Integrand size = 34, antiderivative size = 107 \[ \int F^{c (a+b x)} \sqrt {g \coth (d+e x)} \sqrt {f \sinh (d+e x)} \, dx=-\frac {2 F^{c (a+b x)} \sqrt {g \coth (d+e x)} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1}{4} \left (-1+\frac {2 b c \log (F)}{e}\right ),\frac {1}{4} \left (3+\frac {2 b c \log (F)}{e}\right ),-e^{2 d+2 e x}\right ) \sqrt {f \sinh (d+e x)}}{\sqrt {1+e^{2 d+2 e x}} (e-2 b c \log (F))} \] Output:
-2*F^(c*(b*x+a))*(g*coth(e*x+d))^(1/2)*hypergeom([-1/2, -1/4+1/2*b*c*ln(F) /e],[3/4+1/2*b*c*ln(F)/e],-exp(2*e*x+2*d))*(f*sinh(e*x+d))^(1/2)/(1+exp(2* e*x+2*d))^(1/2)/(e-2*b*c*ln(F))
Time = 1.53 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.09 \[ \int F^{c (a+b x)} \sqrt {g \coth (d+e x)} \sqrt {f \sinh (d+e x)} \, dx=-\frac {4 F^{c (a+b x)} \cosh (d+e x) \sqrt {g \coth (d+e x)} \operatorname {Hypergeometric2F1}\left (1,\frac {5}{4}+\frac {b c \log (F)}{2 e},\frac {3}{4}+\frac {b c \log (F)}{2 e},-\cosh (2 (d+e x))-\sinh (2 (d+e x))\right ) \sqrt {f \sinh (d+e x)} (\cosh (d+e x)+\sinh (d+e x))}{e-2 b c \log (F)} \] Input:
Integrate[F^(c*(a + b*x))*Sqrt[g*Coth[d + e*x]]*Sqrt[f*Sinh[d + e*x]],x]
Output:
(-4*F^(c*(a + b*x))*Cosh[d + e*x]*Sqrt[g*Coth[d + e*x]]*Hypergeometric2F1[ 1, 5/4 + (b*c*Log[F])/(2*e), 3/4 + (b*c*Log[F])/(2*e), -Cosh[2*(d + e*x)] - Sinh[2*(d + e*x)]]*Sqrt[f*Sinh[d + e*x]]*(Cosh[d + e*x] + Sinh[d + e*x]) )/(e - 2*b*c*Log[F])
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int F^{c (a+b x)} \sqrt {f \sinh (d+e x)} \sqrt {g \coth (d+e x)} \, dx\) |
\(\Big \downarrow \) 7271 |
\(\displaystyle \frac {\sqrt {g \coth (d+e x)} \int F^{c (a+b x)} \sqrt {\coth (d+e x)} \sqrt {f \sinh (d+e x)}dx}{\sqrt {\coth (d+e x)}}\) |
\(\Big \downarrow \) 7271 |
\(\displaystyle \frac {\sqrt {f \sinh (d+e x)} \sqrt {g \coth (d+e x)} \int F^{c (a+b x)} \sqrt {\coth (d+e x)} \sqrt {\sinh (d+e x)}dx}{\sqrt {\sinh (d+e x)} \sqrt {\coth (d+e x)}}\) |
\(\Big \downarrow \) 7292 |
\(\displaystyle \frac {\sqrt {f \sinh (d+e x)} \sqrt {g \coth (d+e x)} \int F^{a c+b x c} \sqrt {\coth (d+e x)} \sqrt {\sinh (d+e x)}dx}{\sqrt {\sinh (d+e x)} \sqrt {\coth (d+e x)}}\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \frac {\sqrt {f \sinh (d+e x)} \sqrt {g \coth (d+e x)} \int F^{a c+b x c} \sqrt {\coth (d+e x)} \sqrt {\sinh (d+e x)}dx}{\sqrt {\sinh (d+e x)} \sqrt {\coth (d+e x)}}\) |
Input:
Int[F^(c*(a + b*x))*Sqrt[g*Coth[d + e*x]]*Sqrt[f*Sinh[d + e*x]],x]
