Internal problem ID [15285]
Internal file name [OUTPUT/15286_Wednesday_May_08_2024_03_54_47_PM_65729883/index.tex]
Book: A book of problems in ordinary differential equations. M.L. KRASNOV, A.L. KISELYOV,
G.I. MARKARENKO. MIR, MOSCOW. 1983
Section: Chapter 2 (Higher order ODE’s). Section 15.3 Nonhomogeneous linear equations with
constant coefficients. Trial and error method. Exercises page 132
Problem number: 516.
ODE order: 4.
ODE degree: 1.
The type(s) of ODE detected by this program : "higher_order_linear_constant_coefficients_ODE"
Maple gives the following as the ode type
[[_high_order, _missing_x]]
\[ \boxed {3 y^{\prime \prime \prime \prime }+y^{\prime \prime \prime }=2} \] This is higher order nonhomogeneous ODE. Let the solution be \[ y = y_h + y_p \] Where \(y_h\) is the solution to the homogeneous ODE And \(y_p\) is a particular solution to the nonhomogeneous ODE. \(y_h\) is the solution to \[ 3 y^{\prime \prime \prime \prime }+y^{\prime \prime \prime } = 0 \] The characteristic equation is \[ 3 \lambda ^{4}+\lambda ^{3} = 0 \] The roots of the above equation are \begin {align*} \lambda _1 &= -{\frac {1}{3}}\\ \lambda _2 &= 0\\ \lambda _3 &= 0\\ \lambda _4 &= 0 \end {align*}
Therefore the homogeneous solution is \[ y_h(x)=x^{2} c_{3} +x c_{2} +c_{1} +{\mathrm e}^{-\frac {x}{3}} c_{4} \] The fundamental set of solutions for the homogeneous solution are the following \begin{align*} y_1 &= 1 \\ y_2 &= x \\ y_3 &= x^{2} \\ y_4 &= {\mathrm e}^{-\frac {x}{3}} \\ \end{align*} Now the particular solution to the given ODE is found \[ 3 y^{\prime \prime \prime \prime }+y^{\prime \prime \prime } = 2 \] The particular solution is found using the method of undetermined coefficients. Looking at the RHS of the ode, which is \[ 1 \] Shows that the corresponding undetermined set of the basis functions (UC_set) for the trial solution is \[ [\{1\}] \] While the set of the basis functions for the homogeneous solution found earlier is \[ \left \{1, x, x^{2}, {\mathrm e}^{-\frac {x}{3}}\right \} \] Since \(1\) is duplicated in the UC_set, then this basis is multiplied by extra \(x\). The UC_set becomes \[ [\{x\}] \] Since \(x\) is duplicated in the UC_set, then this basis is multiplied by extra \(x\). The UC_set becomes \[ [\{x^{2}\}] \] Since \(x^{2}\) is duplicated in the UC_set, then this basis is multiplied by extra \(x\). The UC_set becomes \[ [\{x^{3}\}] \] Since there was duplication between the basis functions in the UC_set and the basis functions of the homogeneous solution, the trial solution is a linear combination of all the basis function in the above updated UC_set. \[ y_p = A_{1} x^{3} \] The unknowns \(\{A_{1}\}\) are found by substituting the above trial solution \(y_p\) into the ODE and comparing coefficients. Substituting the trial solution into the ODE and simplifying gives \[ 6 A_{1} = 2 \] Solving for the unknowns by comparing coefficients results in \[ \left [A_{1} = {\frac {1}{3}}\right ] \] Substituting the above back in the above trial solution \(y_p\), gives the particular solution \[ y_p = \frac {x^{3}}{3} \] Therefore the general solution is \begin{align*} y &= y_h + y_p \\ &= \left (x^{2} c_{3} +x c_{2} +c_{1} +{\mathrm e}^{-\frac {x}{3}} c_{4}\right ) + \left (\frac {x^{3}}{3}\right ) \\ \end{align*}
The solution(s) found are the following \begin{align*} \tag{1} y &= x^{2} c_{3} +x c_{2} +c_{1} +{\mathrm e}^{-\frac {x}{3}} c_{4} +\frac {x^{3}}{3} \\ \end{align*}
Verification of solutions
\[ y = x^{2} c_{3} +x c_{2} +c_{1} +{\mathrm e}^{-\frac {x}{3}} c_{4} +\frac {x^{3}}{3} \] Verified OK.
Maple trace
`Methods for high order ODEs: --- Trying classification methods --- trying a quadrature trying high order exact linear fully integrable -> Calling odsolve with the ODE`, diff(_b(_a), _a) = -(1/3)*_b(_a)+2/3, _b(_a)` *** Sublevel 2 *** Methods for first order ODEs: --- Trying classification methods --- trying a quadrature trying 1st order linear <- 1st order linear successful <- high order exact linear fully integrable successful`
✓ Solution by Maple
Time used: 0.0 (sec). Leaf size: 27
dsolve(3*diff(y(x),x$4)+diff(y(x),x$3)=2,y(x), singsol=all)
\[ y \left (x \right ) = \frac {x^{3}}{3}+\frac {c_{2} x^{2}}{2}-27 \,{\mathrm e}^{-\frac {x}{3}} c_{1} +c_{3} x +c_{4} \]
✓ Solution by Mathematica
Time used: 0.074 (sec). Leaf size: 36
DSolve[3*y''''[x]+y'''[x]==2,y[x],x,IncludeSingularSolutions -> True]
\[ y(x)\to \frac {x^3}{3}+c_4 x^2+c_3 x-27 c_1 e^{-x/3}+c_2 \]