Internal problem ID [14072]
Internal file name [OUTPUT/13753_Saturday_March_02_2024_02_49_17_PM_28097140/index.tex]
Book: INTRODUCTORY DIFFERENTIAL EQUATIONS. Martha L. Abell, James P. Braselton.
Fourth edition 2014. ElScAe. 2014
Section: Chapter 1. Introduction to Differential Equations. Exercises 1.1, page 10
Problem number: 36.
ODE order: 1.
ODE degree: 1.
The type(s) of ODE detected by this program : "quadrature"
Maple gives the following as the ode type
[_quadrature]
\[ \boxed {y^{\prime }=\frac {x}{\sqrt {x^{2}-16}}} \]
Integrating both sides gives \begin {align*} y &= \int { \frac {x}{\sqrt {x^{2}-16}}\,\mathop {\mathrm {d}x}}\\ &= \sqrt {x^{2}-16}+c_{1} \end {align*}
Summary
The solution(s) found are the following \begin{align*} \tag{1} y &= \sqrt {x^{2}-16}+c_{1} \\ \end{align*}
Verification of solutions
\[ y = \sqrt {x^{2}-16}+c_{1} \] Verified OK.
\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & y^{\prime }=\frac {x}{\sqrt {x^{2}-16}} \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Integrate both sides with respect to}\hspace {3pt} x \\ {} & {} & \int y^{\prime }d x =\int \frac {x}{\sqrt {x^{2}-16}}d x +c_{1} \\ \bullet & {} & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & y=\frac {\left (x -4\right ) \left (x +4\right )}{\sqrt {x^{2}-16}}+c_{1} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y=\frac {c_{1} \sqrt {x^{2}-16}+x^{2}-16}{\sqrt {x^{2}-16}} \end {array} \]
Maple trace
`Methods for first order ODEs: --- Trying classification methods --- trying a quadrature <- quadrature successful`
✓ Solution by Maple
Time used: 0.0 (sec). Leaf size: 20
dsolve(diff(y(x),x)=x/sqrt(x^2-16),y(x), singsol=all)
\[ y \left (x \right ) = \frac {\left (x -4\right ) \left (x +4\right )}{\sqrt {x^{2}-16}}+c_{1} \]
✓ Solution by Mathematica
Time used: 0.004 (sec). Leaf size: 17
DSolve[y'[x]==x/Sqrt[x^2-16],y[x],x,IncludeSingularSolutions -> True]
\[ y(x)\to \sqrt {x^2-16}+c_1 \]