\(\int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx\) [150]

Optimal result

Integrand size = 34, antiderivative size = 209 \[ \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx=-\frac {2 \left (1+e^{2 d+2 e x}\right ) F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)}}{\left (1-e^{2 d+2 e x}\right ) (e+2 b c \log (F))}-\frac {8 b c \sqrt {1+e^{2 d+2 e x}} F^{c (a+b x)} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{4} \left (-1+\frac {2 b c \log (F)}{e}\right ),\frac {1}{4} \left (3+\frac {2 b c \log (F)}{e}\right ),-e^{2 d+2 e x}\right ) \log (F) \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)}}{\left (1-e^{2 d+2 e x}\right ) \left (e^2-4 b^2 c^2 \log ^2(F)\right )} \] Output:

-2*(1+exp(2*e*x+2*d))*F^(c*(b*x+a))*(f*sinh(e*x+d))^(1/2)*(g*tanh(e*x+d))^ 
(1/2)/(1-exp(2*e*x+2*d))/(e+2*b*c*ln(F))-8*b*c*(1+exp(2*e*x+2*d))^(1/2)*F^ 
(c*(b*x+a))*hypergeom([1/2, -1/4+1/2*b*c*ln(F)/e],[3/4+1/2*b*c*ln(F)/e],-e 
xp(2*e*x+2*d))*ln(F)*(f*sinh(e*x+d))^(1/2)*(g*tanh(e*x+d))^(1/2)/(1-exp(2* 
e*x+2*d))/(e^2-4*b^2*c^2*ln(F)^2)
 

Mathematica [A] (warning: unable to verify)

Time = 2.12 (sec) , antiderivative size = 202, normalized size of antiderivative = 0.97 \[ \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx=\frac {2 F^{c (a+b x)} g \sqrt {f \sinh (d+e x)} \left (\operatorname {Hypergeometric2F1}\left (1,\frac {e+2 b c \log (F)}{4 e},\frac {3}{4}+\frac {b c \log (F)}{2 e},-\cosh (2 (d+e x))-\sinh (2 (d+e x))\right ) (3 e+2 b c \log (F))+\operatorname {Hypergeometric2F1}\left (1,\frac {5}{4}+\frac {b c \log (F)}{2 e},\frac {7}{4}+\frac {b c \log (F)}{2 e},-\cosh (2 (d+e x))-\sinh (2 (d+e x))\right ) (e-2 b c \log (F)) (\cosh (2 (d+e x))+\sinh (2 (d+e x)))\right )}{(e-2 b c \log (F)) (3 e+2 b c \log (F)) \sqrt {g \tanh (d+e x)}} \] Input:

Integrate[F^(c*(a + b*x))*Sqrt[f*Sinh[d + e*x]]*Sqrt[g*Tanh[d + e*x]],x]
 

Output:

(2*F^(c*(a + b*x))*g*Sqrt[f*Sinh[d + e*x]]*(Hypergeometric2F1[1, (e + 2*b* 
c*Log[F])/(4*e), 3/4 + (b*c*Log[F])/(2*e), -Cosh[2*(d + e*x)] - Sinh[2*(d 
+ e*x)]]*(3*e + 2*b*c*Log[F]) + Hypergeometric2F1[1, 5/4 + (b*c*Log[F])/(2 
*e), 7/4 + (b*c*Log[F])/(2*e), -Cosh[2*(d + e*x)] - Sinh[2*(d + e*x)]]*(e 
- 2*b*c*Log[F])*(Cosh[2*(d + e*x)] + Sinh[2*(d + e*x)])))/((e - 2*b*c*Log[ 
F])*(3*e + 2*b*c*Log[F])*Sqrt[g*Tanh[d + e*x]])
 

Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx\)

\(\Big \downarrow \) 7271

\(\displaystyle \frac {\sqrt {f \sinh (d+e x)} \int F^{c (a+b x)} \sqrt {\sinh (d+e x)} \sqrt {g \tanh (d+e x)}dx}{\sqrt {\sinh (d+e x)}}\)

\(\Big \downarrow \) 7271

\(\displaystyle \frac {\sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \int F^{c (a+b x)} \sqrt {\sinh (d+e x)} \sqrt {\tanh (d+e x)}dx}{\sqrt {\sinh (d+e x)} \sqrt {\tanh (d+e x)}}\)

