\left (b \sin \left (f x + e\right ) + a\right )}^{2} \left (d \csc \left (f x + e\right )\right )^{n} \,d x } \] Input:
integrate((d*csc(f*x+e))^n*(a+b*sin(f*x+e))^2,x, algorithm="fricas")
Output:
integral(-(b^2*cos(f*x + e)^2 - 2*a*b*sin(f*x + e) - a^2 - b^2)*(d*csc(f*x + e))^n, x)
\[ \int (d \csc (e+f x))^n (a+b \sin (e+f x))^2 \, dx=\int \left (d \csc {\left (e + f x \right )}\right )^{n} \left (a + b \sin {\left (e + f x \right )}\right )^{2}\, dx \] Input:
integrate((d*csc(f*x+e))**n*(a+b*sin(f*x+e))**2,x)
Output:
Integral((d*csc(e + f*x))**n*(a + b*sin(e + f*x))**2, x)
\[ \int (d \csc (e+f x))^n (a+b \sin (e+f x))^2 \, dx=\int { {\left (b \sin \left (f x + e\right ) + a\right )}^{2} \left (d \csc \left (f x + e\right )\right )^{n} \,d x } \] Input:
integrate((d*csc(f*x+e))^n*(a+b*sin(f*x+e))^2,x, algorithm="maxima")
Output:
integrate((b*sin(f*x + e) + a)^2*(d*csc(f*x + e))^n, x)
\[ \int (d \csc (e+f x))^n (a+b \sin (e+f x))^2 \, dx=\int { {\left (b \sin \left (f x + e\right ) + a\right )}^{2} \left (d \csc \left (f x + e\right )\right )^{n} \,d x } \] Input:
integrate((d*csc(f*x+e))^n*(a+b*sin(f*x+e))^2,x, algorithm="giac")
Output:
integrate((b*sin(f*x + e) + a)^2*(d*csc(f*x + e))^n, x)
Timed out. \[ \int (d \csc (e+f x))^n (a+b \sin (e+f x))^2 \, dx=\int {\left (\frac {d}{\sin \left (e+f\,x\right )}\right )}^n\,{\left (a+b\,\sin \left (e+f\,x\right )\right )}^2 \,d x \] Input:
int((d/sin(e + f*x))^n*(a + b*sin(e + f*x))^2,x)
Output:
int((d/sin(e + f*x))^n*(a + b*sin(e + f*x))^2, x)
\[ \int (d \csc (e+f x))^n (a+b \sin (e+f x))^2 \, dx=d^{n} \left (\left (\int \csc \left (f x +e \right )^{n}d x \right ) a^{2}+\left (\int \csc \left (f x +e \right )^{n} \sin \left (f x +e \right )^{2}d x \right ) b^{2}+2 \left (\int \csc \left (f x +e \right )^{n} \sin \left (f x +e \right )d x \right ) a b \right ) \] Input:
int((d*csc(f*x+e))^n*(a+b*sin(f*x+e))^2,x)
Output:
d**n*(int(csc(e + f*x)**n,x)*a**2 + int(csc(e + f*x)**n*sin(e + f*x)**2,x) *b**2 + 2*int(csc(e + f*x)**n*sin(e + f*x),x)*a*b)