Link to actual problem [1338] \[ \boxed {9 x^{2} \left (x^{2}+1\right ) y^{\prime \prime }+3 x \left (13 x^{2}+3\right ) y^{\prime }-\left (-25 x^{2}+1\right ) y=0} \] With the expansion point for the power series method at \(x = 0\).
type detected by program
{"second order series method. Regular singular point. Difference not integer"}
type detected by Maple
[[_2nd_order, _with_linear_symmetries]]
Maple symgen result This shows Maple’s found \(\xi ,\eta \) and the corresponding canonical coordinates \(R,S\)\begin{align*} \\ \\ \end{align*}
\begin{align*} \left [\underline {\hspace {1.25 ex}}\xi &= 0, \underline {\hspace {1.25 ex}}\eta &= \frac {1}{x^{\frac {1}{3}} \left (x^{2}+1\right )^{\frac {2}{3}}}\right ] \\ \left [R &= x, S \left (R \right ) &= x^{\frac {1}{3}} \left (x^{2}+1\right )^{\frac {2}{3}} y\right ] \\ \end{align*}
\begin{align*} \left [\underline {\hspace {1.25 ex}}\xi &= 0, \underline {\hspace {1.25 ex}}\eta &= x^{\frac {1}{3}} \operatorname {hypergeom}\left (\left [1, 1\right ], \left [\frac {4}{3}\right ], -x^{2}\right )\right ] \\ \left [R &= x, S \left (R \right ) &= \frac {y}{x^{\frac {1}{3}} \operatorname {hypergeom}\left (\left [1, 1\right ], \left [\frac {4}{3}\right ], -x^{2}\right )}\right ] \\ \end{align*}