\(\Big \downarrow \) 7292

\(\displaystyle \frac {\sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \int F^{a c+b x c} \sqrt {\sinh (d+e x)} \sqrt {\tanh (d+e x)}dx}{\sqrt {\sinh (d+e x)} \sqrt {\tanh (d+e x)}}\)

\(\Big \downarrow \) 7299

\(\displaystyle \frac {\sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \int F^{a c+b x c} \sqrt {\sinh (d+e x)} \sqrt {\tanh (d+e x)}dx}{\sqrt {\sinh (d+e x)} \sqrt {\tanh (d+e x)}}\)

Input:

Int[F^(c*(a + b*x))*Sqrt[f*Sinh[d + e*x]]*Sqrt[g*Tanh[d + e*x]],x]
 

Output:

$Aborted
 

Maple [F]

\[\int F^{c \left (b x +a \right )} \sqrt {f \sinh \left (e x +d \right )}\, \sqrt {g \tanh \left (e x +d \right )}d x\]

Input:

int(F^(c*(b*x+a))*(f*sinh(e*x+d))^(1/2)*(g*tanh(e*x+d))^(1/2),x)
 

Output:

int(F^(c*(b*x+a))*(f*sinh(e*x+d))^(1/2)*(g*tanh(e*x+d))^(1/2),x)
 

Fricas [F]

\[ \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx=\int { \sqrt {f \sinh \left (e x + d\right )} \sqrt {g \tanh \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:

integrate(F^(c*(b*x+a))*(f*sinh(e*x+d))^(1/2)*(g*tanh(e*x+d))^(1/2),x, alg 
orithm="fricas")
                                                                                    
                                                                                    
 

Output:

integral(sqrt(f*sinh(e*x + d))*sqrt(g*tanh(e*x + d))*F^(b*c*x + a*c), x)
 

Sympy [F(-1)]

Timed out. \[ \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx=\text {Timed out} \] Input:

integrate(F**(c*(b*x+a))*(f*sinh(e*x+d))**(1/2)*(g*tanh(e*x+d))**(1/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx=\int { \sqrt {f \sinh \left (e x + d\right )} \sqrt {g \tanh \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:

integrate(F^(c*(b*x+a))*(f*sinh(e*x+d))^(1/2)*(g*tanh(e*x+d))^(1/2),x, alg 
orithm="maxima")
 

Output:

integrate(sqrt(f*sinh(e*x + d))*sqrt(g*tanh(e*x + d))*F^((b*x + a)*c), x)
 

Giac [F]

\[ \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx=\int { \sqrt {f \sinh \left (e x + d\right )} \sqrt {g \tanh \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:

integrate(F^(c*(b*x+a))*(f*sinh(e*x+d))^(1/2)*(g*tanh(e*x+d))^(1/2),x, alg 
orithm="giac")
 

Output:

integrate(sqrt(f*sinh(e*x + d))*sqrt(g*tanh(e*x + d))*F^((b*x + a)*c), x)
 

Mupad [F(-1)]

Timed out. \[ \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx=\int F^{c\,\left (a+b\,x\right )}\,\sqrt {f\,\mathrm {sinh}\left (d+e\,x\right )}\,\sqrt {g\,\mathrm {tanh}\left (d+e\,x\right )} \,d x \] Input:

int(F^(c*(a + b*x))*(f*sinh(d + e*x))^(1/2)*(g*tanh(d + e*x))^(1/2),x)
 

Output:

int(F^(c*(a + b*x))*(f*sinh(d + e*x))^(1/2)*(g*tanh(d + e*x))^(1/2), x)
 

Reduce [F]

\[ \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \tanh (d+e x)} \, dx=\sqrt {g}\, f^{a c +\frac {1}{2}} \left (\int f^{b c x} \sqrt {\tanh \left (e x +d \right )}\, \sqrt {\sinh \left (e x +d \right )}d x \right ) \] Input:

int(F^(c*(b*x+a))*(f*sinh(e*x+d))^(1/2)*(g*tanh(e*x+d))^(1/2),x)
 

Output:

sqrt(g)*f**((2*a*c + 1)/2)*int(f**(b*c*x)*sqrt(tanh(d + e*x))*sqrt(sinh(d 
+ e*x)),x)