2.14.5.65 problem 465 out of 2993

Link to actual problem [2904] \[ \boxed {y^{\prime \prime }+2 y^{\prime } x^{2}+2 y x=0} \] With the expansion point for the power series method at \(x = 0\).

type detected by program

{"second order series method. Ordinary point", "second order series method. Taylor series method"}

type detected by Maple

[[_2nd_order, _with_linear_symmetries]]

Maple symgen result This shows Maple’s found \(\xi ,\eta \) and the corresponding canonical coordinates \(R,S\)\begin{align*} \\ \\ \end{align*}

\begin{align*} \left [\underline {\hspace {1.25 ex}}\xi &= 0, \underline {\hspace {1.25 ex}}\eta &= {\mathrm e}^{-\frac {x^{3}}{3}} \sqrt {x}\, \operatorname {BesselI}\left (\frac {1}{6}, \frac {x^{3}}{3}\right )\right ] \\ \left [R &= x, S \left (R \right ) &= \frac {{\mathrm e}^{\frac {x^{3}}{3}} y}{\sqrt {x}\, \operatorname {BesselI}\left (\frac {1}{6}, \frac {x^{3}}{3}\right )}\right ] \\ \end{align*}

\begin{align*} \left [\underline {\hspace {1.25 ex}}\xi &= 0, \underline {\hspace {1.25 ex}}\eta &= {\mathrm e}^{-\frac {x^{3}}{3}} \sqrt {x}\, \operatorname {BesselK}\left (\frac {1}{6}, \frac {x^{3}}{3}\right )\right ] \\ \left [R &= x, S \left (R \right ) &= \frac {{\mathrm e}^{\frac {x^{3}}{3}} y}{\sqrt {x}\, \operatorname {BesselK}\left (\frac {1}{6}, \frac {x^{3}}{3}\right )}\right ] \\ \end{align*}