3.95.49 \(\int \frac {e^{3-e^{3-e^{x^4-2 x^3 \log (4+x)+x^2 \log ^2(4+x)}-x}-x} (-4-x+e^{3-e^{x^4-2 x^3 \log (4+x)+x^2 \log ^2(4+x)}-x} (4+x+e^{x^4-2 x^3 \log (4+x)+x^2 \log ^2(4+x)} (14 x^3+4 x^4+(-22 x^2-6 x^3) \log (4+x)+(8 x+2 x^2) \log ^2(4+x))))}{4+x} \, dx\)

Optimal. Leaf size=36 \[ 2+e^{3-e^{3-e^{x^2 (-x+\log (4+x))^2}-x}-x} \]

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Rubi [A]  time = 5.76, antiderivative size = 43, normalized size of antiderivative = 1.19, number of steps used = 1, number of rules used = 1, integrand size = 161, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.006, Rules used = {6706} \begin {gather*} \exp \left (-\exp \left ((x+4)^{-2 x^3} \left (-e^{x^4+x^2 \log ^2(x+4)}\right )-x+3\right )-x+3\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(E^(3 - E^(3 - E^(x^4 - 2*x^3*Log[4 + x] + x^2*Log[4 + x]^2) - x) - x)*(-4 - x + E^(3 - E^(x^4 - 2*x^3*Log
[4 + x] + x^2*Log[4 + x]^2) - x)*(4 + x + E^(x^4 - 2*x^3*Log[4 + x] + x^2*Log[4 + x]^2)*(14*x^3 + 4*x^4 + (-22
*x^2 - 6*x^3)*Log[4 + x] + (8*x + 2*x^2)*Log[4 + x]^2))))/(4 + x),x]

[Out]

E^(3 - E^(3 - x - E^(x^4 + x^2*Log[4 + x]^2)/(4 + x)^(2*x^3)) - x)

Rule 6706

Int[(F_)^(v_)*(u_), x_Symbol] :> With[{q = DerivativeDivides[v, u, x]}, Simp[(q*F^v)/Log[F], x] /;  !FalseQ[q]
] /; FreeQ[F, x]

Rubi steps

\begin {gather*} \begin {aligned} \text {integral} &=\exp \left (3-\exp \left (3-x-e^{x^4+x^2 \log ^2(4+x)} (4+x)^{-2 x^3}\right )-x\right )\\ \end {aligned} \end {gather*}

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Mathematica [A]  time = 0.44, size = 43, normalized size = 1.19 \begin {gather*} e^{3-e^{3-x-e^{x^4+x^2 \log ^2(4+x)} (4+x)^{-2 x^3}}-x} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(E^(3 - E^(3 - E^(x^4 - 2*x^3*Log[4 + x] + x^2*Log[4 + x]^2) - x) - x)*(-4 - x + E^(3 - E^(x^4 - 2*x
^3*Log[4 + x] + x^2*Log[4 + x]^2) - x)*(4 + x + E^(x^4 - 2*x^3*Log[4 + x] + x^2*Log[4 + x]^2)*(14*x^3 + 4*x^4
+ (-22*x^2 - 6*x^3)*Log[4 + x] + (8*x + 2*x^2)*Log[4 + x]^2))))/(4 + x),x]

[Out]

E^(3 - E^(3 - x - E^(x^4 + x^2*Log[4 + x]^2)/(4 + x)^(2*x^3)) - x)

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fricas [A]  time = 0.69, size = 40, normalized size = 1.11 \begin {gather*} e^{\left (-x - e^{\left (-x - e^{\left (x^{4} - 2 \, x^{3} \log \left (x + 4\right ) + x^{2} \log \left (x + 4\right )^{2}\right )} + 3\right )} + 3\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((((2*x^2+8*x)*log(4+x)^2+(-6*x^3-22*x^2)*log(4+x)+4*x^4+14*x^3)*exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x
^4)+4+x)*exp(-exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x^4)+3-x)-x-4)*exp(-exp(-exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x^4
)+3-x)+3-x)/(4+x),x, algorithm="fricas")

[Out]

e^(-x - e^(-x - e^(x^4 - 2*x^3*log(x + 4) + x^2*log(x + 4)^2) + 3) + 3)

