Link to actual problem [2909] \[ \boxed {y^{\prime \prime }+2 y^{\prime }+4 y x=0} \] With the expansion point for the power series method at \(x = 0\).
type detected by program
{"second_order_airy", "second order series method. Ordinary point", "second order series method. Taylor series method"}
type detected by Maple
[[_2nd_order, _with_linear_symmetries]]
Maple symgen result This shows Maple’s found \(\xi ,\eta \) and the corresponding canonical coordinates \(R,S\)\begin{align*} \\ \\ \end{align*}
\begin{align*} \left [\underline {\hspace {1.25 ex}}\xi &= 0, \underline {\hspace {1.25 ex}}\eta &= {\mathrm e}^{-x} \operatorname {AiryAi}\left (-2^{\frac {2}{3}} x +\frac {2^{\frac {2}{3}}}{4}\right )\right ] \\ \left [R &= x, S \left (R \right ) &= \frac {{\mathrm e}^{x} y}{\operatorname {AiryAi}\left (-2^{\frac {2}{3}} x +\frac {2^{\frac {2}{3}}}{4}\right )}\right ] \\ \end{align*}
\begin{align*} \left [\underline {\hspace {1.25 ex}}\xi &= 0, \underline {\hspace {1.25 ex}}\eta &= {\mathrm e}^{-x} \operatorname {AiryBi}\left (-2^{\frac {2}{3}} x +\frac {2^{\frac {2}{3}}}{4}\right )\right ] \\ \left [R &= x, S \left (R \right ) &= \frac {{\mathrm e}^{x} y}{\operatorname {AiryBi}\left (-2^{\frac {2}{3}} x +\frac {2^{\frac {2}{3}}}{4}\right )}\right ] \\ \end{align*}