3.15 problem 13 (c)

3.15.1 Existence and uniqueness analysis
3.15.2 Solving as quadrature ode

Internal problem ID [14138]
Internal file name [OUTPUT/13819_Saturday_March_02_2024_02_50_57_PM_21734797/index.tex]

Book: INTRODUCTORY DIFFERENTIAL EQUATIONS. Martha L. Abell, James P. Braselton. Fourth edition 2014. ElScAe. 2014
Section: Chapter 2. First Order Equations. Exercises 2.1, page 32
Problem number: 13 (c).
ODE order: 1.
ODE degree: 1.

The type(s) of ODE detected by this program : "quadrature"

Maple gives the following as the ode type

[_quadrature]

\[ \boxed {y^{\prime }-\sqrt {y^{2}-1}=0} \] With initial conditions \begin {align*} \left [y \left (0\right ) = {\frac {1}{2}}\right ] \end {align*}

3.15.1 Existence and uniqueness analysis

This is non linear first order ODE. In canonical form it is written as \begin {align*} y^{\prime } &= f(t,y)\\ &= \sqrt {y^{2}-1} \end {align*}

The \(y\) domain of \(f(t,y)\) when \(t=0\) is \[ \{1\le y \le \infty , -\infty \le y \le -1\} \] But the point \(y_0 = {\frac {1}{2}}\) is not inside this domain. Hence existence and uniqueness theorem does not apply. There could be infinite number of solutions, or one solution or no solution at all.

3.15.2 Solving as quadrature ode

Integrating both sides gives \begin {align*} \int \frac {1}{\sqrt {y^{2}-1}}d y &= \int {dt}\\ \ln \left (y +\sqrt {y^{2}-1}\right )&= t +c_{1} \end {align*}

Initial conditions are used to solve for \(c_{1}\). Substituting \(t=0\) and \(y={\frac {1}{2}}\) in the above solution gives an equation to solve for the constant of integration. \begin {align*} \frac {i \pi }{3} = c_{1} \end {align*}

The solutions are \begin {align*} c_{1} = \frac {i \pi }{3} \end {align*}

Trying the constant \begin {align*} c_{1} = \frac {i \pi }{3} \end {align*}

Substituting \(c_{1}\) found above in the general solution gives \begin {align*} \ln \left (y +\sqrt {y^{2}-1}\right ) = t +\frac {i \pi }{3} \end {align*}

The constant \(c_{1} = \frac {i \pi }{3}\) gives valid solution.

Summary

The solution(s) found are the following \begin{align*} \tag{1} \ln \left (y+\sqrt {y^{2}-1}\right ) &= t +\frac {i \pi }{3} \\ \end{align*}

Verification of solutions

\[ \ln \left (y+\sqrt {y^{2}-1}\right ) = t +\frac {i \pi }{3} \] Verified OK.

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
trying Bernoulli 
trying separable 
<- separable successful`
 

Solution by Maple

Time used: 0.344 (sec). Leaf size: 26

dsolve([diff(y(t),t)=sqrt(y(t)^2-1),y(0) = 1/2],y(t), singsol=all)
 

\[ y \left (t \right ) = \frac {i \sqrt {3}\, {\mathrm e}^{t}}{4}-\frac {i \sqrt {3}\, {\mathrm e}^{-t}}{4}+\frac {{\mathrm e}^{t}}{4}+\frac {{\mathrm e}^{-t}}{4} \]

Solution by Mathematica

Time used: 0.076 (sec). Leaf size: 59

DSolve[{y'[t]==Sqrt[y[t]^2-1],{y[0]==1/2}},y[t],t,IncludeSingularSolutions -> True]
 

\[ y(t)\to \frac {e^{-t} \sqrt {4 e^{2 t}+i \left (\sqrt {3}+i\right ) e^{4 t}-1-i \sqrt {3}}}{2 \sqrt {2}} \]