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giac [A]  time = 34.83, size = 40, normalized size = 1.11 \begin {gather*} e^{\left (-x - e^{\left (-x - e^{\left (x^{4} - 2 \, x^{3} \log \left (x + 4\right ) + x^{2} \log \left (x + 4\right )^{2}\right )} + 3\right )} + 3\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((((2*x^2+8*x)*log(4+x)^2+(-6*x^3-22*x^2)*log(4+x)+4*x^4+14*x^3)*exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x
^4)+4+x)*exp(-exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x^4)+3-x)-x-4)*exp(-exp(-exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x^4
)+3-x)+3-x)/(4+x),x, algorithm="giac")

[Out]

e^(-x - e^(-x - e^(x^4 - 2*x^3*log(x + 4) + x^2*log(x + 4)^2) + 3) + 3)

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maple [A]  time = 0.57, size = 41, normalized size = 1.14

method	result	size
risch	\({\mathrm e}^{-{\mathrm e}^{-\left (4+x \right )^{-2 x^{3}} {\mathrm e}^{x^{2} \left (\ln \left (4+x \right )^{2}+x^{2}\right )}+3-x}+3-x}\)	\(41\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((((2*x^2+8*x)*ln(4+x)^2+(-6*x^3-22*x^2)*ln(4+x)+4*x^4+14*x^3)*exp(x^2*ln(4+x)^2-2*x^3*ln(4+x)+x^4)+4+x)*e
xp(-exp(x^2*ln(4+x)^2-2*x^3*ln(4+x)+x^4)+3-x)-x-4)*exp(-exp(-exp(x^2*ln(4+x)^2-2*x^3*ln(4+x)+x^4)+3-x)+3-x)/(4
+x),x,method=_RETURNVERBOSE)

[Out]

exp(-exp(-(4+x)^(-2*x^3)*exp(x^2*(ln(4+x)^2+x^2))+3-x)+3-x)

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maxima [A]  time = 0.72, size = 40, normalized size = 1.11 \begin {gather*} e^{\left (-x - e^{\left (-x - e^{\left (x^{4} - 2 \, x^{3} \log \left (x + 4\right ) + x^{2} \log \left (x + 4\right )^{2}\right )} + 3\right )} + 3\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((((2*x^2+8*x)*log(4+x)^2+(-6*x^3-22*x^2)*log(4+x)+4*x^4+14*x^3)*exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x
^4)+4+x)*exp(-exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x^4)+3-x)-x-4)*exp(-exp(-exp(x^2*log(4+x)^2-2*x^3*log(4+x)+x^4
)+3-x)+3-x)/(4+x),x, algorithm="maxima")

[Out]

e^(-x - e^(-x - e^(x^4 - 2*x^3*log(x + 4) + x^2*log(x + 4)^2) + 3) + 3)

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mupad [B]  time = 7.61, size = 45, normalized size = 1.25 \begin {gather*} {\mathrm {e}}^{-{\mathrm {e}}^{-x}\,{\mathrm {e}}^3\,{\mathrm {e}}^{-\frac {{\mathrm {e}}^{x^4}\,{\mathrm {e}}^{x^2\,{\ln \left (x+4\right )}^2}}{{\left (x+4\right )}^{2\,x^3}}}}\,{\mathrm {e}}^{-x}\,{\mathrm {e}}^3 \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(exp(3 - exp(3 - exp(x^4 - 2*x^3*log(x + 4) + x^2*log(x + 4)^2) - x) - x)*(x - exp(3 - exp(x^4 - 2*x^3*lo
g(x + 4) + x^2*log(x + 4)^2) - x)*(x + exp(x^4 - 2*x^3*log(x + 4) + x^2*log(x + 4)^2)*(log(x + 4)^2*(8*x + 2*x
^2) - log(x + 4)*(22*x^2 + 6*x^3) + 14*x^3 + 4*x^4) + 4) + 4))/(x + 4),x)

[Out]

exp(-exp(-x)*exp(3)*exp(-(exp(x^4)*exp(x^2*log(x + 4)^2))/(x + 4)^(2*x^3)))*exp(-x)*exp(3)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((((2*x**2+8*x)*ln(4+x)**2+(-6*x**3-22*x**2)*ln(4+x)+4*x**4+14*x**3)*exp(x**2*ln(4+x)**2-2*x**3*ln(4
+x)+x**4)+4+x)*exp(-exp(x**2*ln(4+x)**2-2*x**3*ln(4+x)+x**4)+3-x)-x-4)*exp(-exp(-exp(x**2*ln(4+x)**2-2*x**3*ln
(4+x)+x**4)+3-x)+3-x)/(4+x),x)

[Out]

Timed out

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