3.69.26 $\int (5+e)dx$

Optimal. Leaf size=18 $$x(5+e-\frac{\log \left(5e^{e^2}\right)}{x})$$

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Rubi [A]  time = 0.00, antiderivative size = 5, normalized size of antiderivative = 0.28, number of steps used = 1, number of rules used = 1, integrand size = 3, $\frac{\text{number of rules}}{\text{integrand size}}$ = 0.333, Rules used = {8} $$\begin{array}{c}(5+e)x\end{array}$$

Antiderivative was successfully verified.

[In]

Int[5 + E,x]

[Out]

(5 + E)*x

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rubi steps

$$\begin{array}{c}\begin{array}{rl}\text{integral}& =(5+e)x\end{array}\end{array}$$

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Mathematica [A]  time = 0.00, size = 7, normalized size = 0.39 $$\begin{array}{c}5x+ex\end{array}$$

Antiderivative was successfully verified.

[In]

Integrate[5 + E,x]

[Out]

5*x + E*x

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fricas [A]  time = 0.50, size = 8, normalized size = 0.44 $$\begin{array}{c}xe+5x\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(1)+5,x, algorithm="fricas")

[Out]

x*e + 5*x

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giac [A]  time = 0.14, size = 6, normalized size = 0.33 $$\begin{array}{c}x(e+5)\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(1)+5,x, algorithm="giac")

[Out]

x*(e + 5)

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maple [A]  time = 0.01, size = 7, normalized size = 0.39

method	result	size
default	$(\mathrm{e}+5)x$	$7$
norman	$(\mathrm{e}+5)x$	$7$
risch	$x\mathrm{e}+5x$	$9$

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(1)+5,x,method=_RETURNVERBOSE)

[Out]

(exp(1)+5)*x

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maxima [A]  time = 0.36, size = 6, normalized size = 0.33 $$\begin{array}{c}x(e+5)\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(1)+5,x, algorithm="maxima")

[Out]

x*(e + 5)

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mupad [B]  time = 0.00, size = 6, normalized size = 0.33 $$\begin{array}{c}x(\mathrm{e}+5)\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(1) + 5,x)

[Out]

x*(exp(1) + 5)

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sympy [A]  time = 0.05, size = 5, normalized size = 0.28 $$\begin{array}{c}x(e+5)\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(1)+5,x)

[Out]

x*(E + 5)

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