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y′(x)2−(4y(x)+1)y′(x)+y(x)(4y(x)+1)=0 ✓ Mathematica : cpu = 0.0445709 (sec), leaf count = 57
{{y(x)→−14ex−4c1(2e2c1−ex)},{y(x)→14e2c1+x(e2c1+x−2)}}
✓ Maple : cpu = 0.54 (sec), leaf count = 193
{y(x)=−14,y(x)=−(ex)22_C1(−_C1(ex)2(−_C1(ex)2−2)1−_C1(ex)2+_C1(ex)2+2),y(x)=(ex)22_C1(_C1(ex)2(−_C1(ex)2−2)1−_C1(ex)2−_C1(ex)2−2),y(x)=−(ex)22_C1(−_C1(ex)2(−_C1(ex)2+2)1−_C1(ex)2+_C1(ex)2+2),y(x)=(ex)22_C1(_C1(ex)2(−_C1(ex)2+2)1−_C1(ex)2−_C1(ex)2−2)}
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