Output:
$Aborted
\[\int F^{c \left (b x +a \right )} \sqrt {g \coth \left (e x +d \right )}\, \sqrt {f \sinh \left (e x +d \right )}d x\]
Input:
int(F^(c*(b*x+a))*(g*coth(e*x+d))^(1/2)*(f*sinh(e*x+d))^(1/2),x)
Output:
int(F^(c*(b*x+a))*(g*coth(e*x+d))^(1/2)*(f*sinh(e*x+d))^(1/2),x)
\[ \int F^{c (a+b x)} \sqrt {g \coth (d+e x)} \sqrt {f \sinh (d+e x)} \, dx=\int { \sqrt {g \coth \left (e x + d\right )} \sqrt {f \sinh \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:
integrate(F^(c*(b*x+a))*(g*coth(e*x+d))^(1/2)*(f*sinh(e*x+d))^(1/2),x, alg orithm="fricas")
Output:
integral(sqrt(g*coth(e*x + d))*sqrt(f*sinh(e*x + d))*F^(b*c*x + a*c), x)
Timed out. \[ \int F^{c (a+b x)} \sqrt {g \coth (d+e x)} \sqrt {f \sinh (d+e x)} \, dx=\text {Timed out} \] Input:
integrate(F**(c*(b*x+a))*(g*coth(e*x+d))**(1/2)*(f*sinh(e*x+d))**(1/2),x)
Output:
Timed out
\[ \int F^{c (a+b x)} \sqrt {g \coth (d+e x)} \sqrt {f \sinh (d+e x)} \, dx=\int { \sqrt {g \coth \left (e x + d\right )} \sqrt {f \sinh \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:
integrate(F^(c*(b*x+a))*(g*coth(e*x+d))^(1/2)*(f*sinh(e*x+d))^(1/2),x, alg orithm="maxima")
Output:
integrate(sqrt(g*coth(e*x + d))*sqrt(f*sinh(e*x + d))*F^((b*x + a)*c), x)
\[ \int F^{c (a+b x)} \sqrt {g \coth (d+e x)} \sqrt {f \sinh (d+e x)} \, dx=\int { \sqrt {g \coth \left (e x + d\right )} \sqrt {f \sinh \left (e x + d\right )} F^{{\left (b x + a\right )} c} \,d x } \] Input:
integrate(F^(c*(b*x+a))*(g*coth(e*x+d))^(1/2)*(f*sinh(e*x+d))^(1/2),x, alg orithm="giac")
Output:
integrate(sqrt(g*coth(e*x + d))*sqrt(f*sinh(e*x + d))*F^((b*x + a)*c), x)
Timed out. \[ \int F^{c (a+b x)} \sqrt {g \coth (d+e x)} \sqrt {f \sinh (d+e x)} \, dx=\int F^{c\,\left (a+b\,x\right )}\,\sqrt {g\,\mathrm {coth}\left (d+e\,x\right )}\,\sqrt {f\,\mathrm {sinh}\left (d+e\,x\right )} \,d x \] Input:
int(F^(c*(a + b*x))*(g*coth(d + e*x))^(1/2)*(f*sinh(d + e*x))^(1/2),x)
Output:
int(F^(c*(a + b*x))*(g*coth(d + e*x))^(1/2)*(f*sinh(d + e*x))^(1/2), x)
\[ \int F^{c (a+b x)} \sqrt {g \coth (d+e x)} \sqrt {f \sinh (d+e x)} \, dx=\sqrt {g}\, f^{a c +\frac {1}{2}} \left (\int f^{b c x} \sqrt {\sinh \left (e x +d \right )}\, \sqrt {\coth \left (e x +d \right )}d x \right ) \] Input:
int(F^(c*(b*x+a))*(g*coth(e*x+d))^(1/2)*(f*sinh(e*x+d))^(1/2),x)
Output:
sqrt(g)*f**((2*a*c + 1)/2)*int(f**(b*c*x)*sqrt(sinh(d + e*x))*sqrt(coth(d + e*x)),x)