1.25 problem 26

1.25.1 Solving as quadrature ode
1.25.2 Maple step by step solution

Internal problem ID [7069]
Internal file name [OUTPUT/6055_Sunday_June_05_2022_04_15_45_PM_52012227/index.tex]

Book: Own collection of miscellaneous problems
Section: section 1.0
Problem number: 26.
ODE order: 1.
ODE degree: 1.

The type(s) of ODE detected by this program : "quadrature"

Maple gives the following as the ode type

[_quadrature]

\[ \boxed {x y^{\prime }=0} \]

1.25.1 Solving as quadrature ode

Integrating both sides gives \begin {align*} y &= \int { 0\,\mathop {\mathrm {d}x}}\\ &= c_{1} \end {align*}

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= c_{1} \\ \end{align*}

Figure 35: Slope field plot

Verification of solutions

\[ y = c_{1} \] Verified OK.

1.25.2 Maple step by step solution

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & y^{\prime }=0 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Integrate both sides with respect to}\hspace {3pt} x \\ {} & {} & \int y^{\prime }d x =\int 0d x +c_{1} \\ \bullet & {} & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & y=c_{1} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y=c_{1} \end {array} \]

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
<- 1st order linear successful`
 

Solution by Maple

Time used: 0.0 (sec). Leaf size: 5

dsolve(x*diff(y(x),x)=0,y(x), singsol=all)
 

\[ y \left (x \right ) = c_{1} \]

Solution by Mathematica

Time used: 0.002 (sec). Leaf size: 7

DSolve[x*y'[x]==0,y[x],x,IncludeSingularSolutions -> True]
 

\[ y(x)\to c_1 \]